Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 17, Problem 110A

(a)

Interpretation Introduction

Interpretation: The number of anions required to form an electrically neutral compound is to be found.

Concept Introduction : Ionic compounds are formed by the transfer of electrons between metal and non-metal. For the formation of a neutral ionic compound, the charges on the cation and anion must be balanced. The cation is formed by the loss of electrons by metals and anions are formed by the gain of electrons by nonmetals.

(a)

Expert Solution
Check Mark

Answer to Problem 110A

The number of chloride ions required to react with strontium cation to make an electrically neutral particle is 2 .

Explanation of Solution

Here the given metal is strontium which is having an oxidation state of +2 called as Sr2+ cation and chlorine forms an anion Cl- with the oxidation state of 1 . In order to form an electrically neutral particle, two chloride ions must combine with strontium cation to give neutral SrCl2 named as strontium chloride.

(b)

Interpretation Introduction

Interpretation: The number of anions required to form an electrically neutral compound is to be found.

Concept Introduction : Ionic compounds are formed by the transfer of electrons between metal and non-metal. For the formation of a neutral ionic compound, the charges on the cation and anion must be balanced. The cation is formed by the loss of electrons by metals and anions are formed by the gain of electrons by nonmetals.

(b)

Expert Solution
Check Mark

Answer to Problem 110A

The number of chloride ions required to react with calcium cation to make an electrically neutral particle is 2 .

Explanation of Solution

Here the given metal is calcium which is having an oxidation state of +2 called as Ca2+ cation and chlorine forms an anion Cl- with the oxidation state of 1 . In order to form an electrically neutral particle, two chloride ions must combine with a calcium cation to give a neutral CaCl2 named as calcium chloride.

(c)

Interpretation Introduction

Interpretation: The number of anions required to form an electrically neutral compound is to be found.

Concept Introduction : Ionic compounds are formed by the transfer of electrons between metal and non-metal. For the formation of a neutral ionic compound, the charges on the cation and anion must be balanced. The cation is formed by the loss of electrons by metals and anions are formed by the gain of electrons by nonmetals.

(c)

Expert Solution
Check Mark

Answer to Problem 110A

The number of chloride ions required to react with aluminum cation to make an electrically neutral particle is 3 .

Explanation of Solution

Here the given metal is aluminum which is having an oxidation state of +3 called as Al3+ cation and chlorine forms an anion Cl- with the oxidation state of 1 . In order to form an electrically neutral particle, three chloride ions must combine with an aluminum cation to give a neutral AlCl3 named as aluminum chloride.

(d)

Interpretation Introduction

Interpretation: The number of anions required to form an electrically neutral compound is to be found.

Concept Introduction : Ionic compounds are formed by the transfer of electrons between metal and non-metal. For the formation of a neutral ionic compound, the charges on the cation and anion must be balanced. The cation is formed by the loss of electrons by metals and anions are formed by the gain of electrons by nonmetals.

(d)

Expert Solution
Check Mark

Answer to Problem 110A

The number of chloride ions required to react with lithium cation to make an electrically neutral particle is 1 .

Explanation of Solution

Here the given metal is lithium which is having an oxidation state of +1 called as Li+ cation and chlorine forms an anion Cl- with the oxidation state of 1 . In order to form an electrically neutral particle, one chloride ion must combine with a lithium cation to give a neutral LiCl named as lithium chloride.

Chapter 17 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 17.1 - Prob. 11LCCh. 17.2 - Prob. 12SPCh. 17.2 - Prob. 13SPCh. 17.2 - Prob. 14SPCh. 17.2 - Prob. 15SPCh. 17.2 - Prob. 16LCCh. 17.2 - Prob. 17LCCh. 17.2 - Prob. 18LCCh. 17.2 - Prob. 19LCCh. 17.2 - Prob. 20LCCh. 17.2 - Prob. 21LCCh. 17.3 - Prob. 22SPCh. 17.3 - Prob. 23SPCh. 17.3 - Prob. 24SPCh. 17.3 - Prob. 25SPCh. 17.3 - Prob. 26SPCh. 17.3 - Prob. 27SPCh. 17.3 - Prob. 28LCCh. 17.3 - Prob. 29LCCh. 17.3 - Prob. 30LCCh. 17.3 - Prob. 31LCCh. 17.3 - Prob. 32LCCh. 17.3 - Prob. 33LCCh. 17.3 - Prob. 34LCCh. 17.4 - Prob. 35SPCh. 17.4 - Prob. 36SPCh. 17.4 - Prob. 37LCCh. 17.4 - Prob. 38LCCh. 17.4 - Prob. 39LCCh. 17.4 - Prob. 40LCCh. 17.4 - Prob. 41LCCh. 17 - Prob. 42ACh. 17 - Prob. 44ACh. 17 - Prob. 45ACh. 17 - Prob. 46ACh. 17 - Prob. 47ACh. 17 - Prob. 48ACh. 17 - Prob. 49ACh. 17 - Prob. 50ACh. 17 - Prob. 51ACh. 17 - Prob. 52ACh. 17 - Prob. 53ACh. 17 - Prob. 54ACh. 17 - Prob. 55ACh. 17 - Prob. 56ACh. 17 - Prob. 57ACh. 17 - Prob. 58ACh. 17 - Prob. 59ACh. 17 - Prob. 60ACh. 17 - Prob. 61ACh. 17 - Prob. 62ACh. 17 - Prob. 63ACh. 17 - Prob. 64ACh. 17 - Prob. 65ACh. 17 - Prob. 66ACh. 17 - Prob. 67ACh. 17 - Prob. 68ACh. 17 - Prob. 69ACh. 17 - Prob. 70ACh. 17 - Prob. 71ACh. 17 - Prob. 72ACh. 17 - Prob. 73ACh. 17 - Prob. 74ACh. 17 - Prob. 75ACh. 17 - Prob. 76ACh. 17 - Prob. 77ACh. 17 - Prob. 78ACh. 17 - Prob. 79ACh. 17 - Prob. 80ACh. 17 - Prob. 81ACh. 17 - Prob. 82ACh. 17 - Prob. 83ACh. 17 - Prob. 84ACh. 17 - Prob. 85ACh. 17 - Prob. 86ACh. 17 - Prob. 87ACh. 17 - Prob. 88ACh. 17 - Prob. 89ACh. 17 - Prob. 90ACh. 17 - Prob. 91ACh. 17 - Prob. 92ACh. 17 - Prob. 93ACh. 17 - Prob. 94ACh. 17 - Prob. 95ACh. 17 - Prob. 96ACh. 17 - Prob. 97ACh. 17 - Prob. 98ACh. 17 - Prob. 99ACh. 17 - Prob. 100ACh. 17 - Prob. 101ACh. 17 - Prob. 102ACh. 17 - Prob. 103ACh. 17 - Prob. 104ACh. 17 - Prob. 105ACh. 17 - Prob. 106ACh. 17 - Prob. 107ACh. 17 - Prob. 108ACh. 17 - Prob. 109ACh. 17 - Prob. 110ACh. 17 - Prob. 111ACh. 17 - Prob. 112ACh. 17 - Prob. 113ACh. 17 - Prob. 114ACh. 17 - Prob. 115ACh. 17 - Prob. 116ACh. 17 - Prob. 117ACh. 17 - Prob. 118ACh. 17 - Prob. 119ACh. 17 - Prob. 120ACh. 17 - Prob. 1STPCh. 17 - Prob. 2STPCh. 17 - Prob. 3STPCh. 17 - Prob. 4STPCh. 17 - Prob. 5STPCh. 17 - Prob. 6STPCh. 17 - Prob. 7STPCh. 17 - Prob. 8STPCh. 17 - Prob. 9STPCh. 17 - Prob. 10STP
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