Concept explainers
The probability of the same kind bar Luis and Granola receive.
Answer to Problem 24PPS
The probability of the same kind bar Luis and Granola receive is P (Pair ofgranola bars) =
Explanation of Solution
Given:
Cinnamon Apple granola bars:
PeanutApple granola bars:
Oatmeal raisin granola bars:
Calculation:
Fraction Form:
It is given the box has
So no matter if cinnamon, peanut or oatmeal raisin to get a pair, so pick 2 simultaneously. The probability of getting
P (Pair of Apple Cinnamon):
For this take the number of total of apple cinnamon and total number of granola bars.
P (First bar is Apple Cinnamon) =
Now remove the
P (Second bar is Apple Cinnamon) =
P (Pair of Apple Cinnamon) = P (First) * P (Second)
So the P (Pair of Apple Cinnamon)
P (Pair of peanut bars)
For this take the number of total of peanut bars and total number of granola bars.
P (First bar ispeanut bars) =
Now remove the
P (Second bar ispeanut bars) =
P (Pair of peanut bars) = P (First) * P (Second)
So the P (Pair of peanut bars)
P (Pair of Oatmeal Raisin):
For this take the number of total of Oatmeal Raisinand total number of granola bars.
P (First bar is Oatmeal Raisin) =
Now remove the
P (Second bar is Oatmeal Raisin) =
P (Pair of Oatmeal Raisin) = P (First) * P (Second)
So the P (Pair of Oatmeal Raisin)
Now, as there are
P (Pair of granola bars):
P (Pair ofgranola bars) = P (Apple cinnamon) + P (Peanut) + P (Oatmeal Raisin)
Conclusion:
Hence, P (Pair ofgranola bars)=
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