Organic Chemistry: Principles and Mechanisms (Second Edition)
Organic Chemistry: Principles and Mechanisms (Second Edition)
2nd Edition
ISBN: 9780393663556
Author: Joel Karty
Publisher: W. W. Norton & Company
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Chapter 15, Problem 15.39P
Interpretation Introduction

Interpretation:

In Section 6.2d, we saw that pKa of an acid is equal to the pH of the solution at which half the acid has dissociated into its conjugate base. UV–vis spectroscopy can be used to measure the relative concentrations involved if the acid or conjugate base absorbs UV–vis light. With this in mind, suppose that a particular acid has λmax of 312 nm. The given figure shows the absorbance at that wavelength as a function of pH. pKa of the acid is to be determined.

Concept introduction:

If the given absorbance corresponds to the concentration of acid present, half the absorbance shows the acid which is dissociated in the equal concentration of its conjugate base. pKa of an acid is equal to the pH of the solution at which half the acid has dissociated into its conjugate base.

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In Section 6.2d, we saw that the pK, of an acid is equal to the pH of the solution at which half the acid has dissociated into its conjugate base. UV-vis spectroscopy can be used to measure the relative concentrations involved if the acid or conjugate base absorbs UV-vis light. With this in mind, suppose that a particular acid has a Amax of 312 nm. The figure here shows the absorbance at that wavelength as a function of pH. What is the pk, of the acid? 3 4 6 7 8 10 11 12 pH Absorbance at 312 nm
2. You add 10.00 ml of a 0.630 M methyl red solution to a 100.00 ml volumetric flask. You then add small volumes of sodium acetate and acetic acid solutions to adjust the pH, and then fill the 100 mL volumetric flask to the mark with deionized water. You then make a spectroscopic measurement and obtain absorbance values of 0.253 at 520 nm and 0.079 at 420 nm. What is the concentration of [HIn] in the solution. Remember to use M;V1 = M2V2 as the first step in the calculation process. Hint: see eq. 6 in the lab manual A$20, = 0.367 A520, = 0.010 A420, - 0.012 A420, = 0.275 O 4.30 x 102 O 0.430 O 4.18 x 102 O 0.418
What do you understand by estimation? Justify that using higher values of Cl gives better estimations.

Chapter 15 Solutions

Organic Chemistry: Principles and Mechanisms (Second Edition)

Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.24PCh. 15 - Prob. 15.25PCh. 15 - Prob. 15.26PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32PCh. 15 - Prob. 15.33PCh. 15 - Prob. 15.34PCh. 15 - Prob. 15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. 15.38PCh. 15 - Prob. 15.39PCh. 15 - Prob. 15.40PCh. 15 - Prob. 15.41PCh. 15 - Prob. 15.42PCh. 15 - Prob. 15.43PCh. 15 - Prob. 15.44PCh. 15 - Prob. 15.45PCh. 15 - Prob. 15.46PCh. 15 - Prob. 15.47PCh. 15 - Prob. 15.48PCh. 15 - Prob. 15.49PCh. 15 - Prob. 15.50PCh. 15 - Prob. 15.51PCh. 15 - Prob. 15.52PCh. 15 - Prob. 15.53PCh. 15 - Prob. 15.54PCh. 15 - Prob. 15.55PCh. 15 - Prob. 15.56PCh. 15 - Prob. 15.57PCh. 15 - Prob. 15.58PCh. 15 - Prob. 15.59PCh. 15 - Prob. 15.60PCh. 15 - Prob. 15.61PCh. 15 - Prob. 15.62PCh. 15 - Prob. 15.63PCh. 15 - Prob. 15.64PCh. 15 - Prob. 15.65PCh. 15 - Prob. 15.66PCh. 15 - Prob. 15.67PCh. 15 - Prob. 15.68PCh. 15 - Prob. 15.1YTCh. 15 - Prob. 15.2YTCh. 15 - Prob. 15.3YTCh. 15 - Prob. 15.4YTCh. 15 - Prob. 15.5YTCh. 15 - Prob. 15.6YTCh. 15 - Prob. 15.7YTCh. 15 - Prob. 15.8YTCh. 15 - Prob. 15.9YTCh. 15 - Prob. 15.10YTCh. 15 - Prob. 15.11YTCh. 15 - Prob. 15.12YTCh. 15 - Prob. 15.13YTCh. 15 - Prob. 15.14YTCh. 15 - Prob. 15.15YTCh. 15 - Prob. 15.16YTCh. 15 - Prob. 15.17YTCh. 15 - Prob. 15.18YTCh. 15 - Prob. 15.19YTCh. 15 - Prob. 15.20YTCh. 15 - Prob. 15.21YTCh. 15 - Prob. 15.22YTCh. 15 - Prob. 15.23YTCh. 15 - Prob. 15.24YTCh. 15 - Prob. 15.25YTCh. 15 - Prob. 15.26YTCh. 15 - Prob. 15.27YTCh. 15 - Prob. 15.28YTCh. 15 - Prob. 15.29YTCh. 15 - Prob. 15.30YT
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