Explanation Given information: The decomposition of PbI 2 is given as follows: PbI 2 ⇌ Pb 2 + + 2 I − The expression of solubility product is written as follows: K sp = [ Pb 2 + ] [ I − ] 2 Consider the solubility of PbI 2 to be s and therefore, the concentration of Pb 2 + and I − be s and is represented as follows: [ Pb 2 + ] = [ I − ] = s The above expression of K sp is written as, K sp = [ Pb 2 + ] [ I − ] 2 = ( s ) ( 2 s ) 2 = 4 s 3 The value of molar solubility is given as 1.45 × 10 − 3 M . Substitute to obtain the value of K sp . K sp = 4 s 3 = 4 ( 1.45 × 10 − 3 ) 3 = 1.22 × 10 − 8 Similarly at 80 ° C , The value of molar solubility is given as 6.85 × 10 − 3 M . Substitute to obtain the value of K sp . K sp = 4 s 3 = 4 ( 6.85 × 10 − 3 ) 3 = 1.29 × 10 − 6 The formula to convert degree Celsius to kelvin is as follows: T ( K ) = T ( ° C ) + 273 K The temperature in Celsius is 20 ° C . Substitute in above formula. T ( K ) = T ( ° C ) + 273 K = 20 ° C + 273 K = 293 K The formula to convert degree Celsius to kelvin is as follows: T ( K ) = T ( ° C ) + 273 K The temperature in Celsius is 80 ° C . Substitute in above formula. T ( K ) = T ( ° C ) + 273 K = 80 ° C + 273 K = 353 K The expression to evaluate ΔH ° is given by the equation as follows: ln K 1 K 2 = Δ H ° R ( 1 T 2 − 1 T 1 ) The value of K 1 is 1

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Author: Robinson

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Chapter 18, Problem 18.129MP

Interpretation Introduction

Interpretation:

The values of ΔH° and ΔS° for dissolution of PbI2 is to be calculated.

Concept introduction:

The expression to evaluate ΔH° is given by the equation as follows:

lnK1K2=ΔH°R(1T2−1T1)

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Chapter 18, Problem 18.128MP

Chapter 18, Problem 18.130MP

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The values of Δ H ° and Δ S ° for dissolution of PbI 2 is to be calculated. Concept introduction: The expression to evaluate ΔH ° is given by the equation as follows: ln K 1 K 2 = Δ H ° R ( 1 T 2 − 1 T 1 )

Solution Summary: The author explains that the expression to evaluate H° is given by the equation as follows:

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Interpretation:

The values of ΔH° and ΔS° for dissolution of PbI2 is to be calculated.

Concept introduction:

The expression to evaluate ΔH° is given by the equation as follows:

lnK1K2=ΔH°R(1T2−1T1)

Want to see the full answer?

Chapter 18 Solutions

The values of Δ H ° and Δ S ° for dissolution of PbI 2 is to be calculated. Concept introduction: The expression to evaluate ΔH ° is given by the equation as follows: ln K 1 K 2 = Δ H ° R ( 1 T 2 − 1 T 1 )

Solution Summary: The author explains that the expression to evaluate H° is given by the equation as follows:

Concept explainers

Videos

Interpretation: The values of ΔH° and ΔS° for dissolution of PbI2 is to be calculated. Concept introduction: The expression to evaluate ΔH° is given by the equation as follows: lnK1K2=ΔH°R(1T2−1T1)

Want to see the full answer?

Chapter 18 Solutions

Interpretation:

The values of ΔH° and ΔS° for dissolution of PbI2 is to be calculated.

Concept introduction:

The expression to evaluate ΔH° is given by the equation as follows:

lnK1K2=ΔH°R(1T2−1T1)