
Interpretation: The amount of heat absorbed when 5.66g of CS2 is formed from its elements.
Concept introduction: Endothermic reactions are those in which heat is absorbed by the reactants and enthalpy change for the reaction is positive.
The standard enthalpy of formation is the amount of energy released or consumed when one mole of a substance is formed under standard conditions from its pure elements.

Answer to Problem 15SP
The amount of heat absorbed when 5.66g of CS2 is formed from its elements is 6.61 kJ
Explanation of Solution
The given chemical equation is:
C(s)+2S(s)→CS2(l) ΔH=89.3 kJ
Thus, the standard enthalpy of formation of CS2 is 89.3 kJ
Given the amount of CS2 = 5.66g
Moles of CS2 is found by dividing the given amount of CS2 by the molecular mass of CS2 .
Moles of CS2 given = 5.66g76.2gmol-1=0.074mol
For the formation of 1 mol of CS2 , heat absorbed is = 89.3 kJ
Thus, for the formation of 0.074 mol
CS2 , heat absorbed is = 89.3kJ1mol×0.074mol=6.61 kJ
Chapter 17 Solutions
Chemistry 2012 Student Edition (hard Cover) Grade 11
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