Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 16, Problem 33Q
To determine
(a)
The longest wavelength required to dislodge the extra electron from a negative hydrogen ion.
To determine
(b)
The part of the
To determine
(c)
Whether a visible light photon is able to dislodge the extra electron from a negative hydrogen ion.
To determine
(d)
The reason for the photosphere that contains negative hydrogen ion to be quite opaque towards visible light but less opaque when light of wavelength greater than that obtained in part (a) is considered.
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A)Calculate the frequency when an electron drops from n=5 to the n=4 level in a hydrogen atom. Round your answer to 4 significant digits.
B)An electron in the hydrogen atom makes a transition from an energy state of principal quantum number ni to the n=2 state. If the photon emitted has a wavelength of 434nm , what is the value of ni? Round your answer to the nearest whole number.)
(a) A simplified parabolic E-K diagram for an electron in the conduction band is given in
Figure 3. Determine the relative effective mass, m'/m.. given the E – E. = C,k², value
of a of 1 nm, Planck constant h = 6.625 × 10-34 J. s, free electron mass m, = 9.11 x
10-31 kg, electric charge q = 1.6 x 10-19 C and 1 eV = 1.6 x 10-19 J.
E
E = E,+0.32 eV
Figure 3
The light observed that is emitted by a hydrogen atom is explained by a simple model of its structure with one proton in its nucleus and an electron bound to it, but only with internal energies of the atom satisfying
EH=−RH/n2EH=−RH/n2
where RHRH is the Rydberg constant and nn is an integer such as 1, 2, 3 ... and so on. When a hydrogen atom in an excited state emits light, the photon carries away energy and the atom goes into a lower energy state.
Be careful about units. The Rydberg constant in eV is
13.605693009 eV
That would be multiplied by the charge on the electron 1.602× 10-19 C to give
2.18× 10-18 J
A photon with this energy would have a frequency f such that E=hf. Its wavelength would be λ = c/f = hc/E. Sometimes it is handy to measure the Rydberg constant in units of 1/length for this reason. You may see it given as 109737 cm-1 if you search the web, so be aware that's not joules.
The following questions are intended to help you understand the connection between…
Chapter 16 Solutions
Universe: Stars And Galaxies
Ch. 16 - Prob. 1QCh. 16 - Prob. 2QCh. 16 - Prob. 3QCh. 16 - Prob. 4QCh. 16 - Prob. 5QCh. 16 - Prob. 6QCh. 16 - Prob. 7QCh. 16 - Prob. 8QCh. 16 - Prob. 9QCh. 16 - Prob. 10Q
Ch. 16 - Prob. 11QCh. 16 - Prob. 12QCh. 16 - Prob. 13QCh. 16 - Prob. 14QCh. 16 - Prob. 15QCh. 16 - Prob. 16QCh. 16 - Prob. 17QCh. 16 - Prob. 18QCh. 16 - Prob. 19QCh. 16 - Prob. 20QCh. 16 - Prob. 21QCh. 16 - Prob. 22QCh. 16 - Prob. 23QCh. 16 - Prob. 24QCh. 16 - Prob. 25QCh. 16 - Prob. 26QCh. 16 - Prob. 27QCh. 16 - Prob. 28QCh. 16 - Prob. 29QCh. 16 - Prob. 30QCh. 16 - Prob. 31QCh. 16 - Prob. 32QCh. 16 - Prob. 33QCh. 16 - Prob. 34QCh. 16 - Prob. 35QCh. 16 - Prob. 36QCh. 16 - Prob. 37QCh. 16 - Prob. 38QCh. 16 - Prob. 39QCh. 16 - Prob. 40QCh. 16 - Prob. 41QCh. 16 - Prob. 42QCh. 16 - Prob. 43QCh. 16 - Prob. 44QCh. 16 - Prob. 45QCh. 16 - Prob. 46QCh. 16 - Prob. 47QCh. 16 - Prob. 48QCh. 16 - Prob. 49QCh. 16 - Prob. 50QCh. 16 - Prob. 51QCh. 16 - Prob. 52QCh. 16 - Prob. 53QCh. 16 - Prob. 54QCh. 16 - Prob. 55QCh. 16 - Prob. 56QCh. 16 - Prob. 57QCh. 16 - Prob. 58QCh. 16 - Prob. 59QCh. 16 - Prob. 60Q
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