Chapter 13, Problem 4P

To determine

The corresponding values on the Celsius scale for the two temperatures given in $°F$

Answer to Problem 4P

Solution:

The highest natural air temperature on the Celsius scale is $57.8°C$ and the lowest natural air temperature is - $89.44°C$

.

Explanation of Solution

Given:

Temperature $1=136°F$

Temperature $2=-129°F$

Formula used:

$T(°C)=\frac{5}{9}[T(°F)-32]$

Calculation:

The formula to convert temperature from Fahrenheit scale to Celsius scale is

$T(°C)=\frac{5}{9}[T(°F)-32]$

Substituting the value of temperature 1,

$T(°C)=\frac{5}{9}[136-32]=57.8°C$

Substituting the value of temperature 2,

$T(°C)=\frac{5}{9}[-129-32]=-89.44°C$