Universe: Stars And Galaxies
Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 18, Problem 11Q
To determine

To Explain: The type of spectrum lines that would be observed when one looks at the spectrum of a reflection nebula.Theway, a spectrum demonstrates that the light was reflected fromnearby stars.

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As a star runs out of hydrogen to fuel nuclear fusion in its core, changes within the star usually cause it to leave the main sequence, expanding and cooling as it does so. Would a star with a radius 6 times that of the Sun, but a surface temperature 0.4 times that of the Sun, be more, or less luminous than the Sun? Show and explain your reasoning. You may assume the surface area of a sphere is A = 4πr2.
Tutorial Star A has a temperature of 5,000 K. How much energy per second (in J/s/m2) does it radiate from a square meter of its surface? If the temperature of Star A decreases by a factor of 2, the energy will decrease by a factor of Star B has a temperature that is 5 times higher than Star A. How much more energy per second (compared to Star A) does it radiate from a square meter of its surface? Part 1 of 4 The energy of a star is related to its temperature by E = GT4 where σ = 5.67 x 10-8 J/s/m2/K4. Part 2 of 4 To determine how much energy Star A is radiating, we just plug in the temperature to solve for EA. EA = J/s/m² Submit Skip (you cannot come back)
Tutorial Star A has a temperature of 6,000 K. How much energy per second (in J/s/m²) does it radiate onto a square meter of its surface? If the temperature of Star A decreases by a factor of 2, the energy will decrease by a factor of Star B has a temperature that is 5 times higher than Star A. How much more energy per second (compared to Star A) does it radiate onto a square meter of its surface? Part 1 of 4 The energy of a star is related to its temperature by E = OTA where o = 5.67 x 10-8 J/s/m²/K4. Part 2 of 4 To determine how much energy Star A is radiating, we just plug in the temperature to solve for EA. EA J/s/m²
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