Chapter 12.7, Problem 1WE

To determine

To solve the given triangle ABC.

Answer to Problem 1WE

  $b=32.0$

Explanation of Solution

Given information :

  

According to law of sines,

In any triangle ABC,

  

  $\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}$

Hence,

  $\begin{array}{l}\frac{14}{\sin {25}^{\circ }}=\frac{b}{\sin {75}^{\circ }}\\ b=\frac{\sin {75}^{\circ }\times 14}{\sin {25}^{\circ }}\\ b=32.0\end{array}$