Chapter 17, Problem 4STP

Interpretation Introduction

Interpretation:The effect of addition of oxygen gas on the given equilibrium reaction and on the value of $K$ is to be explained.

Concept Introduction: The equilibrium reactions are governed by Le-Chatlier’s principle. As per this principle, a reaction at equilibrium tends to be in equilibrium. If any change occurs be it change in concentration of reactants, products, change in volume, temperature or pressure the reaction shifts itself in a direction that nullifies the change occurred. Also $K$ is the equilibrium constant and it is independent of the concentration of the reactants and products.

Answer to Problem 4STP

Correct answer: The amount of $N{O}_{(g)}$ increases and the value $K$ remains the same.

Explanation of Solution

Reason for correct option: The given reaction is $N_{2(g)}+O_{2(g)}$$2N{O}_{(g)}$

. Oxygen is a reactant. As per Le-Chatlier’s principle, on increasing its concentration, reaction will shift in the direction of product in order to nullify the change that has occurred. This results in the increase in concentration of whereas $K$ remains the same as it is independent of the concentration of the reactants and products.

Conclusion

Reasons for incorrect options: The amount of cannot decrease as per Le-Chatlier’s principle and also the value for $K$ does not increase as it is independent of the concentration of the reactants and products.