Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN: 9781305081550
Author: Braja M. Das
Publisher: Cengage Learning
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Chapter 2, Problem 2.24P
To determine
Calculate the shear strength parameters
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A consolidated-drained triaxial test was conducted on a normally consolidated clay.The results were as follows:σ3 = 276 kN/m2(Δσd)f = 276 kN/m2a. Find the angle of friction. ϕ'.b. What is the angle that the failure plane makes with the major principal stress?c. C. Determine the normal stress σ' and the shear stress τf on the failure plane.
A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as
follows:
03 = 276 kN/m?
(Aoa)f = 276 kN/m²
Determine
a. Angle of friction, o'
b. Angle 0 that the failure plane makes with the major principal plane
c. Find the normal stress o' and the shear stress tf on the failure plane
d. Determine the effective normal stress on the plane of maximum shear stress
of
Effective stress failure envelope
↑
B
of
20
276 kN/m2
A
oj = 552 kN/m²
Normal stress
Shear stress
© Cengage Learning 2014
A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as
follows:
O3 =
150 kN/m?
(Aoa)f= 130 kN/m?
Determine
a. Angle of friction, o'
b. Angle 0 that the failure plane makes with the major principal plane
c. Find the normal stress o' and the shear stress tf on the failure plane
d. Determine the effective normal stress on the plane of maximum shear stress
Chapter 2 Solutions
Principles of Foundation Engineering (MindTap Course List)
Ch. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10P
Ch. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - For a normally consolidated soil, the following is...Ch. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27P
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- : A specimen of normally consolidated clay is consolidated to 722 kN/m² and then failed by increasing o, while o, held constant. Find qr and Prif Ø= 26°. A cylindrical sample of soil soil having a cohesion of 100 kN/m² and angle of internal friction of 22° is subjected to cell pressure (63) of 80 kN/m². Determine: 1) Maximum deviator stress at which the sample will failed. 2) Angle made by the failure plan with the axis of sample. 3) Normal and shear stress on failure plan.arrow_forward2. The shear strength of a normally consolidated clay can be given by the equation t = ơ' tan 28°. A consolidated-undrained test was conducted on the clay. Following are the results of the test. Chamber confining pressure = 105 KN/m? Deviator stress at failure = 97 KN/m² a. Compute the pore water pressure developed in the clay specimen at failure. b. Compute the consolidated-undrained friction angle 4. What would have been the deviator stress at failure if a drained test had been conducted with the same chamber confining pressure that is o3= 105 KN/m? C.arrow_forwardthe results of a consolidated undrained test, in which o3 = 392 kN/m?, %3D on a normally consolidated clay are given next: Axial Strain, % Ao, kN/m2 Ud, kN/m? 0.5 156 99 0.75 196 120 1 226 132 1.3 235 147 2 250 161 3 245 170 4 240 173 4.5 235 175 Draw the kf line in a p' vs q' diagram. Also draw the stress path for the test in the diagram.arrow_forward
- SITUATION 5: A sand sample is subjected to direct shear testing at it's (in - situ) water content. Two tests are performed. For one of the tests, the sample shears at a stress of 400 kPa when the normal stress is 600 kPa. From these data, 15. Determine the value of the apparent cohesion. c. 230 kPa d. 221 kPa а. 100 kPa b. 179 КРа 16. Determine the corresponding angle of internal friction. a. 22.65 degrees b. 26.57 degrees c. 32.54 degrees d. 18.43 degreesarrow_forwardA direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the minor principal stress in kPa. Show the free body diagram. a.53.5 b.136.5 c.36.9 d.64.5arrow_forwardA direct shear test, when conducted on a remolded sample of sand, gave the following observations at the time of failure: Normal load = 288 N; shear load = 173 N. The cross-sectional area of the sample = 36 cm2. Determine the minor principal stress in kPa. Pls include fbd.arrow_forward
- Q-2: Following are the results of four drained direct shear tests on an over consolidated clay: Diameter of specimen = 50 mm Height of specimen = 25 mm Test no. 1 2 3 4 Normal force (N) 150 250 350 550 Shear force at failure (N) 157.5 199.9 257.6 363.4 Determine shear strength parameters by plotting grapharrow_forwardA series of previous CD tests conducted on a NC clay has established that the ultimate effective friction angle of the clay is 300. Now a CU test is conducted on this soil with an effective cell pressure of 100 kPa. The specimen fails at a deviatoric stress of 100 kPa. Estimate the pore pressure at failure. Given: σ3f′=Kaσ1f′whereKa=1−sinϕ1+sinϕ Please do fast .... ASAP Fastarrow_forwardThe results of a consolidated undrained test, in which o3 = 392 kN/m?, on a normally consolidated clay are given as: Axial strain (%) Ao(kN/m²) ug(kN/m²) 0.5 0.75 156 196 226 235 250 245 240 235 99 120 132 147 161 170 173 175 1.3 2 3 4 4.5 Draw the K; line in a P' versus q' diagram. Also draw the s tress path for this test in the diagram.arrow_forward
- 1.A dry sand is known to have an angle of internal friction of 29. A triaxial test is planned, where the confining pressure will be 41 kPa. What is the maximum axial stress, in kPa, (major principal stress) that can be applied? Calculate the value to 1 decimal place. Do not provide units in your answer. 2.A clay soil is subjected to a triaxial test under unconsolidated-undrained conditions. At failure, the major and minor principal stresses are 8401 psf and 4875 psf, respectively. What is the shear strength of this soil if the confining pressure is doubled? Provide your answer in psf with no decimals.arrow_forwardQ: A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as following: confining stress, G3 = 150 kN/m² and deviator stress, (Aod)t = 150 kN/m². i) Determine angle of friction, q; ii) Determine angle 0 that the failure plane makes with the major principal plane; iii) Find the normal stress and the shear stress ty on the failure plane; and iv) Determine the effective normal stress on the plane of maximum shear stress. Express your results in two decimal places.arrow_forwardhe following results were obtained from a direct shear test conducted on pure sand: Sample height and diameter = 30 mm and 75 mm respectively. Normal stress = 100 kN/m2 Shear force at failure = 185 N a) Determine the angle of friction for the soil. Round off to one decimal i.e. 99.5! b) What would be the shear force (in N) at failure if the normal stress is 175 kN/m2? Round off to the nearest figure i.e. 300.55 to 301! c) What would be the principal stress at failure? Consider a and barrow_forward
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