EBK PRINCIPLES OF FOUNDATION ENGINEERIN
8th Edition
ISBN: 8220100547058
Author: Das
Publisher: CENGAGE L
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 2, Problem 2.26P
To determine
Find the pore water pressure at failure
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
8. For a normally consolidated clay specimen, the results of a drained triaxial test are as
follows:
Chamber-confining pressure = 125 kN/m?
Deviator stress at failure = 175 kN/m?
%3D
Determine the soil friction angle, o'
A sample of normally consolidated clay was
subjected to a consolidated undrained triaxial
compression test that was carried out until the
specimen failed at a deviator stress of 50
kN/m2. The pore water
pressure at failure was recorded to be 20
kN/m2 and confining pressure of 50 kN/m2
was used in the test. Determine the
consolidated undrained friction angle.
A consolidated-undrained triaxial test was conducted on a dense sand with a confining pressure of 138 kN/m2. Results showed that ϕ′=24 deg and ϕ=31 deg. Determine the deviator stress and the pore water pressure at failure.
Chapter 2 Solutions
EBK PRINCIPLES OF FOUNDATION ENGINEERIN
Ch. 2 - Prob. 2.1PCh. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10P
Ch. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - For a normally consolidated soil, the following is...Ch. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.Similar questions
- Q: A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as following: confining stress, G3 = 150 kN/m² and deviator stress, (Aod)t = 150 kN/m². i) Determine angle of friction, q; ii) Determine angle 0 that the failure plane makes with the major principal plane; iii) Find the normal stress and the shear stress ty on the failure plane; and iv) Determine the effective normal stress on the plane of maximum shear stress. Express your results in two decimal places.arrow_forward2. The shear strength of a normally consolidated clay can be given by the equation t = ơ' tan 28°. A consolidated-undrained test was conducted on the clay. Following are the results of the test. Chamber confining pressure = 105 KN/m? Deviator stress at failure = 97 KN/m² a. Compute the pore water pressure developed in the clay specimen at failure. b. Compute the consolidated-undrained friction angle 4. What would have been the deviator stress at failure if a drained test had been conducted with the same chamber confining pressure that is o3= 105 KN/m? C.arrow_forwardsample of normally consolidated clay was subjected to a consolidated undrained triaxial compression st that was carried out until the specimen failed at a deviator stress of 50 kN/m?. The pore water pressure at failure was recorded to be 20 kN/m? and confining pressure of 50 kN/m² was used in the test. Determine the consolidated undrained friction angle o and drained friction angle ¢cn: CD сиarrow_forward
- A consolidated-drained triaxial test was conducted on a normally consolidated clay. The results kN o', = 276 kN (A0,), = 276 m² are as follows: Determine: (a) The angle of friction o; (b) The angle 0 that the failure plane makes with the major principal plane, and (c) The normal stress o’ and shear stress t, on the failure plane.arrow_forwardA consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as follows: O3 = 150 kN/m? (Aoa)f= 130 kN/m? Determine a. Angle of friction, o' b. Angle 0 that the failure plane makes with the major principal plane c. Find the normal stress o' and the shear stress tf on the failure plane d. Determine the effective normal stress on the plane of maximum shear stressarrow_forwardA consolidated-undrained test on a normally consolidate clay yield the following results: Confining Pressure = 160 KPa; Deviator Stress = 182 KPa; Pore Pressure = 73 KPa. Calculate the consolidated undrained friction angle.arrow_forward
- A consolidated-undrained test on a normally consolidate clay yield the following results: Confining Pressure 167 KPa; Deviator Stress = 184 KPa; Pore Pressure = 74 KPa. Calculate the normal stress at the failure plane at drained condition in KPa.arrow_forward5- The shear strength of a normally consolidated clay can be given by the equation tf o'tan 27°. Following are the results of a consolidated-undrained test on the clay. • Chamber-confining pressure = 3,130 lb/ft² Deviator stress at failure = 2,510 lb/ft² a) Determine the consolidated-undrained friction angle b) Pore-water pressure developed in the specimen at failurearrow_forwardA consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as following: confining stress, σ3 = 250 kN/m² and deviator stress, (Aod)f = 100 kN/m². i) Determine angle of friction, q; ii) Determine angle 0 that the failure plane makes with the major principal plane; iii) Find the normal stress o and the shear stress tf on the failure plane; and iv) Determine the effective normal stress on the plane of maximum shear stress. Express your results in two decimal places.arrow_forward
- A consolidated-drained triaxial test on a sand yields the results:All-around confining pressure = σ3 = 30 lb/in2Added axial stress at failure = Δσ = 96 lb/in2Determine the shear stress parameters (i.e., Φ' and c')arrow_forwardA consolidated drained tri-axial test was conducted on normally consolidated clay. The results were: the confining pressure is 300 kPa and the deviators stress is 300 kPa. Compute the angle that the failure plane makes with the major principal axis in degrees. show free body diagram. a.54.74 b.16.3 c.24.72 d.19.47arrow_forwardA clay specimen with drained shear strength parameters of c'=5 kPa and Φ=320 is consolidated under all around pressure of 140 kPa.The specimen was then loaded axially to failure under undrained condition and failed when the principal stress diffrences reached 60 kPa.Calculate the pore pressure(u) and the pore pressure coefficient D(=A*B=Δu/Δσv) of the clay.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Geotechnical Engineering (MindTap C...Civil EngineeringISBN:9781305970939Author:Braja M. Das, Khaled SobhanPublisher:Cengage Learning
Fundamentals of Geotechnical Engineering (MindTap...Civil EngineeringISBN:9781305635180Author:Braja M. Das, Nagaratnam SivakuganPublisher:Cengage Learning
Principles of Foundation Engineering (MindTap Cou...Civil EngineeringISBN:9781305081550Author:Braja M. DasPublisher:Cengage Learning
Principles of Geotechnical Engineering (MindTap C...
Civil Engineering
ISBN:9781305970939
Author:Braja M. Das, Khaled Sobhan
Publisher:Cengage Learning
Fundamentals of Geotechnical Engineering (MindTap...
Civil Engineering
ISBN:9781305635180
Author:Braja M. Das, Nagaratnam Sivakugan
Publisher:Cengage Learning
Principles of Foundation Engineering (MindTap Cou...
Civil Engineering
ISBN:9781305081550
Author:Braja M. Das
Publisher:Cengage Learning