In Problems 27 and 28 show that the given partial differential equation possesses the indicated product solution. 28. ∂ 2 u ∂ r 2 + 1 r ∂ u ∂ r + 1 r 2 ∂ 2 u ∂ θ 2 = 0 ; u = ( c 1 cos αθ + c 2 sin αθ )( c 3 r α + c 4 r − α )
In Problems 27 and 28 show that the given partial differential equation possesses the indicated product solution. 28. ∂ 2 u ∂ r 2 + 1 r ∂ u ∂ r + 1 r 2 ∂ 2 u ∂ θ 2 = 0 ; u = ( c 1 cos αθ + c 2 sin αθ )( c 3 r α + c 4 r − α )
Solution Summary: The author explains that the partial differential equation partial
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