Chemistry: An Atoms-Focused Approach
14th Edition
ISBN: 9780393912340
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster
Publisher: W. W. Norton & Company
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At 25 oC, Ammonia is a weak base that reacts with water according to this equation: NH3(aq) + H2O(aq) ⇌ NH4+(aq) + OH−(aq)
Briefly explain how the equilibrium will shift (to get back to equilibrium) if the following perturbations are made to the system:
(a) Addition of HCl
(b) Addition of NaOH
(c) Addition of NH4Cl
Water ionizes by the equation
H₂O(1)
H+ (aq) + OH- (aq)
The extent of the reaction is small in pure water and dilute aqueous solutions.
This reaction creates the following relationship between [H+] and [OH-]:
Kw = [H+][OH-]
Keep in mind that, like all equilibrium constants, the value of Kw changes with
temperature.
Acetic acid is a weak acid, meaning it does not fully dissociate in water. Instead, there is an equilibrium between the dissolved but undissociated molecule and the component ions:
HOAc (aq) + H2O (l) ⇌ H3O+ (aq) + OAc– (aq)OAc– is an abbreviation for the acetate ion, CH3COO–, and H3O+ is the hydronium ion (lone protons, H+ (aq), do not exist!).
(d) When starting with completely un-dissociated acetic acid, is it accurate to assume that [HOAc]0 = [HOAc]eq? Why or why not?
(e) A highly concentrated acetic acid solution contains 15.0M acetic acid at equilibrium. What are the equilibrium concentrations of the hydronium and acetate ions in this solution?
(f) Creating the concentrated acetic acid solution by dissolving liquid HOAc in water raises the temperature of the water by about 5°C from room temperature. At 50°C, do you expect the solution to contain more or less acetate ion OAc– than what you calculated in (c)? Why?
Chapter 15 Solutions
Chemistry: An Atoms-Focused Approach
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- Kafor acetic acid (HC2H3O2) at 25°C is 1.754105 . At 50°C, Kais 1.633105 . Assuming that H° and S° are not affected by a change in temperature, calculate S° for the ionization of acetic acid.arrow_forwardMost naturally occurring acids are weak acids. Lactic acid is one example. CH3CH(OH)CO2H(s)+H2O(l)H3O+(aq)+CH3CH(OH)CO2(aq) If you place some lactic acid in water, it will ionize to a small extent, and an equilibrium will be established. Suggest some experiments to prow that this is a weak acid and that the establishment of equilibrium is a reversible process.arrow_forwardProve that Ka3 Kb1 = Kw for phosphoric acid, H3PO4, by adding the chemical equilibrium expressions that corresponds to the third ionization step of the acid in water with the first of the three successive steps of the reaction of phosphate ion, PO43, with water.arrow_forward
- Table 13-4 lists the stepwise Ka values for some polyprotic acids. What is the difference between a monoprotic acid, a diprotic acid, and a triprotic acid? Most polyprotic acids are weak acids; the major exception is H2SO4. To solve for the pH of a solution of H2SO4, you must generally solve a strong acid problem as well as a weak acid problem. Explain. Write out the reactions that refer to Ka1 and Ka2 for H2SO4. For H3PO4, Ka1 = 7.5 103, Ka2 = 6.2 108, and Ka3= 4.8 1013. Write out the reactions that refer to the Ka1, Ka2and Ka3equilibrium constants. What are the three acids in a solution of H3PO4? Which acid is strongest? What are the three conjugate bases in a solution of H3PO4? Which conjugate base is strongest? Summarize the strategy for calculating the pH of a polyprotic acid in water.arrow_forwardFor each of the following reactions, predict whether the equilibrium lies predominantly to the left or to the right. Explain your predictions briefly. (a) NH4+(aq) + Br(aq) NH3(aq) + HBr(aq) (b) HPO42(aq) + CH3CO2(aq) PO43(aq) + CH3CO2H(aq) (c)[Fe(H2O)6]3+(aq) + HCO3(aq) [Fe(H2O)5(OH)]2+(aq) + H2CO3(aq)arrow_forwardWrite the chemical equation and the expression for the equilibrium constant, and calculate Kb for the reaction of each of the following ions as a base. (a) sulfate ion (b) citrate ionarrow_forward
- Ionization of the first proton from H2SO4 is complete (H2SO4 is a strong acid); the acid-ionization constant for the second proton is 1.1 102. a What would be the approximate hydronium-ion concentration in 0.100 M H2SO4 if ionization of the second proton were ignored? b The ionization of the second proton must be considered for a more exact answer, however. Calculate the hydronium-ion concentration in 0.100 M H2SO4, accounting for the ionization of both protons.arrow_forwardAcetic acid is a weak acid, meaning it does not fully dissociate in water. Instead, there is an equilibrium between the dissolved but undissociated molecule and the component ions: HOAc (aq) + H2O (l) ⇌ H3O+ (aq) + OAc– (aq)OAc– is an abbreviation for the acetate ion, CH3COO–, and H3O+ is the hydronium ion (lone protons, H+ (aq), do not exist!). (a) Write the equilibrium constant expression for the dissociation of acetic acid. (b) Vinegar sold commercially is typically 0.8 − 1.0 M acetic acid. A 1.00 M solution of acetic acid is measured by its pH to have an equilibrium concentration of 4.19×10−3 M for both acetate ions and hydronium ions at room temperature. Assuming [HOAc]0 = 1.00M, what is the equilibrium concentration of undissociated acetic acid [HOAc]eq to the correct number of significant figures? (c) What is the value of the equilibrium constant Keq for the dissociation according to the concentrations from part (b)? (d) When starting with completely un-dissociated…arrow_forwardThe value of K, for acetylsalicylic acid (aspirin), HC,H,O4, is 3.00×10-4 Write the equation for the reaction that goes with this equilibrium constant. (Use H3O+ instead of H*.) + +arrow_forward
- What is the approximate K for the following acid/base reaction? H25 (aq) +F (aq) ++ HF (aq) +HS (aq) ACID BASE HCI C H2SO4 HNO3 H30 (aq) HSO H3PO4 HSO NO3 H2O so, H,PO, F HF CH3COOH H,CO3 H,S H,PO, NH, CH;COO HCO, HS HPO, NH, CO PO OH HCO HPO. 1,0 OH H, CH CH, OA unable to determine OB. K.<1 Base strength increasing Acid strength increasingarrow_forwardFormic acid, HCOOH, ionizes in water according to the following equation. The equilibrium constant is K=1.8 × 10-4. HCOOH(aq) + H,O(D) — HCOO¯(aq) + H₂O + (aq) Calculate the equilibrium concentration of H3O+ in a 0.985 Msolution. Marrow_forwardWrite the equilibrium expression for the following reaction. HClO4 (aq) -> H+ (aq) + ClO4- (aq)arrow_forward
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