Find the steady-state temperature u(r,θ) in a semicirular plate of radius r=2 if: u(2,θ) = {1,  0<θ<π/2 and 0,  π/2<θ<π} and the edges θ = 0 and    0 = π are insuated.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Find the steady-state temperature u(r,θ) in a semicirular plate of radius r=2 if:

u(2,θ) = {1,  0<θ<π/2 and 0,  π/2<θ<π} and the edges θ = 0 and    0 = π are insuated. 

**Problem Statement:**

Find the steady-state temperature \( u(r, \theta) \) in a semicircular plate of radius \( r = 2 \).

**Boundary Conditions:**

\[ 
u(2, \theta) = 
  \begin{cases} 
   1 & \text{for } 0 < \theta < \pi/2 \\
   0 & \text{for } \pi/2 < \theta < \pi 
  \end{cases}
\]

Additionally, the edges \( \theta = 0 \) and \( \theta = \pi \) are insulated. 

---

**Explanation:**

The problem involves determining the temperature distribution, \( u(r, \theta) \), over a semicircular plate. The boundary conditions specify that along the curved edge of the semicircular plate (at \( r = 2 \)), the temperature is set to 1 in the first quadrant (\( 0 < \theta < \pi/2 \)) and 0 in the second quadrant (\( \pi/2 < \theta < \pi \)). The straight edges of the semicircle, corresponding to \( \theta = 0 \) and \( \theta = \pi \), are insulated, meaning no heat flows across these boundaries.
Transcribed Image Text:**Problem Statement:** Find the steady-state temperature \( u(r, \theta) \) in a semicircular plate of radius \( r = 2 \). **Boundary Conditions:** \[ u(2, \theta) = \begin{cases} 1 & \text{for } 0 < \theta < \pi/2 \\ 0 & \text{for } \pi/2 < \theta < \pi \end{cases} \] Additionally, the edges \( \theta = 0 \) and \( \theta = \pi \) are insulated. --- **Explanation:** The problem involves determining the temperature distribution, \( u(r, \theta) \), over a semicircular plate. The boundary conditions specify that along the curved edge of the semicircular plate (at \( r = 2 \)), the temperature is set to 1 in the first quadrant (\( 0 < \theta < \pi/2 \)) and 0 in the second quadrant (\( \pi/2 < \theta < \pi \)). The straight edges of the semicircle, corresponding to \( \theta = 0 \) and \( \theta = \pi \), are insulated, meaning no heat flows across these boundaries.
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