Physical Universe
16th Edition
ISBN: 9780077862619
Author: KRAUSKOPF, Konrad B. (konrad Bates), Beiser, Arthur
Publisher: Mcgraw-hill Education,
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Chapter 18, Problem 32E
To determine
Which is larger between a red star and white star when they both have equal brightness and same distance from earth.
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In the parallax method of determining stellar distances, the angle to a star is measured while
the earth is on one side of the sun and then again six months later, as in the diagram below.
Assume the earth-sun distance is 1 Astronomical Unit. The parallax angle of Alpha Centauri
is 0= 2.1 x 10-4 ° . Find the distance from the sun to a Centauri in light years. Assume a
circular orbit for the Earth.
a Centauri
Earth (June)
Earth (December)
Sun
If we view a star now, and then view it again 6 months later, our position will have changed by the diameter of the Earth's orbit around the sun. For nearby stars (within 100 light-years or so), the change in viewing location is sufficient to make the star appear to be in a slightly different location in the sky. Half of the angle from one location to the next is known as the parallax angle (see figure). Parallax can be used to measure the distance to the star. An approximate relationship is given by
d =
3.26
p
,
where d is the distance in light-years, and p is the parallax measured in seconds of arc. Vega is a star that has a parallax angle of 0.13 second. How far is Vega from the sun? Note: Parallax is used not only to measure stellar distances. Our binocular vision actually provides the brain with a parallax angle that it uses to estimate distances to objects we see. (Round your answer to two decimal places.) light-years
The star Sirius has an apparent magnitude of -1.46 and appears 95-times brighter compared tothe more distant star Tau Ceti, which has an absolute magnitude of 5.69.(a) Explain the terms apparent magnitude, absolute magnitude and bolometric magnitude.(b) Calculate the apparent magnitude of the star Tau Ceti.(c) Find the distance between the Earth and Tau Ceti.www.
Chapter 18 Solutions
Physical Universe
Ch. 18 - Prob. 1MCCh. 18 - Prob. 2MCCh. 18 - Prob. 3MCCh. 18 - Prob. 4MCCh. 18 - Prob. 5MCCh. 18 - Prob. 6MCCh. 18 - Prob. 7MCCh. 18 - Prob. 8MCCh. 18 - Prob. 9MCCh. 18 - Prob. 10MC
Ch. 18 - Prob. 11MCCh. 18 - Prob. 12MCCh. 18 - Prob. 13MCCh. 18 - Prob. 14MCCh. 18 - Prob. 15MCCh. 18 - Prob. 16MCCh. 18 - If we know both the luminosity and brightness of a...Ch. 18 - Prob. 18MCCh. 18 - Prob. 19MCCh. 18 - Prob. 20MCCh. 18 - Prob. 21MCCh. 18 - Prob. 22MCCh. 18 - Prob. 23MCCh. 18 - Prob. 24MCCh. 18 - Prob. 25MCCh. 18 - Prob. 26MCCh. 18 - Prob. 27MCCh. 18 - Prob. 28MCCh. 18 - Prob. 29MCCh. 18 - Prob. 30MCCh. 18 - Prob. 31MCCh. 18 - Prob. 32MCCh. 18 - Prob. 33MCCh. 18 - Prob. 34MCCh. 18 - Prob. 35MCCh. 18 - Prob. 36MCCh. 18 - Prob. 37MCCh. 18 - Prob. 38MCCh. 18 - Prob. 39MCCh. 18 - Black holes are remnants of a. stars with small...Ch. 18 - Prob. 1ECh. 18 - Prob. 2ECh. 18 - Prob. 3ECh. 18 - Prob. 4ECh. 18 - Prob. 5ECh. 18 - Prob. 6ECh. 18 - Prob. 7ECh. 18 - Prob. 8ECh. 18 - Prob. 9ECh. 18 - Prob. 10ECh. 18 - Prob. 11ECh. 18 - Prob. 12ECh. 18 - Prob. 13ECh. 18 - Prob. 14ECh. 18 - Prob. 15ECh. 18 - Prob. 16ECh. 18 - Prob. 17ECh. 18 - Prob. 18ECh. 18 - Prob. 19ECh. 18 - Prob. 20ECh. 18 - Prob. 21ECh. 18 - Prob. 22ECh. 18 - Prob. 23ECh. 18 - Prob. 24ECh. 18 - Prob. 25ECh. 18 - Prob. 26ECh. 18 - Prob. 27ECh. 18 - Prob. 28ECh. 18 - Prob. 29ECh. 18 - Prob. 30ECh. 18 - Prob. 31ECh. 18 - Prob. 32ECh. 18 - Prob. 33ECh. 18 - Prob. 34ECh. 18 - Prob. 35ECh. 18 - Prob. 36ECh. 18 - Prob. 37ECh. 18 - Prob. 38ECh. 18 - Prob. 39ECh. 18 - Prob. 40ECh. 18 - Prob. 41ECh. 18 - Prob. 42ECh. 18 - Prob. 43ECh. 18 - Prob. 44ECh. 18 - Prob. 45ECh. 18 - Prob. 46ECh. 18 - Prob. 47ECh. 18 - Prob. 48ECh. 18 - Prob. 49ECh. 18 - Prob. 50ECh. 18 - Prob. 51ECh. 18 - Prob. 52ECh. 18 - Prob. 53ECh. 18 - Prob. 54ECh. 18 - Prob. 55ECh. 18 - How large are black holes? Can any star evolve...Ch. 18 - Prob. 57ECh. 18 - Prob. 58E
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- A star is observed at a distance of 90 pc. What will be its parallax angle?arrow_forward)The apparent brightness of the Earth is inversely proportional to the square of the distance between the Earth and the star) True or falsearrow_forwardAccording to the equation d=1/p, a star whose parallax angle is 1/50” is how far away?arrow_forward
- The nearest star to our sun is Proxima Centauri, at a distance of 4.3 light-years from the Sun. A light-year is the distance that light travels in one year (365 days). How far away, in kilometers, is Proxima Centauri from the Sun?Express your answer using two significant figures.arrow_forwardEarth is about 150 million kilometers from the Sun (1 Astronomical Unit, or AU), and the apparent brightness of the Sun in our sky is about 1300 watts/m^2. Using these two facts and the inverse square law for light, determine the apparent brightness that we would measure for the Sun if we were located at the following positions. b) At the orbit of Jupiter (780 million km from the Sun).arrow_forwardA particular star is 4.5 × 1014 km away from Earth. What is this distance in light-years (ly)?arrow_forward
- Earth is about 150 million kilometers from the Sun, and the apparent brightness of the Sun in our sky is about 1300 watts/m2. Determine the apparent brightness that we would measure for the Sun if we were located 12 times Earth's distance from the Sun.arrow_forwardQ15. The space observatory Gaia was launched in 2013 as the successor to Hipparcos and is returning data on its ambitious mission to catalog the 3- dimensional position of more than 1 billion stars in the Milky Way. The smallest parallax angle it can measure, for stars of at least magnitude 12, is 0.000008", What is the most distant star to which Gaia can measure parallax? Q16. The center of our Galaxy is about 8,500 parsecs from Earth. a. What would be the parallax angle of a star near the center of the Galaxy? b. Could this angle be measured by Hipparcos? c. Could this angle be measured by Gaia?arrow_forwardRaising a number in scientific notation to a power is easy: (5 x 105)² = (5)² x (105)² = 5 x 5 x 105 x 105 = 25 x 10(5 × 2) = 25 x 1010 = 2.5 x 101¹1 Keeping this in mind, what is the volume of the sun in km³? The radius of the sun is about 7 x 105 km, and the volume of a sphere is 4/3 x Pi x R³. (Use 3.14 for Pi, and enter your answer with two decimal places). km³ 3 What is the average density of the Sun? Density = mass / volume. The mass of the sun is 2.0x10³0 kg. kg/km³arrow_forward
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