In Problems 27 and 28 show that the given partial differential equation possesses the indicated product solution. 27. k ( ∂ 2 u ∂ r 2 + 1 r ∂ u ∂ r ) = ∂ u ∂ t ; u = e − k α 2 t ( c 1 J 0 ( α r ) + c 2 Y 0 ( α r ) )
In Problems 27 and 28 show that the given partial differential equation possesses the indicated product solution. 27. k ( ∂ 2 u ∂ r 2 + 1 r ∂ u ∂ r ) = ∂ u ∂ t ; u = e − k α 2 t ( c 1 J 0 ( α r ) + c 2 Y 0 ( α r ) )
Solution Summary: The author explains the partial differential equation k(partial 2uprt) and its solution.
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