Chapter 14, Problem 90A

Interpretation Introduction

Interpretation:

The solubility of a gas is to be calculated.

Concept Introduction:

Solubility: Solubility can be expressed as the maximum amount of solute that can dissolve in a known amount of solvent at a given temperature and pressure.

Henry’s Law: The solubility of a gas in a liquid is directly proportional to the pressure of the gas above the liquid at a certain temperature.

Answer to Problem 90A

The solubility of gas when the pressure is reduced by 3.5 atm is 2.1 g/liter.

Explanation of Solution

Given information:

  $S_1=9.5\mathrm{gm}/litre$

  $P_1=4.5\mathrm{atm}$

  $\begin{array}{c}{P}_2=\left(4.5–3.5\right)atm\\ =1atm\end{array}$

The expression of Henry’s Law is $\frac{S_1}{P_1}=\frac{S_2}{P_2}$

The solubility of a gas is S₁at P₁pressure and S₂at pressure P₂.

As the pressure is reduced by 3.5 atm,

  $\begin{array}{c}\frac{S_1}{P_1}=\frac{S_2}{P_2}\\ S_2=\frac{S_1\times P_2}{P_1}\\ S_2=\frac{9.5g/litre\times 1atm}{4.5atm}=2.1g/litre\end{array}$

So, the solubility of the gas at 1 atm pressure is 2.1 g/liter.