Organic Chemistry: Principles And Mechanisms
2nd Edition
ISBN: 9780393630756
Author: KARTY, Joel
Publisher: W.w. Norton & Company,
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Question
Chapter 16, Problem 16.31YT
Interpretation Introduction
Interpretation:
Hexane has six carbon atoms and dodecane has
Concept introduction:
The total number of carbon atoms in a molecule can be computed from the intensity of the
The equation
The base peak is the peak with the greatest intensity (usually set to
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What is the IUPAC name of the compound shown here?
(view attatchement)
**FIRST TIME YOU ANSWERE THIS WAS WRONG, please help with correct answer.
The answer you gave me before was 1,4-dimethylcyclobut-1-ene but is was WRONG .
This is what the paragraph also said next to the question
"Alkanes are called saturated hydrocarbons because each carbon atom has the maximum number of hydrogen atoms. In contrast, alkenes and alkynes are unsaturated because they contain double or triple bonds that reduce the number of hydrogen atoms in the compound.
When naming unsaturated hydrocarbons, a suffix reflects the type of multiple bond in the compound: ene is used for alkenes (double bond), and yne is used for alkynes (triple bond). For cyclic alkenes and alkynes, the ring is numbered such that the double or triple bond is between the first two carbon atoms. For straight-chain molecules, the numbering starts at one end of the chain, so the location of the double or triple bond must be…
Name the alkyl group as if the dashed line were where it was connect to the rest of the molecule, state whether it is primary, secondary, or tertiary.
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Chapter 16 Solutions
Organic Chemistry: Principles And Mechanisms
Ch. 16 - Prob. 16.1PCh. 16 - Prob. 16.2PCh. 16 - Prob. 16.3PCh. 16 - Prob. 16.4PCh. 16 - Prob. 16.5PCh. 16 - Prob. 16.6PCh. 16 - Prob. 16.7PCh. 16 - Prob. 16.8PCh. 16 - Prob. 16.9PCh. 16 - Prob. 16.10P
Ch. 16 - Prob. 16.11PCh. 16 - Prob. 16.12PCh. 16 - Prob. 16.13PCh. 16 - Prob. 16.14PCh. 16 - Prob. 16.15PCh. 16 - Prob. 16.16PCh. 16 - Prob. 16.17PCh. 16 - Prob. 16.18PCh. 16 - Prob. 16.19PCh. 16 - Prob. 16.20PCh. 16 - Prob. 16.21PCh. 16 - Prob. 16.22PCh. 16 - Prob. 16.23PCh. 16 - Prob. 16.24PCh. 16 - Prob. 16.25PCh. 16 - Prob. 16.26PCh. 16 - Prob. 16.27PCh. 16 - Prob. 16.28PCh. 16 - Prob. 16.29PCh. 16 - Prob. 16.30PCh. 16 - Prob. 16.31PCh. 16 - Prob. 16.32PCh. 16 - Prob. 16.33PCh. 16 - Prob. 16.34PCh. 16 - Prob. 16.35PCh. 16 - Prob. 16.36PCh. 16 - Prob. 16.37PCh. 16 - Prob. 16.38PCh. 16 - Prob. 16.39PCh. 16 - Prob. 16.40PCh. 16 - Prob. 16.41PCh. 16 - Prob. 16.42PCh. 16 - Prob. 16.43PCh. 16 - Prob. 16.44PCh. 16 - Prob. 16.45PCh. 16 - Prob. 16.46PCh. 16 - Prob. 16.47PCh. 16 - Prob. 16.48PCh. 16 - Prob. 16.49PCh. 16 - Prob. 16.50PCh. 16 - Prob. 16.51PCh. 16 - Prob. 16.52PCh. 16 - Prob. 16.53PCh. 16 - Prob. 16.54PCh. 16 - Prob. 16.55PCh. 16 - Prob. 16.56PCh. 16 - Prob. 16.57PCh. 16 - Prob. 16.58PCh. 16 - Prob. 16.59PCh. 16 - Prob. 16.60PCh. 16 - Prob. 16.61PCh. 16 - Prob. 16.62PCh. 16 - Prob. 16.63PCh. 16 - Prob. 16.64PCh. 16 - Prob. 16.65PCh. 16 - Prob. 16.66PCh. 16 - Prob. 16.67PCh. 16 - Prob. 16.68PCh. 16 - Prob. 16.69PCh. 16 - Prob. 16.70PCh. 16 - Prob. 16.71PCh. 16 - Prob. 16.72PCh. 16 - Prob. 16.73PCh. 16 - Prob. 16.74PCh. 16 - Prob. 16.75PCh. 16 - Prob. 16.76PCh. 16 - Prob. 16.77PCh. 16 - Prob. 16.78PCh. 16 - Prob. 16.79PCh. 16 - Prob. 16.80PCh. 16 - Prob. 16.81PCh. 16 - Prob. 16.82PCh. 16 - Prob. 16.83PCh. 16 - Prob. 16.84PCh. 16 - Prob. 16.85PCh. 16 - Prob. 16.86PCh. 16 - Prob. 16.87PCh. 16 - Prob. 16.88PCh. 16 - Prob. 16.89PCh. 16 - Prob. 16.1YTCh. 16 - Prob. 16.2YTCh. 16 - Prob. 16.3YTCh. 16 - Prob. 16.4YTCh. 16 - Prob. 16.5YTCh. 16 - Prob. 16.6YTCh. 16 - Prob. 16.7YTCh. 16 - Prob. 16.8YTCh. 16 - Prob. 16.9YTCh. 16 - Prob. 16.10YTCh. 16 - Prob. 16.11YTCh. 16 - Prob. 16.12YTCh. 16 - Prob. 16.13YTCh. 16 - Prob. 16.14YTCh. 16 - Prob. 16.15YTCh. 16 - Prob. 16.16YTCh. 16 - Prob. 16.17YTCh. 16 - Prob. 16.18YTCh. 16 - Prob. 16.19YTCh. 16 - Prob. 16.20YTCh. 16 - Prob. 16.21YTCh. 16 - Prob. 16.22YTCh. 16 - Prob. 16.23YTCh. 16 - Prob. 16.24YTCh. 16 - Prob. 16.25YTCh. 16 - Prob. 16.26YTCh. 16 - Prob. 16.27YTCh. 16 - Prob. 16.28YTCh. 16 - Prob. 16.29YTCh. 16 - Prob. 16.30YTCh. 16 - Prob. 16.31YTCh. 16 - Prob. 16.32YTCh. 16 - Prob. 16.33YTCh. 16 - Prob. 16.34YT
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- Examine the cycloalkane above. There are two carbons that make up the front of the ring, and three carbons that make up the back of the ring. Now, if you take the above compound, and place a METHYL group on the carbon in the frontmost right position of the ring, you will have a cycloalkane with three groups, all on different neighboring carbons. The correct complete IUPAC name for this NEW compound would be (including numbers when required): cyclopentanearrow_forwardView the first compound name provided in Table 6. Follow the steps below and draw each part of the structure on a piece of paper. Determine the number of carbons present in the compound based on the base name. Draw the carbon chain and include any double or triple bonds if indicated in the suffix of the base name. Number each carbon. The carbons can be numbered from left to right or right to left. Draw any substituents on the corresponding carbon atom for which is indicated in the name. Refer to Figures 3 and 4 in the background for a visual representation of numbered carbons with corresponding substituents. Check that each carbon atom has a total of 4 bonds.arrow_forwardNow, if you take the above compound, and place a METHYL group on the carbon in the BACK LEFT position of the ring, you will have a cycloalkane with three groups, all on different neighboring carbons. The correct complete IUPAC name for this NEW compound would bearrow_forward
- Part A Alkanes are molecules that contain only carbon and hydrogen and have only single bonds. Straight-chain What is the molecular formula for the alkane shown in the model? alkanes have all the carbon atoms connected in a Express your answer as a chemical formula. row, branched-chain alkanes have branching connections of carbon atoms, and cycloalkanes contain rings of carbon atoms. • View Available Hint(s) ? CH, CH, DA chemical reaction does not occur for this question. Submit Previous Answers X Incorrect; Try Again; 5 attempts remaining Figure View Available Hint(s) Pentanearrow_forwardPlease answer completely will give rating surely All questions answers neededarrow_forwardIs the straight chain alkane with molecular formula C5H12 expected to be a solid, a liquid or a gas at room temperature and pressure. Please type answer note write by hend.arrow_forward
- What is the name of the IUPAC compound shown here? (see attatchement) First time you guys answered it was wrong, trying again. **** The answer 3-methylbut-1-ene you gave yesterday was WRONG . Please help with correct answer. This is what the question has as well: Alkanes are called saturated hydrocarbons because each carbon atom has the maximum number of hydrogen atoms. In contrast, alkenes and alkynes are unsaturated because they contain double or triple bonds that reduce the number of hydrogen atoms in the compound. When naming unsaturated hydrocarbons, a suffix reflects the type of multiple bond in the compound: ene is used for alkenes (double bond), and yne is used for alkynes (triple bond). For cyclic alkenes and alkynes, the ring is numbered such that the double or triple bond is between the first two carbon atoms. For straight-chain molecules, the numbering starts at one end of the chain, so the location of the double or triple bond must be specified in the name.arrow_forwardThere are carbons in the longest continuous chain of carbons in the molecule below.arrow_forwardAnswer this question:How to draw the line bond formula or lewis structure of a methyl ketone with the chemical formula C6H5C3H5O? (also taking into consideration the solubility test and chemical test results provided below) Based on the results of the solubility tests the compound is insoluble in water, 10% NaOH and 10% HCl but soluble in concentrated H2SO4. The functional group/class is identified to be Methyl Ketone, based on the results of the chemical tests on Table 2. CHEMICAL TEST OBSERVATIONS +(compound tested positive for the chemical reaction)/ otherwise (-) Molisch test turbid colorless solution - 2,4-DNP test formation of orange-yellow precipitates + Tollen’s test turbid colorless solution - Ninhydrin test clear pale-yellow solution - iodoform test clear pale-yellow solution +arrow_forward
- Solve all pleasearrow_forwardAnswer with explanation Asap identify the functional groupsarrow_forwardMembers of this series are not as chemcially reactive as the other hydrocarbons, and each has a higher molecular weight as a result of an additional -CH_2_. (That's suppose to be a small two) A) hydrocarbon B) polymer C) alcohol D) paraffin Can you help me understand which one it is please?!arrow_forward
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