Interpretation:
The number of molecules of H2O,CO,H2 and CO2 present in the equilibrium have to be calculated using trial and error method.
Concept Introduction:
Answer to Problem 68A
At equilibrium the container contains 4 molecules of H2O,2molecules of CO,4molecules of H2 and 4molecules of CO2.
Explanation of Solution
Data given: Keq = 2.0
The given chemical equation is-
Initially 8molecules of H2O and6molecules of COare present in the container.
Case I:
If 2molecules of CO react:
The container will contain6molecules of H2O,4molecules of CO,2molecules of H2 and 2molecules of CO2.
Case I is not right.
Case II:
If 3molecules of COreact:
The container will contain5molecules of H2O,3molecules of CO,3molecules of H2 and 3molecules of CO2.
Case II is not right.
Case III:
If 4molecules of CO react:
The container will contain 4molecules of H2O,2molecules of CO,4molecules of H2 and 4molecules of CO2.
The equilibrium constant Keq value calculated in case III matches with the given data.
Chapter 17 Solutions
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