The wavelength of the line in the Balmer series of the hydrogen spectrum for m = 5 .

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Answer 1

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Chapter 18, Problem 8E

To determine

The wavelength of the line in the Balmer series of the hydrogen spectrum for m=5.

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The longest wavelength line of the Balmer Series for hydrogen occurs at 656.3 nm corresponding to the transition from n2 = 3 to n1 = 2. Determine the value for the Rydberg constant for hydrogen using these values.

Given the value of Rydberg constant is 107m−1, the waves number of the lest line of the Balmer series in hydrogen spectrum will be: (1) 0.025×104m−1 (2) 0.5×107m−1 (3) 0.25×107m−1 (4) 2.5×107m−1

Find the longest wavelength present in the Balmer series of hydrogen, corresponding to the Ha line.

Answer 2

Question

Chapter 18, Problem 8E

To determine

The wavelength of the line in the Balmer series of the hydrogen spectrum for m=5.

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Answer 3

Question

Chapter 18, Problem 8E

To determine

The wavelength of the line in the Balmer series of the hydrogen spectrum for m=5.

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Answer 4

Question

Chapter 18, Problem 8E

To determine

The wavelength of the line in the Balmer series of the hydrogen spectrum for m=5.

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Answer 5

Chapter 18, Problem 8E

To determine

The wavelength of the line in the Balmer series of the hydrogen spectrum for m=5.

Answer 6

Chapter 18, Problem 8E

To determine

The wavelength of the line in the Balmer series of the hydrogen spectrum for m=5.

Answer 7

Chapter 18, Problem 8E

To determine

The wavelength of the line in the Balmer series of the hydrogen spectrum for m=5.

Answer 8

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Answer 9

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Answer 11

Ch. 18 - Prob. 1CQ Ch. 18 - Prob. 2CQ Ch. 18 - Prob. 3CQ Ch. 18 - Prob. 4CQ Ch. 18 - Prob. 5CQ Ch. 18 - Prob. 6CQ Ch. 18 - Prob. 7CQ Ch. 18 - Prob. 8CQ Ch. 18 - Prob. 9CQ Ch. 18 - Prob. 10CQ

The wavelength of the line in the Balmer series of the hydrogen spectrum for m = 5 .

Solution Summary: The author calculates the wavelength of the line in the Balmer series of hydrogen spectrum for m=5.

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The wavelength of the line in the Balmer series of the hydrogen spectrum for m=5.

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Chapter 18 Solutions