Chapter 12, Problem 71A

To determine

Change in temperature of vat.

Answer to Problem 71A

  $\Delta T=0.016°\text{C}$

Explanation of Solution

Given:

Work done by machine, $C=4180\text{J/kg}\text{.K}$

Mass of water, $m=32\text{kg}$

Formula Used:

Specific heat formula is,

  $\Delta U=mC\Delta T$

Where,

  $\Delta U$ is heat energy

  $m$ is mass

  $C$ is specific heat

  $\Delta T$ is change in temperature.

Calculation:

Let assume that the 2100 J of work from machine is absorbed in the stamped piece, so vat will absorb 2100 J from each piece in the form of heat. Water only transfers heat and no work is done on water.

So, change in temperature is given by above equation as,

  $\begin{array}{c}\Delta T=\frac{\Delta U}{mC}\\ =\frac{2100}{32\times 4180}\\ =0.016°\text{C}\end{array}$

Conclusion:

Therefore, change in temperature of vat is $\Delta T=0.016°\text{C}$ .