EBK PRINCIPLES OF FOUNDATION ENGINEERIN
8th Edition
ISBN: 8220100547058
Author: Das
Publisher: CENGAGE L
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Chapter 2, Problem 2.17P
To determine
Find the time taken for 50% consolidation for a clay layer.
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Q1: A clay specimen was tested in a laboratory consolidation device, which was 12.7 mm thick and the top & bottom boundaries were drained. A 50% consolidation time on the specimen was obtained as 28.4 minutes, Determine the Following: a- The time for 50% consolidation in the field with a 2.5 m thickness where ‘only the top layer is drained. b- The time for 90% consolidation in the field with a 2.5 m thickness where only the top layer is drained. c- For the same field condition above, find the settlement after 1year, if the final consolidation settlement = 0.0345 m.
A laboratory sample of clay 2 cm thick took 15 min to attain 60 percent consolidation under a double
drainage condition.
a. What time will be required to attain the same degree of consolidation for a clay layer 3 m thick
under the foundation of a building for a similar loading and drainage condition?
b. How long (in days) will it take in the field for 30% primary consolidation to occur?
A clay soil specimen, 1.5 in. thick (drained on top only) was tested in the laboratory. For a given
load increment, the time for 60% consolidation was 8 min and 10 sec. How long will it take (in
days) for 40% consolidation for a similar clay layer in the field that is 10-ft thick and drained on
both sides?
Page 1 of 2
Chapter 2 Solutions
EBK PRINCIPLES OF FOUNDATION ENGINEERIN
Ch. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10P
Ch. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - For a normally consolidated soil, the following is...Ch. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27P
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- 3- The time for 65% consolidation of a 1.12-inch clay specimen (drained at top and bottom) in the laboratory is 12 minutes. How long will it take (in days) for a 15-ft-thick clay layer in the field to undergo 35% consolidation under the same pressure increment? In the field, there is a rock layer at the bottom of the clay.arrow_forward9.4 A clay specimen was tested in a laboratory consolidation device, which was 12.7 mm (1/2 in.) thick and the top and the bottom boundaries were drained. A 50% consolidation time on the specimen was obtained as 28.4 minutes. Determine the following: (a) Time for 50% consolidation in the field with this soil with a 2.5 m thickness where only the top layer is drained (b) Time for 90% consolidation in the field with this soil with a 2.5 m thickness where only the top layer is drained (c) For the same field condition above, at the end of 1 year after the placement of load, how much primary consolidation settlement occurs relative to its final amount of the settlement? (d) The same question as in (c), but at the end of 5 yearsarrow_forwardThe time for 50% consolidation of a 1-in. thick clay layer (drained at top and bottom) in the laboratory is 2 min, 20 sec. How long (in days) will it take for an 8-ft thick layer of the same clay in the field (under the same pressure increment) to reach 30% consolidation? In the field, there is a rock layer at the bottom of the clay.arrow_forward
- Laboratory tests on a 25-mm-thick clay specimen drained at the top and bot-tom show that 50% consolidation takes place in 8.5 min.a. How long will it take for a similar clay layer in the field, 3.2 m thick anddrained at the top only, to undergo 50% consolidation?b. Find the time required for the clay layer in the field described in part (a)to reach 65% consolidation.arrow_forwardA 3-m thick layer of saturated clay (two-way drainage) under a surcharge loadingunderwent 90% primary consolidation in 100 days. The laboratory test’s specimenwill have two-way drainage.a. Find the coefficient of consolidation of clay for the pressure range. b. For a 25 mm. thick undisturbed clay specimen, how long will it take to under-go 80% consolidation in the laboratory for a similar pressure range?arrow_forwardThe time required for a 50% consolidation of a 25 mm thick layer (drained at both sides) in the laboratory is 2 min and 20 sec. How long in days will it take for a 3 m thick layer of the same clay in the field under the same pressure increment to reach 50% consolidation? In the field there is a rock layer at the bottom of the clay.arrow_forward
- A 20 mm-thick sample in a singly drained laboratory consolidation test reaches 75% consolidation in 5 houres . How long will it take to reach 75% consolidation for a 5 m-thick clay sandwiched between two sand layers in the field ?arrow_forward3-lf the time needed for 50% consolidation of a 2-in clay specimen (single drainage) in the laboratory=2 min, how many days will it take for a 12-ft thick clay layer (with sand on top, and bottom) in the field to undergo 90% consolidation under the same pressure increment?arrow_forwardFigure 1 office illustrates the soil profile at a site for a proposed building. It is expected that the vertical stress at the middle of the clay layer will increase by 32 kPa. Calculate the final consolidation settlement. Ground water level is at the top of the clay layer. An oedometer test on a sample of the clay revealed that 90% consolidation on a 20-mm thick sample occurred in 40 minutes. The sample was drained on the upper and lower boundaries. Estimate the consolidation settlement in one year. Gs(clay) = 2.70 and Gs(sand) = 2.60. 5 m w = 23% Sand S = 90% w = 40% 10 m C= 0.3 OCR = 1 Clay Impervious rock Figure 1 0.9 U. avg 0.00 0.000 0.8 0.0 0.1 0.0 0.008 0.031 0.071 0.05 0.252 0.10 0.357 0.197 0.500 0.7 02 0.3 0.20 0.30 0.40 0.504 0.6 04 0.126 0.613 0.698 0.764 0.816 0.856 0.887 0.848 0.900 0.912 0.931 0.980 0.5 0.197 0.5 0.6 0.287 0.50 0.7 0.403 0.60 0.4 0.567 0.70 0.848 0.95 1.163 0,9 0.80 0.3 1.0 0.90 02 1.00 1.50 2.00 0.1 0.994 02 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 Time factor, T…arrow_forward
- Question 2 The result presented in Table Q2a were obtained from a consolidated drained (CD) triaxial test on a normally consolidated clay sample of 75mm height x 38mm diameter tested at a confining pressure of 50 kPa. Table Q2a. CD triaxial test result Axial strain (%) 1 2 5 10 15 Applied force (kN) 0.01 0.03 0.05 0.08 0.10 Page 3 of 6 (a) Draw the Mohr circle for each stress state in the sample and the total stress path (TSP) throughout the test and determine the slope of the TSP to the horizontal.arrow_forward2.17 A clay specimen 25 mm thick (drained at top only) was tested in the laboratory. For a given load increment, the time for 60% consolidation was 6 min. How long will it take for 50% consolidation for a similar clay layer in the field that is 2.45 m thick and drained on both sides?arrow_forwardIn a consolidated drained tri-axial text on a normally consolidated clay soil, a deviator of 152 kPa was required to fail the sample when the confining pressure was 70 kPa. A. What was the angle of shearing resistance? B. Suppose that after consolidation under the 70 kPa confining pressure, the sample is placed in an unconfined compression apparatus and tested. Determine the resulting shear strength.arrow_forward
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