(a) Interpretation: The appearance of the high resolution 13 C spectrum of methyl formate when the protons are not decoupled should be predicted. Concept introduction: 13 C isotope of carbon has low natural abundance . 12 C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since 13 C is less likely to find in nature there is a very low probability of finding two 13 C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in 13 C NMR spectra. But there are 13 C and 1 H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified 13 C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Question

Want to see the full answer?

Answer 1

Question

Chapter 19, Problem 19.22QAP

Interpretation Introduction

(a)

Interpretation:

The appearance of the high resolution ¹³C spectrum of methyl formate when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Interpretation Introduction

(b)

Interpretation:

The appearance of the high resolution ¹³C spectrum of acetaldehyde when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Interpretation Introduction

(c)

Interpretation:

The appearance of the high resolution ¹³C spectrum of acetone when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Give examples of homotopic, diastereometric and enantiotopic protons in a molecule

For "B nuclei (Ị= 3/2, y = 8.5843 × 10' rad T-' s') in a magnetic field of 9.4 T, sketch a Zeeman energy level diagram for the "B spin system; indicate all the NMR-allowed transitions and calculate the transition frequency (in MHz); calculate the probability of finding a "B nucleus at each of the four spin states at 27 °C (Note that the high temperature approximation can be applied) (i) (ii) (iii)

What is the EPR resonance frequency in a magnetic field for which the NMR frequency for 1H nuclei (protons) is 500 MHz? Express your answer in gigahertz.

Answer 2

Question

Chapter 19, Problem 19.22QAP

Interpretation Introduction

(a)

Interpretation:

The appearance of the high resolution ¹³C spectrum of methyl formate when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Interpretation Introduction

(b)

Interpretation:

The appearance of the high resolution ¹³C spectrum of acetaldehyde when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Interpretation Introduction

(c)

Interpretation:

The appearance of the high resolution ¹³C spectrum of acetone when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 19, Problem 19.22QAP

Interpretation Introduction

(a)

Interpretation:

The appearance of the high resolution ¹³C spectrum of methyl formate when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Interpretation Introduction

(b)

Interpretation:

The appearance of the high resolution ¹³C spectrum of acetaldehyde when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Interpretation Introduction

(c)

Interpretation:

The appearance of the high resolution ¹³C spectrum of acetone when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 19, Problem 19.22QAP

Interpretation Introduction

(a)

Interpretation:

The appearance of the high resolution ¹³C spectrum of methyl formate when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Interpretation Introduction

(b)

Interpretation:

The appearance of the high resolution ¹³C spectrum of acetaldehyde when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Interpretation Introduction

(c)

Interpretation:

The appearance of the high resolution ¹³C spectrum of acetone when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 19, Problem 19.22QAP

Interpretation Introduction

(a)

Interpretation:

The appearance of the high resolution ¹³C spectrum of methyl formate when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Interpretation Introduction

(b)

Interpretation:

The appearance of the high resolution ¹³C spectrum of acetaldehyde when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Interpretation Introduction

(c)

Interpretation:

The appearance of the high resolution ¹³C spectrum of acetone when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Answer 6

Chapter 19, Problem 19.22QAP

Interpretation Introduction

(a)

Interpretation:

The appearance of the high resolution ¹³C spectrum of methyl formate when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Answer 7

Chapter 19, Problem 19.22QAP

Interpretation Introduction

(a)

Interpretation:

The appearance of the high resolution ¹³C spectrum of methyl formate when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The appearance of the high resolution ¹³C spectrum of acetaldehyde when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The appearance of the high resolution ¹³C spectrum of acetaldehyde when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The appearance of the high resolution ¹³C spectrum of acetone when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The appearance of the high resolution ¹³C spectrum of acetone when the protons are not decoupled should be predicted.

Concept introduction:

¹³C isotope of carbon has low natural abundance. ¹²C is the most abundant isotope in nature. But it is NMR inactive because the spin quantum number is zero. Since ¹³C is less likely to find in nature there is a very low probability of finding two ¹³C nuclei which are close to each other. So there is no observable spin-spin coupling between adjacent carbons in ¹³C NMR spectra. But there are ¹³C and ¹H coupling which leads to large number of splitting patterns in the spectrum. To obtain simplified ¹³C spectrum scientists use a method called broadband decoupling. This technique avoids the C-H coupling signal, so that all carbon signals appear as singlets.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 15

Ch. 19 - Prob. 19.1QAP Ch. 19 - Prob. 19.2QAP Ch. 19 - Prob. 19.3QAP Ch. 19 - Prob. 19.4QAP Ch. 19 - Prob. 19.5QAP Ch. 19 - A nucleus has a spin quantum number of 7/2. How...Ch. 19 - Prob. 19.7QAP Ch. 19 - Prob. 19.8QAP Ch. 19 - Prob. 19.9QAP Ch. 19 - Why is 133C-133C spin-spin splitting not observed...

Solution Summary: The author explains that 13 C is the most abundant isotope in nature, but it is NMR inactive because the spin quantum number is zero.

Want to see the full answer?

Chapter 19 Solutions