
(a)
Find the perimeter of a regular
(a)

Answer to Problem 24WE
2nsin(180n) , 2ntan(180n)
Explanation of Solution
Formula Used:
Law of Sines:
asinA=bsinB=csinC
Calculation:
The n -gon has n sides and if we join the sides to the centre of the circle, it forms n isosceles
Since there are n equal triangles, the angle to the centre of each triangle is 360°n .
Let base of each triangle is x .
In the isosceles triangle , the central angle is 360°n , the other two angles are equal since the triangle is isosceles , so each angle is 90°−180°n..............[sum of all angles is 180°] .
Use the law of sines to find x :
1sin(90−180n)=xsin(360n)⇒x=sin(2⋅180n)cos(180n).....................[multiply each side by sin(360n) and sin(90-θ)=cosθ]⇒x=2sin(180n)cos(180n)cos(180n)..................[sin2θ=2sinθcosθ]⇒x=2sin(180n)
Since the n -gon has n sides , and one of the side is x , so , the perimeter of the n -gon inscribed inside a unit circle is nx :
nx=2nsin(180n)
The n -gon circumscribed about the unit circle has n sides and if we join the sides to the centre of the circle, it forms n triangles:
Since there are n equal triangles, the angle to the centre of each triangle is 360°n .
So, the central angle of the right angled triangle that bisects the triangle is 180°n
Let base of each right angled triangle is x and height is 1.
So,
tanθ=side opposite to θside adjacent to θ⇒tan(180n)=x1⇒x=tan(180n)
Eace side of the n - gon is 2x = 2tan(180n)
Since the n -gon has n sides , and one of the side is 2tan(180n) , so , the perimeter of the n -gon circumscribed about a unit circle is:
2ntan(180n)
(b)
Find where the number is approached when n gets larger and larger:
nsin(180n) , ntan(180n)
(b)

Answer to Problem 24WE
both the numbers approaches 0 as n becomes larger and larger.
Explanation of Solution
Calculation :
As n becomes larger and larger , 180n becomes smaller and smaller. So,
n→∞⇒180n→0⇒nsin180n→0 and ntan180n→0
Hence , both the numbers approaches 0 as n becomes larger and larger.
Chapter 12 Solutions
Algebra and Trigonometry: Structure and Method, Book 2
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