Practice Problem CONCEPTUALIZE
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Chemistry
- Predict the sign of S for each of the following and explain. a. the evaporation of alcohol b. the freezing of water c. compressing an ideal gas at constant temperature d. dissolving NaCl in waterarrow_forwardFor which reaction will ΔS be positive? Group of answer choices N2O4(g) ⟶ 2 NO2(g) 2 H2(g) + O2(g) ⟶2 H2O(g) 3 NO(g) ⟶NO2(g) + N2O(g) 2 SO2(g) + O2(g) ⟶2 SO3(g)arrow_forwardCalculate ΔS°298 for the following changes.(a) SnCl4(l) ⟶ SnCl4(g)(b) CS2(g) ⟶ CS2(l)(c) Cu(s) ⟶ Cu(g)(d) H2 O(l) ⟶ H2 O(g)(e) 2H2(g) + O2(g) ⟶ 2H2 O(l)(f) 2HCl(g) + Pb(s) ⟶ PbCl2(s) + H2(g)(g) Zn(s) + CuSO4(s) ⟶ Cu(s) + ZnSO4(s)arrow_forward
- Calculate the ΔGo for the following equation. Sb4O6(s) + 6C(graphite) ⟶ 4Sb(s) + 6CO(g) Group of answer choices -1131.02 kJ/mole 445.27 kJ/mole -445.27 kJ/mole -1131.02 kJ/mole 445.27 kJ/mole -445.27 kJ/mole 1131.02 kJ/mole 1131.02 kJ/molearrow_forwardCalculate ΔS° for the following changes. (Please show all work) SnCl4(l) ⟶ SnCl4(g) CS2(g) ⟶ CS2(l) Cu(s) ⟶ Cu(g) H2O(l) ⟶ H2O(g) 2H2(g) + O2(g) ⟶ 2H2O(l) 2HCl(g) + Pb(s) ⟶ PbCl2(s) + H2(g) Zn(s) + CuSO4(s) ⟶ Cu(s) + ZnSO4(s)arrow_forward1. Consider the freezing of liquid water at -10°C and 1 atm. For this process, what are the signs for AH, AS, and AG? ΔΗ AS AG (A) (B) (C) (D) I + + 1 + 1 + 1arrow_forward
- For each process below, determine the sign of ΔG. (positive, negative, or not enough information)2H2O(s) → 2H2O(l) at relatively high temperaturesA process for which ΔS is negative.2H2(g) + O2(g) → 2H2O(g) ΔH= -An exothermic process during which the atoms get more ordered.A process with positive ΔH and positive ΔS.A process that is non-spontaneous at all temperatures.arrow_forward19 Thermodynamic Quantities for Selected Substances at 298.15 K (25°C) AHf AGf AS° AHf (kJ/mol) AGf (kJ/mol) AS° Substance (kJ/mol) (kJ/mol) (J/mol-K) Substance (J/mol-K) Aluminum Chlorine CI (g) C (аq) Cl2 (g) HCI (aq) HCI (g) Chromium Al (s) AIC13 (s) 28.32 121.7 105,7 - 131,2 165.2 - 705.6 - 630.0 109.3 - 167.2 56.5 Al203 (s) - 1669.8 1576.5 51.00 222,96 - 131.2 -95.27 - 167.2 56.5 186,69 Barium - - Ba(s) BaCO3(s) BaO(s) Beryllium Be(s) 63.2 -92.30 - 1216,3 - 553.5 - 1137.6 112.1 Cr (g) Cr (s) Cr203 (s) Cobalt Со (g) Copper Cu (s) CuCl2 (s) CuO (s) - 525.1 70.42 397.5 352.6 174.2 23.6 9.44 - 1139.7 - 1058.1 81.2 BeO(s) Be(ОН)2(8) 13.77 50.21 - 608.4 -579,1 - 817.9 - 905.8 439 393 179 Bromine 111.8 - 120.9 Br(g) Br-(aq) Br2(g) Br2(1) HBr(g) Calcium Ca(g) Ca(s) CaCO3 (s, calcite) CaCl2(s) CaF2(s) CaO(s) Ca(OH)2(s) CaSO4(s) 82.38 174.9 33.30 108.1 - 102.8 - 167,7 - 128,3 - 147.9 80.71 - 205.9 30,71 3.14 245.3 - 156,1 42,59 - Cu20 (s) Fluorine F (g) F- (aq) F2 (g) HF (g) Hydrogen 152.3…arrow_forwardSubstance X has a heat of vaporization of 55.4 kJ/mol at its normal boiling point (423°C). For the process X(l) → X(g) at 1 atm and 423°C, calculate the value of ΔG . Question 23 options: A) 79.6 J/K•mol B) –79.6 J/K•mol C) 0 D) 103 J/K•mol E) –103 J/K•molarrow_forward
- What is equal to zero at 298 K? A) ΔrH° (F, g) B) S° (F, g) C) S° (F2, g) ΔrH° (F2, g)arrow_forwardCalculate ΔS° (J/mol-K) for the reaction below, given the thermodynamic data in the table. 1 A(s) + 4 B(g) → 1 C(s) + 3 D(g) Substance S°(J/mol-K) A(s) 165.5 B(g) 260.0 C(s) 154.6 D(g) 188.3arrow_forwardFor the reaction below, which statement best describes what is happening with the sign of ΔG0? N a2C O3(a q) + C a Cl2(a q) → C a C O3(s) + 2 N a Cl(a q) (endothermic) Question 6 options: The reaction is non-spontaneous at low temperature and spontaneous at high temperature. The reaction is spontaneous at all temperatures. The reaction is spontaneous at low temperature and non-spontaneous at high temperature. The reaction is non-spontaneous at all temperatures.arrow_forward
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