Chapter 13.6, Problem 2CYU

To determine

  $\text{P}\left(\text{even }\right)$ is to be estimated.

Answer to Problem 2CYU

In fraction form,

  $\text{P}\left(\text{even }\right)=\frac{1}{2}$

In percent form,

  $\text{P}\left(\text{even }\right)\text{=0}\text{.005\%}$

Explanation of Solution

Given:

The spinner is spun once which is shown below

  

Calculation:

There are $\text{10}$ total sections on spinner.

So the number of total outcomes becomes $\text{10}$ .

To find that how many of these $\text{10}$ sections contain even numbers,

The even terms occurred on the spinner are $\text{2,4,6,8,10}$

  $\text{5}$ Out of $\text{10}$ parts contain even terms.

The probability that the even terms are occurred after being spun once can be calculated by formula,< $=\frac{\text{Number of desired outcomes}}{\text{Number of total outcomes}}$

Substituting the values in above formula,

  $\begin{array}{l}\text{P}\left(\text{even }\right)\text{=}\frac{\text{5}}{\text{10}}\\ \text{P}\left(\text{even }\right)\text{=}\frac{\text{1}}{\text{2}}\end{array}$

Conclusion:

Hence, $\text{P}\left(\text{even }\right)\text{=}\frac{\text{1}}{\text{2}}$