Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 18, Problem 41Q
To determine
The angular diameter in arcminutes of Cassiopeia A as seen from Earth.
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Next you will (1) convert your measurement of the semi-major axis from arcseconds to AU, (2) convert your measurement of the period from days to years, and (3) calculate the mass of the planet using Newton's form of Kepler's Third Law.
Use Stellarium to find the distance to the planet when Skynet took any of your images, in AU. Answer: 4.322 AU
Use this equation to determine a conversion factor from 1 arcsecond to AU at the planet's distance. You will need to convert ? = 1 arcsecond to degrees first. Answer: 2.096e-5 AU
(2 x 3.14 x 4.322 x (.000278/360) = 2.096e-5)
Next, use this number to convert your measurement of the moon's orbital semi-major axis from arcseconds to AU.
A) Calculate a in AU.
B) Convert your measurement of the moon's orbital period from days to years.
C) By Newton's form of Kepler's third law, calculate the mass of the planet.
D) Finally, convert the planet's mass to Earth masses: 1 solar mass = 333,000 Earth masses.
What diameter telescope is needed to see the separation between Uranus and its largest moon, Titania, from Earth at 550 nm, when Earth is 19.7 AU away? The moon is 436,300 km from the center of the planet. (Enter your
answer in m.)
m
Imagine a telescope was placed on the
planet Mercury and was used to measure
the positions of stars in the sky.
Assuming Mercury follows a circular orbit
with a semi-major axis = 0.387 AU and a
period = 88 days, calculate the maximum
%3D
stellar aberration that would be detected,
expressing your answer in arcseconds.
Choose the option below that best
matches your answer.
Select one:
Оа.
100
O b. 25
О с
60
O d. 15
O e.
33
Chapter 18 Solutions
Universe: Stars And Galaxies
Ch. 18 - Prob. 1QCh. 18 - Prob. 2QCh. 18 - Prob. 3QCh. 18 - Prob. 4QCh. 18 - Prob. 5QCh. 18 - Prob. 6QCh. 18 - Prob. 7QCh. 18 - Prob. 8QCh. 18 - Prob. 9QCh. 18 - Prob. 10Q
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- If you observed the Solar System from the nearest star (distance = 1.3 parsecs), what would the maximum angular separation be between Earth and the Sun? (Note: 1 pc is 2.1105 AU.) (Hint: Use the small-angle formula in Reasoning with Numbers 3-1.)arrow_forwardWhat is an asterism? Can you name an example?arrow_forwardFirst we will do a simulation of Eratosthenes measurement of the size of our planet over 2000 years ago, but we will do it on a hypothetical planet. At one location on that planet at noon, the light from its star comes in directly overhead. At another town 200 miles due South, the shadows cast by the towers in that town indicate that the sunlight is coming in at an angle of approximately 10 degrees from directly overhead. Using this information (and the fact that there are 360 degrees in a circle and that the diameter of a circle is equal to the circumstances divided by pi), please show your work to explain what the circumstances and diameter of this new planet isarrow_forward
- why is it pie - (pie/6)? why is it not in quadrant 3?arrow_forwardA spacecraft leaving Earth is deployed at burnout from its launch vehicle at 400 km altitude with flight path angle -10.0 degrees and speed 10.8 km/sec. ; Using Kepler's equation, determine how long it will take the spacecraft to cross lunar orbit (assume the Moon is on a circular orbit about Earth with 384,000 km radius, and ignore the lunar gravitational effects). Confirm your answer to part (a) using the appropriate Lambert TOF a. b. equation. If burnout speed is increased to 13 km/sec (still with flight path angle с. at -10.0 degrees and altitude 400 km), how much time can be saved for the trip to the Moon?arrow_forwardAn asteroid is observed to be on a superior orbit with a synodic period of 466.6 days. What are the sidereal orbital period and semi-major axis of this asteroid? Choose the option below that most closely matches your answers. Select one: O a. Sidereal period = 1683 days and %3D semi-major = 2.7 AU O b. Sidereal period = 1683 days and semi-major axis = 4.8 AU O c. Sidereal period = 865 days and semi- major axis = 1.8 AU O d. Sidereal period = 426 day and semi- %3D major axis = 2.7 AU O e. Sidereal period = 1727 days and е. semi-major axis = 0.8 AUarrow_forward
- m AGNITUDE SCALE nadto km or THE Q2: Use the fact that our closest neighboring star (Proxima Centauri) is at a distance of 4.24 1.y. and has a radius of about 98.1 × 10³ km to determine its angular diameter. (b.c 10 Col at its greatest brill! Id:stol s1802 to noiton srit of noitoubortal (i on hapitifunt od insup of hoes olsos A 14/49/phaigo odt pilhade fldgrante lize alter Brightes(sansin-boy) neglich beaten thun-Vaga) endoggi sonowies to note ballso aliso osis)arrow_forwardAs seen from earth the sun has an apparent magnitude and of about -26.7 what is the apparent magnitude of the sun as eeen from Saturn about 10AU away?arrow_forwardure This image is taken from the course content (Lessons or Readings). Select the words from the drop-down controls which best describe the image. Eris Pluto Neptune Saturn Uranus Jupiter Mars Earth Sun Venus The image shows the sun, the planets, and the • The objects are Mercury • largest known +arrow_forward
- Galileo’s telescope showed him that Venus has a large angular diameter (61 arc seconds) when it is a crescent and a small angular diameter (10 arc seconds) when it is nearly full. Use the small-angle formula to find the ratio of its maximum distance to its minim um distance. Is this ratio compatible with the Ptolemaic shown on the right-hand page of Concept Art 4A? (Hint: See Reasoning with Numbers 3-1.)arrow_forwardWhat is the angular diameter of Saturn (in arc seconds) as seen from Earth when the two planets are farthest apart?arrow_forwardAn asteroid is 3 AUaway fromthe Sun when it is observed from the Earth at opposition. How large does the asteroid have to be in order to occult a Sun-like Star at a distanced= 10pc? [Hint:θ=s/r.]arrow_forward
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