Basic Chemistry
6th Edition
ISBN: 9780134878119
Author: Timberlake, Karen C. , William
Publisher: Pearson,
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Question
Chapter 15, Problem 75CP
(a)
Interpretation Introduction
Interpretation: Determine the oxidation number of Br in Br2
Concept Introduction:
The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
(b)
Interpretation Introduction
Interpretation: Determine the oxidation number of Br in HBrO2
Concept Introduction: The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
(c)
Interpretation Introduction
Interpretation: Determine the oxidation number of Br in BrO3-
Concept Introduction: The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
(d)
Interpretation Introduction
Interpretation: Determine the oxidation number of Br in NaBrO4
Concept Introduction: The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
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(7.12) A technician plates a faucet with 0.86
g Cr metal by electrolysis of aqueous
Cr2(SO4)3. If 12.5 min is allowed for the
plating, what current is needed?
Molar mass of Cr: 51.996 g/mol
Analysis/Strategy: mass of Cr ® mol Cr
mol e¯ (or Faraday) ® coulombs ®
amperes
Reduction half-reaction of chromium
solution to chromium metal: Cr*
,+3,
(aq)
e¯ ® Cr(s)
+
chromium solution, Cr2(SO4)3, has the
ions: [Cr*3 s04-²]
Answer: The current needed is
ampere. (2 sig fig)
4.
5.
OH
+ HCI
I
strong acid
catalyst
Fill in the blanks:
(7.13) Using a current of 4.75 A, how many
minutes does it take to plate a sculpture
with 1.50 g of Cu from a CuS04 solution?
(Cu 63.546 g/mol)
Analysis/Strategy: mass of Cu ® mol Cu
® mol e" (or Faraday) ® coulombs ®
time in minutes (given current
in
amperes)
Reduction half-reaction of copper
solution to copper metal: Cu*2(aq) ·
+
e¯ ® Cu(s)
copper solution, CUSO4, has the ions:
[Cu*2_SOq]
Answer: The time needed to plate out a
sculpture is
minutes. (3
sig fig)
Chapter 15 Solutions
Basic Chemistry
Ch. 15.1 - Identify each of the following as an oxidation or...Ch. 15.1 - Identify each of the following as an oxidation or...Ch. 15.1 - Prob. 3PPCh. 15.1 - Prob. 4PPCh. 15.1 - Prob. 5PPCh. 15.1 - Prob. 6PPCh. 15.1 - Prob. 7PPCh. 15.1 - Prob. 8PPCh. 15.1 - Prob. 9PPCh. 15.1 - Prob. 10PP
Ch. 15.1 - Prob. 11PPCh. 15.1 - Prob. 12PPCh. 15.1 - What is the oxidation number of the specified...Ch. 15.1 - What is the oxidation number of the specified...Ch. 15.1 - Prob. 15PPCh. 15.1 - Prob. 16PPCh. 15.1 - Prob. 17PPCh. 15.1 - Prob. 18PPCh. 15.1 - Prob. 19PPCh. 15.1 - Prob. 20PPCh. 15.2 - Balance each of the following half-reactions in...Ch. 15.2 - Prob. 22PPCh. 15.2 - Prob. 23PPCh. 15.2 - Use the half-reaction method to balance each of...Ch. 15.2 - Use the half-reaction method to balance each of...Ch. 15.2 - Use the half-reaction method to balance each of...Ch. 15.3 - Use the activity series in Table 15.3 to predict...Ch. 15.3 - Use the activity series in Table 15.3 to predict...Ch. 15.3 - Prob. 29PPCh. 15.3 - Prob. 30PPCh. 15.3 - Prob. 31PPCh. 15.3 - Prob. 32PPCh. 15.3 - The following half-reaction takes place in a...Ch. 15.3 - The following half-reaction takes place in a...Ch. 15.3 - The following half-reaction takes place in a...Ch. 15.3 - Prob. 36PPCh. 15.4 - What we call "tin cans" are really iron cans...Ch. 15.4 - Prob. 38PPCh. 15.4 - Prob. 39PPCh. 15.4 - Prob. 40PPCh. 15.4 - Prob. 41PPCh. 15.4 - Prob. 42PPCh. 15 - Prob. 43UTCCh. 15 - Prob. 44UTCCh. 15 - Prob. 45UTCCh. 15 - Prob. 46UTCCh. 15 - The chapter sections to review are shown in...Ch. 15 - The chapter sections to review are shown in...Ch. 15 - The chapter sections to review are shown in...Ch. 15 - Prob. 50UTCCh. 15 - Prob. 51UTCCh. 15 - Prob. 52UTCCh. 15 - The chapter sections to review are shown in...Ch. 15 - The chapter sections to review are shown in...Ch. 15 - Which of the following are oxidation-reduction...Ch. 15 - Which of the following are oxidation-reduction...Ch. 15 - In the mitochondria of human cells, energy is...Ch. 15 - Prob. 58APPCh. 15 - Prob. 59APPCh. 15 - Prob. 60APPCh. 15 - Prob. 61APPCh. 15 - Prob. 62APPCh. 15 - Prob. 63APPCh. 15 - Write the balanced half-reactions and a balanced...Ch. 15 - Prob. 65APPCh. 15 - Use the activity series in Table 15.3 to predict...Ch. 15 - Prob. 67APPCh. 15 - Prob. 68APPCh. 15 - Prob. 69APPCh. 15 - Prob. 70APPCh. 15 - Prob. 71APPCh. 15 - In an acidic dry-cell battery, the following...Ch. 15 - Steel bolts made for sailboats are coated with...Ch. 15 - Copper cooking pans are stainless steel pans...Ch. 15 - Prob. 75CPCh. 15 - Prob. 76CPCh. 15 - Prob. 77CPCh. 15 - The following problems are related to the topics...Ch. 15 - The following problems are related to the topics...Ch. 15 - The following problems are related to the topics...Ch. 15 - Prob. 81CPCh. 15 - Prob. 82CPCh. 15 - Prob. 83CPCh. 15 - Prob. 84CPCh. 15 - Prob. 85CPCh. 15 - Prob. 86CPCh. 15 - Prob. 87CPCh. 15 - Prob. 88CP
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- Given the following redox pair, identify the reducing agent: NAD+/ NADH (-0.32) 2e- 202H2O (0.82) 2e- A. NADH B. NAD+ C. O₂ D. H₂Oarrow_forward5) What is the pH of a 0.250 M HF solution? The Ka of HF is 3.5 X 10-4. (2.03) HF (aq) + H2O (1) + H,0* (aq) +F ° (aq)arrow_forwardFill in the blanks: (7.14) In the electrolysis of CUSO4, how much copper is plated out on the cathode by a current of a 0.75A in 10 minutes? (Cu 63.546 g/mol) Analysis/Strategy: ampere & time coulombs ® mol e¯ (or Faraday) ® mol Cu (R mass of Cu Reduction half-reaction of copper solution to copper metal: Cu*²(aq) + e¯ ® Cu(s) copper solution, CUSO4, has the ions: [Cu*2 SOq] Answer: The mass of copper plated out is g Cu. (3 sig fig)arrow_forward
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