Chemistry 2012 Student Edition (hard Cover) Grade 11
Chemistry 2012 Student Edition (hard Cover) Grade 11
12th Edition
ISBN: 9780132525763
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 17, Problem 5STP
Interpretation Introduction

Interpretation: The temperature of the alcohol increases by what amount is to be determined.

Concept Introduction: The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Mathematically it is represented by

  Q=m×C×ΔT

  Q = Heat absorbed or released

  m = mass of the substance

  C = heat capacity of the substance

  ΔT = change in temperature

Expert Solution & Answer
Check Mark

Answer to Problem 5STP

Increases 4.5°C

Explanation of Solution

The heat absorbed by alcohol will be equal to the heat released by silver.

It is given that the heat capacity of ethanol is ten times larger than the heat capacity of silver.

Thus, Calc=10×Csil

  malc= msil= 55g

Putting in the values, we get:

  meth×Ceth×(ΔTeth)=-[msil×Csil×(ΔTsil)]55g×10×Csil×(ΔTeth)=-[55g×Csil×-45°C]ΔTeth=+4.5°C

Chapter 17 Solutions

Chemistry 2012 Student Edition (hard Cover) Grade 11

Ch. 17.1 - Prob. 11LCCh. 17.2 - Prob. 12SPCh. 17.2 - Prob. 13SPCh. 17.2 - Prob. 14SPCh. 17.2 - Prob. 15SPCh. 17.2 - Prob. 16LCCh. 17.2 - Prob. 17LCCh. 17.2 - Prob. 18LCCh. 17.2 - Prob. 19LCCh. 17.2 - Prob. 20LCCh. 17.2 - Prob. 21LCCh. 17.3 - Prob. 22SPCh. 17.3 - Prob. 23SPCh. 17.3 - Prob. 24SPCh. 17.3 - Prob. 25SPCh. 17.3 - Prob. 26SPCh. 17.3 - Prob. 27SPCh. 17.3 - Prob. 28LCCh. 17.3 - Prob. 29LCCh. 17.3 - Prob. 30LCCh. 17.3 - Prob. 31LCCh. 17.3 - Prob. 32LCCh. 17.3 - Prob. 33LCCh. 17.3 - Prob. 34LCCh. 17.4 - Prob. 35SPCh. 17.4 - Prob. 36SPCh. 17.4 - Prob. 37LCCh. 17.4 - Prob. 38LCCh. 17.4 - Prob. 39LCCh. 17.4 - Prob. 40LCCh. 17.4 - Prob. 41LCCh. 17 - Prob. 42ACh. 17 - Prob. 44ACh. 17 - Prob. 45ACh. 17 - Prob. 46ACh. 17 - Prob. 47ACh. 17 - Prob. 48ACh. 17 - Prob. 49ACh. 17 - Prob. 50ACh. 17 - Prob. 51ACh. 17 - Prob. 52ACh. 17 - Prob. 53ACh. 17 - Prob. 54ACh. 17 - Prob. 55ACh. 17 - Prob. 56ACh. 17 - Prob. 57ACh. 17 - Prob. 58ACh. 17 - Prob. 59ACh. 17 - Prob. 60ACh. 17 - Prob. 61ACh. 17 - Prob. 62ACh. 17 - Prob. 63ACh. 17 - Prob. 64ACh. 17 - Prob. 65ACh. 17 - Prob. 66ACh. 17 - Prob. 67ACh. 17 - Prob. 68ACh. 17 - Prob. 69ACh. 17 - Prob. 70ACh. 17 - Prob. 71ACh. 17 - Prob. 72ACh. 17 - Prob. 73ACh. 17 - Prob. 74ACh. 17 - Prob. 75ACh. 17 - Prob. 76ACh. 17 - Prob. 77ACh. 17 - Prob. 78ACh. 17 - Prob. 79ACh. 17 - Prob. 80ACh. 17 - Prob. 81ACh. 17 - Prob. 82ACh. 17 - Prob. 83ACh. 17 - Prob. 84ACh. 17 - Prob. 85ACh. 17 - Prob. 86ACh. 17 - Prob. 87ACh. 17 - Prob. 88ACh. 17 - Prob. 89ACh. 17 - Prob. 90ACh. 17 - Prob. 91ACh. 17 - Prob. 92ACh. 17 - Prob. 93ACh. 17 - Prob. 94ACh. 17 - Prob. 95ACh. 17 - Prob. 96ACh. 17 - Prob. 97ACh. 17 - Prob. 98ACh. 17 - Prob. 99ACh. 17 - Prob. 100ACh. 17 - Prob. 101ACh. 17 - Prob. 102ACh. 17 - Prob. 103ACh. 17 - Prob. 104ACh. 17 - Prob. 105ACh. 17 - Prob. 106ACh. 17 - Prob. 107ACh. 17 - Prob. 108ACh. 17 - Prob. 109ACh. 17 - Prob. 110ACh. 17 - Prob. 111ACh. 17 - Prob. 112ACh. 17 - Prob. 113ACh. 17 - Prob. 114ACh. 17 - Prob. 115ACh. 17 - Prob. 116ACh. 17 - Prob. 117ACh. 17 - Prob. 118ACh. 17 - Prob. 119ACh. 17 - Prob. 120ACh. 17 - Prob. 1STPCh. 17 - Prob. 2STPCh. 17 - Prob. 3STPCh. 17 - Prob. 4STPCh. 17 - Prob. 5STPCh. 17 - Prob. 6STPCh. 17 - Prob. 7STPCh. 17 - Prob. 8STPCh. 17 - Prob. 9STPCh. 17 - Prob. 10STP
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