Principles of Foundation Engineering (MindTap Course List)
Principles of Foundation Engineering (MindTap Course List)
8th Edition
ISBN: 9781305081550
Author: Braja M. Das
Publisher: Cengage Learning
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Chapter 2, Problem 2.19P
To determine

Calculate the settlement at t=30andt=100 days after the beginning of construction.

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2. A layer of compressible clay 6m thick overlies an impervious bedrock and carries an overburden of pervious sand. A large structure founded in the sand causes the stress on every horizontal section of the clay to increase to the same value. In a standard laboratory oedometer consolidation test performed on a 19 mm thick clay specimen, the void ratio changed from 0.765 to 0.750 under a corresponding increase in stress. Consolidation was 70% complete after 30 min. In the field, a) Estimate the settlement of the structure. b) Determine the time taken for one half of the consolidation settlement to take place (Remember the lab test is for a doubly drained specimen.). c) Determine how long it takes for 50% of the settlement to take place at a depth of 0, 2, 3, 5 and 6 m of the clay stratum. d) If the clay were underlain by pervious sand, determine how long it takes for 50% of the settlement to take place at a depth of 0, 2, 3, 5 and 6 m of the clay stratum.
A consolidated-undrained triaxial compression test was performed on a normalconsolidated clay sample. During the experiment, the confining pressure was 140 kPa, thedeviator stress was 125 kPa, and the pore water pressure was 75 kPa at the time of failure.According to the information given:i- Find the consolidated-undrained internal friction angle of the clay. ii- Find the drained friction angle of the clay
Refer to the soil profile shown in figure below. A laboratory consolidation test on the clay gave the results: o'c = 100 kPa Cc = 0.4 Cs = 0.2Cc If the average effective stress on the clay layer increases by 60 kN/m², what would be the total consolidation settlement in cm. Dry sand; e = 0.55 G,= 2.66: Sand G₂ = 2.66 e = 0.48. Clay w 34.78% G₂ = 2.74 Rock 1.5 m. 5 m Water table;
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