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Chapter 14 Solutions
Organic Chemistry (6th Edition)
- 3) Draw the ECSF structures of (CH3)3CO (tert-butoxide ion) and CH30º (methoxide ion). Why is (tert-butoxide a PN but methoxide a GN even though both have a full O? (As it turns out, both are SBs) Redraw (CH3)3coe (ECSF) Why PN? Redraw CH30S (ECSF) Why GN?arrow_forwardA B C D E 1. NaBH4 2. H3O+ 1. CH3MgBr 2. H3O+ 1. (CH3)2CuLi 2. H3O+ 1. CH3Li 2. H3O+ 1. (CH3CH2)2CuLi 2. H3O+arrow_forwardH3C- -Br + а. b. H3C CH3 2 CH3CH,NH2arrow_forward
- Set C. Some Relatively Easy Molecules (1) SF;CI (2) Chlorobenzene (3) 1,2-Dichlorobenzene (4) 1,3-Dichlorobenzene (5) 1,4-Dichlorobenzene (6) 1,3,5-Trichlorobenzene (7) 1,2,3-Trichlorobenzene (8) 1,2,4-Trichlorobenzene (9) trans-(CrCl,(H,O).J* (ignore H atoms) (10) (11) OPCI, (12) trans-Pt(NH,),Cl; (ignore H atoms) (13) cis-Pt(NH,),Cl, (ignore H atoms) (14) BICIF (15) What is the point group for each of the following substituted cyclo- butanes? Assume that C,H, itself has D symmetry and that replacing an H by X or Y changes no other structure parameters. (a) (d)arrow_forwarde) HC- EN NH 오 아 Br. ㅈ 1. (CH3)₂CHMgBr, ether 2. NH,C1, H,O Products Br. ㅁㅅ NH H H Harrow_forwardCircle 1: E1 or E2? KOt-Bu А. Е1 E2 Br H20 E1 E2 heat Br MeO С. Е1 E2 heat Br B.arrow_forward
- Consider 1– Bromo – 2– methylbutane. A. Looking down at the C1:C2 bond draw the Newman projection with the lowest energy B. looking down at the C1:C2 bond draw the Newman projection highest energyarrow_forwardDraw structures for the following: a. (2E,4E)-1-chloro-3-methyl-2,4-hexadiene c. (3Z,5Z)-4,5-dimethyl-3,5-nonadiene b. (3Z,5E)-4-methyl-3,5-nonadiene d. (3E,5E)-2,5-dibromo-3,5-octadienearrow_forwardDraw the compunds below. (2e,4z)-1-bromo-4-methylhexa-2,4-diene (2e,4z)-5-bromo-3-methylhexa-2,4-diene (2z,4e)-1-bromo-4-methylhexa-2,4-diene (2z,4e)-1-bromo-3-methylhexa-2,4-dienearrow_forward
- 5. Chairs and E2 b. a. Draw the line-bond structure of (1R, 2S,3S)-1-ethyl-2-iodo-3-isopropylcyclohexane. Draw both chair flips of (1R, 2S,3S)-1-ethyl-2-iodo-3-isopropylcyclohexane. Showing all calculations, determine which is the more stable conformation. C. Which chair flip is able to undergo E2 elimination? Justify your answer. d. Show the product of such an E2 elimination using NaOEt as base.arrow_forward1. Predict the correct product for this reaction. 2. Choose ALL correct representations of the product using Newman projection. A ? H B H H သက်လုံး တမျိုး … H H H D H. H H H. H H H H D₂ Pd H H D H H. • သာလိုး E H H H .H H H H D D H H H H H H H H. တ H H H. - ရွှေပိုး H H. H H H H H Harrow_forwardRevision-Chapter 10 – Reactions in aldehyde and ketones Complete the following reaction equation. a) CH=C 1) 0, H3C-HC CH, CH3 CH3 2) Zn/ H,0 b) PCC CH;Cl2 c) CI -CH3 AICI CH3 R CH2. d) H,0* KMno, H3C H3C *CH2arrow_forward
Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning