Thermodynamics: An Engineering Approach
9th Edition
ISBN: 9781259822674
Author: Yunus A. Cengel Dr., Michael A. Boles
Publisher: McGraw-Hill Education
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Chapter 16.6, Problem 116FEP
To determine
The number of independent variables that need to be specified to fix the state of the mixture is
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V.
W.
Th
To
%3D
Room temperature T = 293 K
V
V. Vp
The gas volume changes from Vp to Va at constant temperature T. The cartoon on the right shows a piston of gas undergoing this
compression while submerged in a container of room temperature water, which acts as a reservoir.
The initial state of this process is a piston containing 2 moles of a monatomic gas at Tc = 293 K (room temperature water) and volume V =
a
1.0 m. The gas is compressed until V, = 0.2 m. During the compression, the heat bath of room temperature water maintains the
temperature of the gas at T 293 K.
Calculate the work done in joules by the gas during this process.
Do not include units in your answer.
Be careful to use the standard sign convention for work done by the gas.
Write your numerical answer in normal form as described above in the instructions to this worksheet.
Two kg of a two-phase, liquid-vapor mixture of carbon dioxide exists at -40 °C in a 0.05m^3 tank.determinw the quality of the mixture...
An insulated rigid tank contains a saturated liquid-vapor mix of water initially at a pressure of 100 kPa. The
mass of the mixture is 5 kg, but only 75.6 % of the total mass is liquid. An electric resistance heater is turned
on within the tank until all the water has just vaporized. The heater power is a constant 2.2 kW. Hint: you will
not need to interpolate to find the solution to part (b).
Note: quantities shown in the figure are not necessarily to scale
(CC) BY-NC-SA Niel Crews, 2013
a) What is the volume of the container?
ww
b) How long was the heater on?
3
mº
minutes
Chapter 16 Solutions
Thermodynamics: An Engineering Approach
Ch. 16.6 - Why is the criterion for chemical equilibrium...Ch. 16.6 - Write three different KPrelations for reacting...Ch. 16.6 - Is a wooden table in chemical equilibrium with the...Ch. 16.6 - A reaction chamber contains a mixture of CO2, CO,...Ch. 16.6 - A reaction chamber contains a mixture of N2and N...Ch. 16.6 - A reaction chamber contains a mixture of CO2, CO,...Ch. 16.6 - Which element is more likely to dissociate into...Ch. 16.6 - Prob. 8PCh. 16.6 - Prob. 9PCh. 16.6 - Prob. 10P
Ch. 16.6 - Prob. 11PCh. 16.6 - Prob. 12PCh. 16.6 - Prob. 13PCh. 16.6 - Prob. 14PCh. 16.6 - Prob. 15PCh. 16.6 - Prob. 16PCh. 16.6 - Prob. 17PCh. 16.6 - Prob. 18PCh. 16.6 - Prob. 19PCh. 16.6 - Prob. 20PCh. 16.6 - Prob. 21PCh. 16.6 - Prob. 22PCh. 16.6 - Prob. 23PCh. 16.6 - Determine the equilibrium constant KP for the...Ch. 16.6 - Prob. 26PCh. 16.6 - Prob. 27PCh. 16.6 - Carbon monoxide is burned with 100 percent excess...Ch. 16.6 - Prob. 30PCh. 16.6 - Prob. 31PCh. 16.6 - Estimate KP for the following equilibrium reaction...Ch. 16.6 - Prob. 33PCh. 16.6 - A mixture of 3 mol of N2, 1 mol of O2, and 0.1 mol...Ch. 16.6 - Prob. 35PCh. 16.6 - Prob. 36PCh. 16.6 - Prob. 37PCh. 16.6 - Prob. 38PCh. 16.6 - Prob. 40PCh. 16.6 - What is the equilibrium criterion for systems that...Ch. 16.6 - Prob. 43PCh. 16.6 - Prob. 44PCh. 16.6 - Prob. 45PCh. 16.6 - Prob. 47PCh. 16.6 - Prob. 48PCh. 16.6 - Prob. 51PCh. 16.6 - Prob. 52PCh. 16.6 - Prob. 53PCh. 16.6 - Prob. 54PCh. 16.6 - Prob. 55PCh. 16.6 - Prob. 56PCh. 16.6 - Prob. 58PCh. 16.6 - Prob. 59PCh. 16.6 - Prob. 60PCh. 16.6 - Prob. 61PCh. 16.6 - Using the Henrys constant data for a gas dissolved...Ch. 16.6 - Prob. 63PCh. 16.6 - Prob. 64PCh. 16.6 - Prob. 65PCh. 16.6 - Prob. 66PCh. 16.6 - A liquid-vapor mixture of refrigerant-134a is at...Ch. 16.6 - Prob. 68PCh. 16.6 - Prob. 69PCh. 16.6 - An oxygennitrogen mixture consists of 30 kg of...Ch. 16.6 - Prob. 71PCh. 16.6 - Prob. 72PCh. 16.6 - Prob. 73PCh. 16.6 - Prob. 74PCh. 16.6 - Prob. 75PCh. 16.6 - Prob. 76PCh. 16.6 - An ammoniawater absorption refrigeration unit...Ch. 16.6 - Prob. 78PCh. 16.6 - Prob. 79PCh. 16.6 - Prob. 80PCh. 16.6 - One lbmol of refrigerant-134a is mixed with 1...Ch. 16.6 - Prob. 82RPCh. 16.6 - Prob. 83RPCh. 16.6 - Prob. 84RPCh. 16.6 - Prob. 85RPCh. 16.6 - Prob. 88RPCh. 16.6 - Prob. 89RPCh. 16.6 - Prob. 90RPCh. 16.6 - Prob. 91RPCh. 16.6 - Prob. 92RPCh. 16.6 - A constant-volume tank contains a mixture of 1 mol...Ch. 16.6 - Prob. 94RPCh. 16.6 - Prob. 95RPCh. 16.6 - Prob. 96RPCh. 16.6 - Prob. 97RPCh. 16.6 - Prob. 99RPCh. 16.6 - Consider a glass of water in a room at 25C and 100...Ch. 16.6 - Prob. 101RPCh. 16.6 - Prob. 102RPCh. 16.6 - Prob. 105RPCh. 16.6 - Prob. 106RPCh. 16.6 - Prob. 107RPCh. 16.6 - Prob. 108RPCh. 16.6 - Prob. 109FEPCh. 16.6 - Prob. 110FEPCh. 16.6 - Prob. 111FEPCh. 16.6 - Prob. 112FEPCh. 16.6 - Prob. 113FEPCh. 16.6 - Prob. 114FEPCh. 16.6 - Propane C3H8 is burned with air, and the...Ch. 16.6 - Prob. 116FEPCh. 16.6 - Prob. 117FEPCh. 16.6 - The solubility of nitrogen gas in rubber at 25C is...
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- dioxide (CO,) exists at-40°C in a 0.05 m tank. Determine 3.16 Two kg of a two-phase, liquid-vapor mixture of carbon the quality of the mixture, if the values of specific volume for saturated liquid and saturated vapor CO, at -40C are vy = 0.896 x 10 m/kg and v, = 3.824 x 10 m'/ka respectively.arrow_forwardA0.5-m3 tank holds a two-phase liquid-vapor mixture of carbon dioxide at -17°C. The quality of the mixture is 20.0%. For saturated carbon dioxide at -17°C, V; = 0.9827 x 103m/kg and vg = 1.756 x 102 m³/kg. Determine the masses of saturated liquid and saturated vapor, each in kg. What is the percent of the total volume occupied by saturated liquid? Part A Determine the masses of saturated liquid and saturated vapor, each in kg. kg mg= kg i Attempts: 0 of 3 used Submit Answer Save for Later Using multiple attempts will impact your score. 10% score reduction after attempt 1 Part B The parts of this question must be completed in order. This part will be available when you complete the part above.arrow_forwardIf 10 kg of ice at 0C is added to 2 kg of steam at 100C, the temperature of resulting mixture isarrow_forward
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Lesson 2: Thermodynamic Properties; Author: The Thermo Sage;https://www.youtube.com/watch?v=qA-xwgliPAc;License: Standard Youtube License