Organic Chemistry (6th Edition)
Organic Chemistry (6th Edition)
6th Edition
ISBN: 9781260119107
Author: Janice Gorzynski Smith
Publisher: McGraw Hill Education
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Chapter 14, Problem 66P

The treatment of isoprene [ CH 2 = C ( CH 3 ) CH = CH 2 ] with one equivalent of mCPBA forms A as the major product. A gives a molecular ion at 84 in its mass spectrum, and peaks at 2850 3150 cm 1 in its IR spectrum. The 1H NMR spectrum of A is given below. What is the structure of A?

Chapter 14, Problem 66P, 16.65  The treatment of isoprene  with one equivalent of mCPBA forms  A as the major product. A

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The treatment of isoprene [CH2=C(CH3)CH=CH2] with one equivalent ofmCPBA forms A as the major product. A gives a molecular ion at 84 in itsmass spectrum, and peaks at 2850–3150 cm−1 in its IR spectrum. The 1HNMR spectrum of A is given below. What is the structure of A?
Identify products A and B from the given 1H NMR data. Treatment of acetone [(CH3)2C=O] with dilute aqueous base forms B. Compound B exhibits four singlets in its 1H NMR spectrum at 1.3 (6 H), 2.2 (3 H), 2.5 (2 H), and 3.8 (1H) ppm. What is the structure of B?
Identify products A and B from the given 1H NMR data. Treatment of CH2=CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A?
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IR Spectroscopy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=_TmevMf-Zgs;License: Standard YouTube License, CC-BY