BIOLOGY
BIOLOGY
12th Edition
ISBN: 9781260169614
Author: Raven
Publisher: RENT MCG
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Chapter 13, Problem 2A

As real genetic distance increases, the distance calculated by recombination frequency becomes an

a. overestimate due to multiple crossovers that cannot be scored.

b. underestimate due to multiple crossovers that cannot be scored.

c. underestimate due to multiple crossovers adding to recombination frequency.

d. overestimate due to multiple crossovers adding to recombination frequency.

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a. Which progeny are the parental types? How can you tell?b. Which progeny are the recombinants? How can you tell?c. Do the results of this test cross support linkage of the traits? What is the % recombination?
For single crossovers, the frequency of recombinant gametes is half the frequency of crossing over because a. a testcross between a homozygote and a heterozygote produces ½ heterozygous and ½ homozygous progeny.b. the frequency of recombination is always 50%.c. each crossover takes place between only two of the four chromatids of a homologous pair.d. crossovers take place in about 50% of meioses.
In letter B: If the map distance equals the number of recombinant/total of offspring, wouldn't it be 24/806 x 100? Wouldn't we add both recombinants? Can you explain letter C? I don't grasp that concept well. And since I'm using my question already, would you be able to answer D.  Thank you!
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genetic recombination strategies of bacteria CONJUGATION, TRANSDUCTION AND TRANSFORMATION; Author: Scientist Cindy;https://www.youtube.com/watch?v=_Va8FZJEl9A;License: Standard youtube license