CHEMISTRY-TEXT
CHEMISTRY-TEXT
8th Edition
ISBN: 9780134856230
Author: Robinson
Publisher: PEARSON
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Chapter 18, Problem 18.127MP
Interpretation Introduction

(a)

Interpretation:

The equation that shows temperature dependence of equilibrium constant with entropy is to be derived

Concept introduction:

The formula that determines spontaneity of the reaction is,

ΔG°=ΔH°TΔS°

Where,

  • ΔS° denotes entropy change of reaction.
  • ΔH° denotes enthalpy change of reaction

The expression to evaluate free energy from equilibrium constant is as follows:

ΔG°=RTlnK

Where,

  • K represents equilibrium constant.
  • ΔG° denotes standard free energy change.
  • R denotes gas constant.
  • T denotes temperature.

Interpretation Introduction

(b)

Interpretation:

The manner in that this equation can be used to determine experimental values of ΔH°, ΔS° should be explained.

Concept introduction:

The formula that determines spontaneity of the reaction is,

ΔG°=ΔH°TΔS°

Where,

  • ΔS° denotes entropy change of reaction.
  • ΔH° denotes enthalpy change of reaction

The expression to evaluate free energy from equilibrium constant is as follows:

ΔG°=RTlnK

Where,

  • K represents equilibrium constant.
  • ΔG° denotes standard free energy change.
  • R denotes gas constant.
  • T denotes temperature.

Interpretation Introduction

(c)

Interpretation:

Sign of ΔH° should be predicted on the basis of the given equation.

Concept introduction:

The formula that determines spontaneity of the reaction is,

ΔG°=ΔH°TΔS°

Where,

  • ΔS° denotes entropy change of reaction.
  • ΔH° denotes enthalpy change of reaction

The expression to evaluate free energy from equilibrium constant is as follows:

ΔG°=RTlnK

Where,

  • K represents equilibrium constant.
  • ΔG° denotes standard free energy change.
  • R denotes gas constant.
  • T denotes temperature.

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Students have asked these similar questions
For the gaseous reaction of carbon monoxide and chlorine to form phosgene (COCl2), perform the following calculations. (a) Calculate the Δ S o     at 298 K ( Δ H o     = −220. kJ/mol and Δ G o     = −206 kJ/mol).    kJ/mol · K (b) Assuming that Δ S o     and Δ H o     change little with temperature, calculate Δ G o     at 450. K.     kJ/mol
If experimental determinations of Kp at different temperatures for a given equilibrium in the temperature range 20-40 ºC are fitted to the function shown below: ln Kp = a T-2 + c ln(T) (a = 123.5 K2;c = 23.6) What is the value of ΔHº and ΔSº at 25 ºC? and ΔGº at 35 ºC? Give expressions.
Indicate whether each statement is true or false. (a) The third law of thermodynamics says that the entropy of a perfect, pure crystal at absolute zero increases with the mass of the crystal.

Chapter 18 Solutions

CHEMISTRY-TEXT

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