Engineering Electromagnetics
9th Edition
ISBN: 9780078028151
Author: Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher: Mcgraw-hill Education,
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Question
Chapter 13, Problem 13.19P
To determine
(a)
The range of frequencies for which the guide operates in single mode.
To determine
(b)
The frequency range the guide will support both
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Students have asked these similar questions
What are em and he modes? How do they differ from te and tem modes? What is a single mode waveguide and why is it 0th order mode?
What does the TE mean? Why does one have a 10 as subscript and the other mn? What is a broad and short dimension and a rectangular waveguide?
A 2 V signal is incident to the interface from a 75 Ohm region propagating to a 50 Ohm impedance region. What is the reflection coefficient? What is value of the incident, reflected and transmitted wave? What voltage would you measure on either side of the interface right after the signal goes through the interface.
For the interface, I'm a little confused. I used a voltage divider and got V_transmitted = 0.8 and V_incident = 1.2. But shouldn't they be the same?
Chapter 13 Solutions
Engineering Electromagnetics
Ch. 13 - The conductors of a coaxial transmission line are...Ch. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Find R, L, C, and G for a two-wire transmission...Ch. 13 - Prob. 13.5PCh. 13 - Consider an air-filled coaxial transmission line...Ch. 13 - Pertinent dimensions for the transmission line...Ch. 13 - A transmission line constructed from perfect...Ch. 13 - Prob. 13.9PCh. 13 - Two microstrip lines are fabricated end-to-end on...
Ch. 13 - Prob. 13.11PCh. 13 - Prob. 13.12PCh. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - For the guide of Problem 13.14, and at the 32 GHz...Ch. 13 - Prob. 13.16PCh. 13 - A parallel-plate guide is partially filled with...Ch. 13 - Prob. 13.18PCh. 13 - Prob. 13.19PCh. 13 - Two rectangular waveguides are joined end-to-end....Ch. 13 - Prob. 13.21PCh. 13 - Consider the TE11 mode in a rectangular guide...Ch. 13 - Prob. 13.23PCh. 13 - Prob. 13.24PCh. 13 - Prob. 13.25PCh. 13 - Prob. 13.26PCh. 13 - Prob. 13.27PCh. 13 - Prob. 13.28PCh. 13 - An asymmetric slab waveguide is shown in Figure...Ch. 13 - A step index optical fiber is known to be single...Ch. 13 - Prob. 13.31PCh. 13 - Prob. 13.32P
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Similar questions
- What is field pattern in a. Rectangular waveguide?b. TE mode in rectangular waveguide?c. TM mode in rectangular waveguide?arrow_forwardThis subject is antenna and wave propagation of ece pls solve neatly and faster thanksarrow_forwardA rectangular waveguide has dimensions a = 6 cm and b = 4 cm.a) Over what range of frequencies will the guide operate single mode?b) Over what frequency range will the guide support both TE10 and TE01modes and no others?arrow_forward
- 9 What is field pattern in m.)TE mode in rectangular waveguide?n.)TM mode in rectangular waveguide?arrow_forwardWhat will be the change in the electron density of electrons of the E layer, when the critical frequency changes from to 4 MHz to 1 MHz between day and night?arrow_forwardwhat are the modes of waveguide from where does they origionate?arrow_forward
- P 2.7a What will be the cutoff wavelength for dominant mode in rectangular waveguide whose length is 10 cm? (2)arrow_forwardFigure: structure of a thin film silicon solar cell. Glass Front ITO i (aSi:H) back ZnO:AI 1-D PC The figure above shows a schematic overview of an thin film single junction solar cell. Upon what principle is the back reflector of this solar cell based? The principle of the back reflector is based on refractive scattering. ) The principle of the back reflector is based on diffractive scattering. ) The principle of the back reflector is based on constructive/destructive interference. The principle of the back reflector is based on plasmonic scatteringarrow_forward*:For a certain mode, in a rectangular waveguide, propagation occurs for signals Information are not sufficient to decide O Whose frequency is above the cut off frequency Whose frequency is below the cut off frequency Depending on the dimensions of the waveguide and dielectric O The dominant mode of propagation is preferred with rectangular waveguides * because we can use air as dielectric O it is easier than other modes and leads to smallest dimension of waveguide it is easier than the other modes it leads to smallest dimension of waveguide none of metionedarrow_forward
- 3) Solve the cutoff frequency for the first mode and second mode of WR975 Wave guide TABLE 7.1 Some Standard Rectangular Waveguides Waveguide de signation a (in) b (in) t (in) fe, (GHz) Frequency range (GHz) WR975 9.750 4.875 0.125 0.605 0.75-1.12 WR650 6.500 3.250 0.080 0.908 1.12–1.70 WR430 4.300 2.150 0.080 1.375 1.70-2.60 WR284 2.840 1.340 0.080 2.08 2.60-3.95 WR187 1.872 0.872 0.064 3.16 3.95-5.85 WR137 1.372 0.622 0.064 4.29 5.85-8.20 WR90 0.900 0.450 0.050 6.56 8.2–12.4 WR62 0.622 0.311 0.040 9.49 12.4–18arrow_forward2. Up to this point, you have relied on the boundary conditions to solve the mode fields in a waveguide or a resonant cavity. What is the most-used boundary condition you used for a structure with conducting boundaries?arrow_forwardIn the transverse electromagnetic TEM mode,., .......... Ez = 0, Hz #0 Ez #0, Hz = 0 Ez = 0, Hz =0 nonearrow_forward
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