(a) Interpretation: The appearance of the high-resolution 13 C spectrum of (proton decoupled) methyl formate is to be stated. Concept introduction: The whole signals that appear in the proton decoupled 13 C NMR spectrum are a singlet. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13 C − 13 C bond is that two 13 C atoms must be adjacent to each other. It is almost impossible for two 13 C nuclei to be adjacent to each other because the presence 13 C atoms in nature are less abundant and also the 13 C nuclei do not couple with the 12 C nuclei because of zero spin quantum number.

Question

In a 300 MHz NMR spectrometer, A) what is the Larmor frequency in MHz of a 15N nucleus? g H = N 26.752; g = 2.7126; B) Using the same NMR instrument, suppose that a 13C nucleus from a sample generates a signal which has a frequency of 11,250 Hz higher than that from the carbons in TMS. What is the chemical shift of that carbon atom from the sample? A) 30 MHz; B) 0.15 ppm OA) 25 MHz; B) 0.35 ppm A) 35 MHz; B) 0.30 ppm OA) 25 MHz; B) 0.55 ppm

Answer 1

Question

Chapter 19, Problem 19.21QAP

Interpretation Introduction

(a)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) methyl formate is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are a singlet. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Interpretation Introduction

(b)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) acetaldehyde is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are singlet in nature. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Interpretation Introduction

(c)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) acetone is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are singlet in nature. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

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In a 300 MHz NMR spectrometer, A) what is the Larmor frequency in MHz of a 15N nucleus? g H = N 26.752; g = 2.7126; B) Using the same NMR instrument, suppose that a 13C nucleus from a sample generates a signal which has a frequency of 11,250 Hz higher than that from the carbons in TMS. What is the chemical shift of that carbon atom from the sample? A) 30 MHz; B) 0.15 ppm OA) 25 MHz; B) 0.35 ppm A) 35 MHz; B) 0.30 ppm OA) 25 MHz; B) 0.55 ppm

(a) What would be the chemical shift of a peak that is observed at 655.2 Hz from the reference tetramethylsilane (TMS) recorded using a 90 MHz spectrometer ? (b) At what frequency would the chemical shift of chloroform (CHCl3, δ = 7.28 ppm) occur relative to TMS on a spectrum recorded on a 300 MHz spectrometer? (c) At what frequency and chemical shift would the signal for chloroform occur when using a 1 GHz NMR spectrometer?

(i) Identify TWO (2) functional groups presence in the molecule and state their frequencies. (ii) Predict the possible chemical structure of molecule based on the IR spectra with chemical formula C7H8.

Answer 2

Question

Chapter 19, Problem 19.21QAP

Interpretation Introduction

(a)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) methyl formate is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are a singlet. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Interpretation Introduction

(b)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) acetaldehyde is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are singlet in nature. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Interpretation Introduction

(c)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) acetone is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are singlet in nature. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

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Answer 3

Question

Chapter 19, Problem 19.21QAP

Interpretation Introduction

(a)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) methyl formate is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are a singlet. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Interpretation Introduction

(b)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) acetaldehyde is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are singlet in nature. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Interpretation Introduction

(c)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) acetone is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are singlet in nature. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

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Answer 4

Question

Chapter 19, Problem 19.21QAP

Interpretation Introduction

(a)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) methyl formate is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are a singlet. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Interpretation Introduction

(b)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) acetaldehyde is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are singlet in nature. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Interpretation Introduction

(c)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) acetone is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are singlet in nature. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

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Answer 5

Chapter 19, Problem 19.21QAP

Interpretation Introduction

(a)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) methyl formate is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are a singlet. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Interpretation Introduction

(b)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) acetaldehyde is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are singlet in nature. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Interpretation Introduction

(c)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) acetone is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are singlet in nature. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Answer 6

Chapter 19, Problem 19.21QAP

Interpretation Introduction

(a)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) methyl formate is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are a singlet. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Answer 7

Chapter 19, Problem 19.21QAP

Interpretation Introduction

(a)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) methyl formate is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are a singlet. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Answer 8

Interpretation Introduction

(b)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) acetaldehyde is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are singlet in nature. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Answer 9

Interpretation Introduction

(b)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) acetaldehyde is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are singlet in nature. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Answer 10

Interpretation Introduction

(c)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) acetone is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are singlet in nature. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Answer 11

Interpretation Introduction

(c)

Interpretation:

The appearance of the high-resolution 13C spectrum of (proton decoupled) acetone is to be stated.

Concept introduction:

The whole signals that appear in the proton decoupled 13C NMR spectrum are singlet in nature. Due to several reasons, the carbon atoms are do not coupled with the adjacent carbon atom. The only condition to form 13C−13C bond is that two 13C atoms must be adjacent to each other. It is almost impossible for two 13C nuclei to be adjacent to each other because the presence 13C atoms in nature are less abundant and also the 13C nuclei do not couple with the 12C nuclei because of zero spin quantum number.

Answer 12

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Ch. 19 - Prob. 19.1QAP Ch. 19 - Prob. 19.2QAP Ch. 19 - Prob. 19.3QAP Ch. 19 - Prob. 19.4QAP Ch. 19 - Prob. 19.5QAP Ch. 19 - A nucleus has a spin quantum number of 7/2. How...Ch. 19 - Prob. 19.7QAP Ch. 19 - Prob. 19.8QAP Ch. 19 - Prob. 19.9QAP Ch. 19 - Why is 133C-133C spin-spin splitting not observed...

Chapter 19 Solutions