Chapter 12.1, Problem 10SSC

(a)

To determine

To convert :The given temperature to Kelvin.

Answer to Problem 10SSC

The temperature in Kelvins is $\text{278 K}$

Explanation of Solution

Given:

The temperature is $5°\text{C}$

Formula Used:

The temperature in degree celsius can be converted to Kelvins using the formula,

  $T_K=T_{°C}+273\text{ K}$

Calculation:

Here, the given temperature is $5°\text{C}$ . The temperature in Kelvins can be calculated as,

  $\begin{array}{c}{T}_A=5+273\\ =278\text{ K}\end{array}$

Conclusion:

Therefore, the given temperature in Kelvins is 278K.

(b)

To determine

To convert :The given temperature to degree celsius.

Answer to Problem 10SSC

The temperature in degree celsius is $-239°\text{C}$

Explanation of Solution

Given:

The temperature is 34 K

Formula Used:

The temperature in Kelvins can be converted to degree celsius using the formula,

  $T_{°C}=T_K-273\text{ K}$

Calculation:

Here, the given temperature is 34 K. The temperature in degree celsius can be calculated as,

  $\begin{array}{c}{T}_A=34-273\\ =-239°\text{C}\end{array}$

Conclusion:

The given temperature in degree celsius is $-239°\text{C}$ .

(c)

To determine

To convert:The given temperature to Kelvins.

Answer to Problem 10SSC

The temperature in Kelvins is $485\text{ K}$

Explanation of Solution

Given:

The temperature is $212°\text{C}$

Formula Used:

The temperature in degree celsius can be converted to Kelvins using the formula,

  $T_K=T_{°C}+273\text{ K}$

Calculation:

Here, the given temperature is $212°\text{C}$ . The temperature in Kelvins can be calculated as,

  $\begin{array}{c}{T}_A=212+273\\ =485\text{ K}\end{array}$

Conclusion:

The given temperature in Kelvins 485 K.

(d)

To determine

To convert : The given temperature to degree celsius.

Answer to Problem 10SSC

The temperature in degree celsius is $\text{43 }°\text{C}$

Explanation of Solution

Given:

The temperature is 316 K

Formula Used:

The temperature in Kelvins can be converted to degree celsius using the formula,

  $T_{0C}=T_K-273\text{ K}$

Calculation:

Here, the given temperature is 316 K. The temperature in degree celsius can be calculated as,

  $\begin{array}{c}{T}_A=316-273\\ =43°\text{C}\end{array}$

Conclusion:

The given temperature in degree celsiusis $43°\text{C}$ .