World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Question
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Chapter 12, Problem 58A

(a)

Interpretation Introduction

Interpretation:

The electronic configuration of given atom and its most stable ion is to be written.

Concept introduction:

Electronic configuration is arrangement of electrons in an atom. The atoms lose or gain electrons to acquire noble gas configuration because the ion which achieve nearest noble gas configuration is most stable.

(a)

Expert Solution
Check Mark

Answer to Problem 58A

  Na forms Na+ :

It attains configuration as Ne

Explanation of Solution

Sodium belongs to first group. So it has tendency to loss one electron and form most stable ion Na+

Electronic configuration of Na according to Aufbau’s Principle is:

  [Ne]3s1

Therefore, Electronic configuration of Na+ :

  [Ne]

(b)

Interpretation Introduction

Interpretation:

The electronic configuration of given atom and its most stable ion is to be written.

Concept introduction:

Electronic configuration is arrangement of electrons in an atom. The atoms lose or gain electrons to acquire noble gas configuration because the ion which achieve nearest noble gas configuration is most stable.

(b)

Expert Solution
Check Mark

Answer to Problem 58A

  I forms I

It attains configuration as Xe

Explanation of Solution

Iodine belongs to 17th group. So it has tendency to gain one electron and form most stable ion I

Electronic configuration of I according to Aufbau’s Principle is:

  [Kr]5s24d105p5

Therefore, Electronic configuration of I :

  [Kr]5s24d105p6

(c)

Interpretation Introduction

Interpretation:

The electronic configuration of given atom and its most stable ion is to be written.

Concept introduction:

Electronic configuration is arrangement of electrons in an atom. The atoms lose or gain electrons to acquire noble gas configuration because the ion which achieve nearest noble gas configuration is most stable.

(c)

Expert Solution
Check Mark

Answer to Problem 58A

  K forms K+ :

It attains configuration as Ar

Explanation of Solution

Potassium belongs to first group. So it has tendency to loss one electron and form most stable ion K+

Electronic configuration of K according to Aufbau’s Principle is:

  [Ar]4s1

Therefore, Electronic configuration of K+ :

  [Ar]

(d)

Interpretation Introduction

Interpretation:

The electronic configuration of given atom and its most stable ion is to be written.

Concept introduction:

Electronic configuration is arrangement of electrons in an atom. The atoms lose or gain electrons to acquire noble gas configuration because the ion which achieve nearest noble gas configuration is most stable.

(d)

Expert Solution
Check Mark

Answer to Problem 58A

  CaformsCa2+and attains configuration as argon.

Explanation of Solution

Calcium belongs to 2nd group. So it has tendency to loss two electrons and form most stable ion Ca2+

Electronic configuration of Ca according to Aufbau’s Principle is:

  1s22s22p63s23p64s2

Therefore, Electronic configuration of Ca2+ :

  1s22s22p63s23p6

It attains configuration as Ar

(e)

Interpretation Introduction

Interpretation:

The electronic configuration of given atom and its most stable ion is to be written.

Concept introduction:

Electronic configuration is arrangement of electrons in an atom. The atoms lose or gain electrons to acquire noble gas configuration because the ion which achieve nearest noble gas configuration is most stable.

(e)

Expert Solution
Check Mark

Answer to Problem 58A

Sulphur forms S2ion and get configuration as argon.

Explanation of Solution

Sulphur belongs to 16th group. So it has tendency to gain two electrons and form most stable ion S2

Electronic configuration of S according to Aufbau’s Principle is:

  [Ne]3s23p4

Therefore, Electronic configuration of S2 :

  [Ar]

(f)

Interpretation Introduction

Interpretation:

The electronic configuration of given atom and its most stable ion is to be written.

Concept introduction:

Electronic configuration is arrangement of electrons in an atom. The atoms lose or gain electrons to acquire noble gas configuration because the ion which achieve nearest noble gas configuration is most stable.

(f)

Expert Solution
Check Mark

Answer to Problem 58A

  Mg forms Mg2+ :

It attains configuration as Ne

Explanation of Solution

Magnesium belongs to 2nd group. So it has tendency to loss two electrons and form most stable ion Mg2+

Electronic configuration of Mg according to Aufbau’s Principle is:

  [Ne]3s2

Therefore, Electronic configuration of Mg2+ :

  [Ne]

(g)

Interpretation Introduction

Interpretation:

The electronic configuration of given atom and its most stable ion is to be written.

Concept introduction:

Electronic configuration is arrangement of electrons in an atom. The atoms lose or gain electrons to acquire noble gas configuration because the ion which achieve nearest noble gas configuration is most stable.

(g)

Expert Solution
Check Mark

Answer to Problem 58A

  Al forms Al3+ :

It attains configuration as Ne

Explanation of Solution

Aluminium belongs to 3rd group. So it has tendency to loss three electrons and form most stable ion Al3+

Electronic configuration of Al according to Aufbau’s Principle is:

  [Ne]3s23p1

Therefore, Electronic configuration of Al3+ :

  [Ne]

(h)

Interpretation Introduction

Interpretation:

The electronic configuration of given atom and its most stable ion is to be written.

Concept introduction:

Electronic configuration is arrangement of electrons in an atom. The atoms lose or gain electrons to acquire noble gas configuration because the ion which achieve nearest noble gas configuration is most stable.

(h)

Expert Solution
Check Mark

Answer to Problem 58A

Nitrogen forms N3ion and attain configuration as neon.

Explanation of Solution

Nitrogen belongs to 15th group. So it has tendency to gain three electrons and form most stable ion N3ion

Electronic configuration of N according to Aufbau’s Principle is:

  1s22s22p3

Therefore, Electronic configuration of N3ion :

  1s22s22p6

Chapter 12 Solutions

World of Chemistry, 3rd edition

Ch. 12.2 - Prob. 4RQCh. 12.2 - Prob. 5RQCh. 12.2 - Prob. 6RQCh. 12.2 - Prob. 7RQCh. 12.3 - Prob. 1RQCh. 12.3 - Prob. 2RQCh. 12.3 - Prob. 3RQCh. 12.3 - Prob. 4RQCh. 12.4 - Prob. 1RQCh. 12.4 - Prob. 2RQCh. 12.4 - Prob. 3RQCh. 12.4 - Prob. 4RQCh. 12.4 - Prob. 5RQCh. 12 - Prob. 1ACh. 12 - Prob. 2ACh. 12 - Prob. 3ACh. 12 - Prob. 4ACh. 12 - Prob. 5ACh. 12 - Prob. 6ACh. 12 - Prob. 7ACh. 12 - Prob. 8ACh. 12 - Prob. 9ACh. 12 - Prob. 10ACh. 12 - Prob. 11ACh. 12 - Prob. 12ACh. 12 - Prob. 13ACh. 12 - Prob. 14ACh. 12 - Prob. 15ACh. 12 - Prob. 16ACh. 12 - Prob. 17ACh. 12 - Prob. 18ACh. 12 - Prob. 19ACh. 12 - Prob. 20ACh. 12 - Prob. 21ACh. 12 - Prob. 22ACh. 12 - Prob. 23ACh. 12 - Prob. 24ACh. 12 - Prob. 25ACh. 12 - Prob. 26ACh. 12 - Prob. 27ACh. 12 - Prob. 28ACh. 12 - Prob. 29ACh. 12 - Prob. 30ACh. 12 - Prob. 31ACh. 12 - Prob. 32ACh. 12 - Prob. 33ACh. 12 - Prob. 34ACh. 12 - Prob. 35ACh. 12 - Prob. 36ACh. 12 - Prob. 37ACh. 12 - Prob. 38ACh. 12 - Prob. 39ACh. 12 - Prob. 40ACh. 12 - Prob. 41ACh. 12 - Prob. 42ACh. 12 - Prob. 43ACh. 12 - Prob. 44ACh. 12 - Prob. 45ACh. 12 - Prob. 46ACh. 12 - Prob. 47ACh. 12 - Prob. 48ACh. 12 - Prob. 49ACh. 12 - Prob. 50ACh. 12 - Prob. 51ACh. 12 - Prob. 52ACh. 12 - Prob. 53ACh. 12 - Prob. 54ACh. 12 - Prob. 55ACh. 12 - Prob. 56ACh. 12 - Prob. 57ACh. 12 - Prob. 58ACh. 12 - Prob. 59ACh. 12 - Prob. 60ACh. 12 - Prob. 61ACh. 12 - Prob. 62ACh. 12 - Prob. 63ACh. 12 - Prob. 64ACh. 12 - Prob. 1STPCh. 12 - Prob. 2STPCh. 12 - Prob. 3STPCh. 12 - Prob. 4STPCh. 12 - Prob. 5STPCh. 12 - Prob. 6STPCh. 12 - Prob. 7STPCh. 12 - Prob. 8STPCh. 12 - Prob. 9STP
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