Concept explainers
The treatment of isoprene
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Organic Chemistry (6th Edition)
- The treatment of (CH3)2C = CHCH2Br with H2O forms B (molecular formula C5H10O) as one of the products. Determine the structure of B from its H NMR and IR spectra.arrow_forwardAcid-catalyzed hydrolysis of HOCH2CH2C(CH3)2CN forms compound A (C6H10O2). A shows a strong peak in its IR spectrum at 1770 cm-1 and the following signals in its 1H NMR spectrum: 1.27 (singlet, 6 H), 2.12 (triplet, 2 H), and 4.26 (triplet, 2 H) ppm. Draw the structure for A and give a stepwise mechanism that accounts for its formation.arrow_forwardReaction of p-cresol with two equivalents of 2-methylprop-1-ene affords BHT, a preservative with molecular formula C15H24O. BHT gives the following 1H NMR spectral data: 1.4 (singlet, 18 H), 2.27 (singlet, 3 H), 5.0 (singlet, 1 H), and 7.0 (singlet, 2 H) ppm. What is the structure of BHT? Draw a stepwise mechanism illustrating how it is formed.arrow_forward
- Reaction of (CH3)3CCHO with (C6H5)3P=C(CH3)OCH3, followed by treatment with aqueous acid, affords R (C7H14O). R has a strong absorption in its IR spectrum at 1717 cm−1 and three singlets in its 1H NMR spectrum at 1.02 (9 H), 2.13 (3 H), and 2.33 (2 H) ppm. What is the structure of R? We will learn about this reaction in Chapter 18.arrow_forwardTreatment of benzoic acid (C6H5CO2H) with NaOH followed by 1-iodo-3-methylbutane forms H. H has a molecular ion at 192 and IR absorptions at 3064, 3035, 2960–2872, and 1721 cm-1. Propose a structure for H.arrow_forwardasaparrow_forward
- Treatment of compound E (molecular formula C4H8O2) with excess CH3CH2MgBr yields compound F (molecular formula C6H14O) after protonation with H2O. E shows a strong absorption in its IR spectrum at 1743 cm-1. F shows a strong IR absorption at 3600–3200 cm-1. The 1H NMR spectral data of E and F are given. What are the structures of E and F?Compound E signals at 1.2 (triplet, 3 H), 2.0 (singlet, 3 H), and 4.1 (quartet, 2 H) ppmCompound F signals at 0.9 (triplet, 6 H), 1.1 (singlet, 3 H), 1.5 (quartet, 4 H), and 1.55 (singlet, 1 H) ppmarrow_forwardReaction of (CH3)2CO with LiCCH followed by H2O gives compound X, which has a molecular ion in the mass spectrum at 84. It also has prominent absorptions in the IR spectrum at 3600-3200, 3303, 2938, and 2120 cm-1. The proton NMR shows a singlet at 1.53 (6H), a singlet at 2.37 (1H) and a singlet at 2.43 (1H). What is the structure for compound X?arrow_forwardTreatment of (CH3)2CHCH(OH)CH2CH3 with TsOH affords two products(M and N) with molecular formula C6H12. The 1H NMR spectra of M and Nare given below. Propose structures for M and N, and draw a mechanismto explain their formation.arrow_forward
- Reaction of 2-methylpropanoic acid [(CH3)2CHCO2H] with SOCl2 followed by 2-methylpropan-1-ol forms X. X has a molecular ion at 144 and IR absorptions at 2965, 2940, and 1739 cm-1. Propose a structure for X.arrow_forwardCembrene, C20H32, is a diterpenoid hydrocarbon isolated from pine resin. Cembrene has a UV absorption at 245 nm, but dihydrocembrene (C20H34), the product of hydrogenation with 1 equivalent of H2, has no UV absorption. On exhaustive hydrogenation, 4 equivalents of H2 react, and octahydrocembrene, C20H40, is produced. On ozonolysis of cembrene, followed by treatment of the ozonide with zinc, four carbonylcontaining products are obtained: Propose a structure for cembrene that is consistent with its formation from geranylgeranyl diphosphate.arrow_forwardShow how the synthetic scheme developed in Problem 23.67 can be modified to synthesize this triiodobenzoic acid X-ray contrast agent.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning