Glencoe Chemistry: Matter and Change, Student Edition
Glencoe Chemistry: Matter and Change, Student Edition
1st Edition
ISBN: 9780076774609
Author: McGraw-Hill Education
Publisher: MCGRAW-HILL HIGHER EDUCATION
Question
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Chapter 14.2, Problem 26PP
Interpretation Introduction

Interpretation:

Amount of HCl in solution is to be calculated.

Concept introduction:

Dilution is the process of decreasing the concentration of a stock solution by adding more solvent to the solution. The solvent added is usually the universal solvent, known as water. The more solvent you add, the more diluted the solution will get.

In dilution, the amount of solute does not change, the number of moles is the same before and after dilution.

If subscript "1" represents initial and "2" represents the final values of the quantities involved, we have:

n1 = M1× V1    and   n2= M2× V2

Here, molarity is used as a unit of concentration and n1 and n2 are the number of moles before and after dilution respectively.

n1  = n2   and thus,

The equation for dilution is

M1V1= M2V2Stock solution = Diluted solution

Where

M1 = molarity of the stock solution

V1 = volume of stock solution

M2 = molarity of the diluted solution

V2 = volume of diluted solution

Expert Solution & Answer
Check Mark

Answer to Problem 26PP

91.15 gmHCl is present in the solution.

As we know, in dilution, the amount of solute does not change, the number of moles is the same before and after dilution.

Here, the equation is requiredn1 = M1V1

M1 = molarity of the stock solution V1 = volume of stock solution

Data Given: M1 = molarity of the stock solution = 5.0 M

V1 = volume of stock HCl solution = 0.5 L

n1 = M1V1

= 5.0 M × 0.5 L = 2.5 mol Number of moles of HCl =MassofHClMolecularweightofHCl

Calculate the mass of HCl from above equation:

Mass of HCl = Number of moles of HCl × Molecular weight of HCl                    = 2.5 mol × 36.46 gm/mol                    = 91.15 gm

Thus, 91.15 gmHCl is present in the solution.

Explanation of Solution

As we know, in dilution, the amount of solute does not change, the number of moles is the same before and after dilution.

Here, the equation is requiredn1 = M1V1

M1 = molarity of the stock solution V1 = volume of stock solution

Data Given: M1 = molarity of the stock solution = 5.0 M

V1 = volume of stock HCl solution = 0.5 L

n1 = M1V1

= 5.0 M × 0.5 L = 2.5 mol Number of moles of HCl =MassofHClMolecularweightofHCl

Calculate the mass of HCl from above equation:

Mass of HCl = Number of moles of HCl × Molecular weight of HCl                    = 2.5 mol × 36.46 gm/mol                    = 91.15 gm

Thus, 91.15 gmHCl is present in the solution.

Chapter 14 Solutions

Glencoe Chemistry: Matter and Change, Student Edition

Ch. 14.2 - Prob. 11PPCh. 14.2 - Prob. 12PPCh. 14.2 - Prob. 13PPCh. 14.2 - Prob. 14PPCh. 14.2 - Prob. 15PPCh. 14.2 - Prob. 16PPCh. 14.2 - Prob. 17PPCh. 14.2 - Prob. 18PPCh. 14.2 - Prob. 19PPCh. 14.2 - Prob. 20PPCh. 14.2 - Prob. 21PPCh. 14.2 - Prob. 22PPCh. 14.2 - Prob. 23PPCh. 14.2 - Prob. 24PPCh. 14.2 - Prob. 25PPCh. 14.2 - Prob. 26PPCh. 14.2 - Prob. 27PPCh. 14.2 - Prob. 28PPCh. 14.2 - Prob. 29PPCh. 14.2 - Prob. 30PPCh. 14.2 - Prob. 31SSCCh. 14.2 - Prob. 32SSCCh. 14.2 - Prob. 33SSCCh. 14.2 - Prob. 34SSCCh. 14.2 - Prob. 35SSCCh. 14.3 - Prob. 36PPCh. 14.3 - Prob. 37PPCh. 14.3 - Prob. 38PPCh. 14.3 - Prob. 39SSCCh. 14.3 - Prob. 40SSCCh. 14.3 - Prob. 41SSCCh. 14.3 - Prob. 42SSCCh. 14.3 - Prob. 43SSCCh. 14.3 - Prob. 44SSCCh. 14.4 - Prob. 45PPCh. 14.4 - Prob. 46PPCh. 14.4 - Prob. 47PPCh. 14.4 - Prob. 48SSCCh. 14.4 - Prob. 49SSCCh. 14.4 - Prob. 50SSCCh. 14.4 - Prob. 51SSCCh. 14.4 - Prob. 52SSCCh. 14.4 - Prob. 53SSCCh. 14 - Prob. 54ACh. 14 - What is the difference between a solute and a...Ch. 14 - Prob. 56ACh. 14 - Prob. 57ACh. 14 - Prob. 58ACh. 14 - Prob. 59ACh. 14 - Prob. 60ACh. 14 - Prob. 61ACh. 14 - Prob. 62ACh. 14 - Prob. 63ACh. 14 - Prob. 64ACh. 14 - How do 0.5M and 2.0M aqueous solutions of NaCl...Ch. 14 - Prob. 66ACh. 14 - Prob. 67ACh. 14 - Prob. 68ACh. 14 - Prob. 69ACh. 14 - Prob. 70ACh. 14 - Prob. 71ACh. 14 - Prob. 72ACh. 14 - Prob. 73ACh. 14 - How much CaCl2 , in grams, is needed to make 2.0 L...Ch. 14 - Stock solutions of HCl with various molarities are...Ch. 14 - Prob. 76ACh. 14 - Prob. 77ACh. 14 - Prob. 78ACh. 14 - If you dilute 20.0 mL of a 3.5M solution to...Ch. 14 - Prob. 80ACh. 14 - Prob. 81ACh. 14 - Prob. 82ACh. 14 - Prob. 83ACh. 14 - What is the mole fraction of H 2 S O 4 in a...Ch. 14 - Prob. 85ACh. 14 - Prob. 86ACh. 14 - Prob. 87ACh. 14 - Prob. 88ACh. 14 - Prob. 89ACh. 14 - Prob. 90ACh. 14 - Prob. 91ACh. 14 - Prob. 92ACh. 14 - Prob. 93ACh. 14 - Prob. 94ACh. 14 - Prob. 95ACh. 14 - Prob. 96ACh. 14 - Prob. 97ACh. 14 - Prob. 98ACh. 14 - Prob. 99ACh. 14 - In the lab, you dissolve 179 g of MgCl2 into1.00 L...Ch. 14 - Cooking A cook prepares a solution for boiling by...Ch. 14 - Prob. 102ACh. 14 - Ice Cream A rock salt (NaCl), ice, and water...Ch. 14 - Apply your knowledge of polarity and solubility...Ch. 14 - Prob. 105ACh. 14 - Which solute has the greatest effect on the...Ch. 14 - Study Table 14.4. Analyze solubility and...Ch. 14 - Prob. 108ACh. 14 - If you prepared a saturated aqueous solution of...Ch. 14 - How many grams of calcium nitrate (Ca(NO3)2)...Ch. 14 - Prob. 111ACh. 14 - Prob. 112ACh. 14 - Prob. 113ACh. 14 - Prob. 114ACh. 14 - Infer Dehydration occurs when more fluid is lost...Ch. 14 - Graph Table 14.10 shows solubility data that was...Ch. 14 - Design an Experiment You are given a sample of a...Ch. 14 - Compare Which of the following solutions has...Ch. 14 - Prob. 119ACh. 14 - Prob. 120ACh. 14 - Prob. 121ACh. 14 - Prob. 122ACh. 14 - Prob. 123ACh. 14 - Prob. 124ACh. 14 - Prob. 125ACh. 14 - Prob. 126ACh. 14 - Prob. 127ACh. 14 - Prob. 128ACh. 14 - Prob. 129ACh. 14 - Prob. 1STPCh. 14 - Prob. 2STPCh. 14 - Prob. 3STPCh. 14 - Prob. 4STPCh. 14 - Prob. 5STPCh. 14 - Prob. 6STPCh. 14 - Prob. 7STPCh. 14 - Prob. 8STPCh. 14 - Prob. 9STPCh. 14 - Prob. 10STPCh. 14 - Prob. 11STPCh. 14 - Prob. 12STPCh. 14 - Prob. 13STPCh. 14 - Prob. 14STPCh. 14 - Prob. 15STPCh. 14 - Prob. 16STPCh. 14 - Prob. 17STPCh. 14 - Prob. 18STPCh. 14 - Prob. 19STP
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