World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 12, Problem 22A

(a)

Interpretation Introduction

Interpretation:

The formula of ionic compound formed by pair of atom is to be written.

Concept introduction:

Electronic configuration represents the placement of electrons in various shells, subshells and orbitals of a particular atom.

(a)

Expert Solution
Check Mark

Answer to Problem 22A

Electronic configuration of aluminium is:

  [Ne]3s23p1

Electronic configuration of sulphur is:

  [Ne]3s23p4

Formula of ionic compound: Al2S3

Explanation of Solution

Aluminium has three electrons in valence shell and hence it has tendency to loss three electrons where sulphur has six electrons in valence shell and hence it has tendency to gain two electrons. Therefore two atom of aluminium will form ionic bond with three atoms of sulphur and the chemical formula is Al2S3

(b)

Interpretation Introduction

Interpretation:

The formula of ionic compound formed by pair of atom is to be written.

Concept introduction:

Electronic configuration represents the placement of electrons in various shells, subshells and orbitals of a particular atom.

(b)

Expert Solution
Check Mark

Answer to Problem 22A

Electronic configuration of radium is:

  [Rn]7s2

Electronic configuration of oxygen is:

  1s22s22p4

Formula of ionic compound: RaO

Explanation of Solution

Radium has two electrons in valence shell and hence it has tendency to loss two electrons where oxygen has six electrons in valence shell and hence it has tendency to gain two electrons. Therefore one atom of radium will form ionic bond with one atom of oxygen and the chemical formula is RaO

(c)

Interpretation Introduction

Interpretation:

The formula of ionic compound formed by pair of atom is to be written.

Concept introduction:

Electronic configuration represents the placement of electrons in various shells, subshells and orbitals of a particular atom.

(c)

Expert Solution
Check Mark

Answer to Problem 22A

Electronic configuration of calcium is:

  [Ar]4s2

Electronic configuration of fluorine is:

  1s22s22p5

Formula of ionic compound: CaF2

Explanation of Solution

Calcium has two electrons in valence shell and hence it has tendency to loss two electrons where fluorine has seven electrons in valence shell and hence it has tendency to gain one electros. Therefore one atom of calcium will form ionic bond with two atoms of fluorine and the chemical formula is CaF2

(d)

Interpretation Introduction

Interpretation:

The formula of ionic compound formed by pair of atom is to be written.

Concept introduction:

Electronic configuration represents the placement of electrons in various shells, subshells and orbitals of a particular atom.

(d)

Expert Solution
Check Mark

Answer to Problem 22A

Electronic configuration of cesium is:

  [Xe]6s1

Electronic configuration of nitrogen is:

  1s22s22p3

Formula of ionic compound: Cs3N

Explanation of Solution

Cesium has one electron in valence shell and hence it has tendency to loss one electron where nitrogen has five electrons in valence shell and hence it has tendency to gain three electrons. Therefore three atoms of cesium will form ionic bond with one atom of nitrogen and the chemical formula is Cs3N

(e)

Interpretation Introduction

Interpretation:

The formula of ionic compound formed by pair of atom is to be written.

Concept introduction:

Electronic configuration represents the placement of electrons in various shells, subshells and orbitals of a particular atom.

(e)

Expert Solution
Check Mark

Answer to Problem 22A

Electronic configuration of rubidium is:

  [Kr]5s1

Electronic configuration of phosphorus is:

  [Ne]3s23p3

Formula of ionic compound: Rb3P

Explanation of Solution

Rubidium has one electron in valence shell and hence it has tendency to loss one electron where phosphorus has five electrons in valence shell and hence it has tendency to gain three electrons. Therefore three atoms of rubidium will form ionic bond with one atom of phosphorus and the chemical formula is Rb3P

Chapter 12 Solutions

World of Chemistry, 3rd edition

Ch. 12.2 - Prob. 4RQCh. 12.2 - Prob. 5RQCh. 12.2 - Prob. 6RQCh. 12.2 - Prob. 7RQCh. 12.3 - Prob. 1RQCh. 12.3 - Prob. 2RQCh. 12.3 - Prob. 3RQCh. 12.3 - Prob. 4RQCh. 12.4 - Prob. 1RQCh. 12.4 - Prob. 2RQCh. 12.4 - Prob. 3RQCh. 12.4 - Prob. 4RQCh. 12.4 - Prob. 5RQCh. 12 - Prob. 1ACh. 12 - Prob. 2ACh. 12 - Prob. 3ACh. 12 - Prob. 4ACh. 12 - Prob. 5ACh. 12 - Prob. 6ACh. 12 - Prob. 7ACh. 12 - Prob. 8ACh. 12 - Prob. 9ACh. 12 - Prob. 10ACh. 12 - Prob. 11ACh. 12 - Prob. 12ACh. 12 - Prob. 13ACh. 12 - Prob. 14ACh. 12 - Prob. 15ACh. 12 - Prob. 16ACh. 12 - Prob. 17ACh. 12 - Prob. 18ACh. 12 - Prob. 19ACh. 12 - Prob. 20ACh. 12 - Prob. 21ACh. 12 - Prob. 22ACh. 12 - Prob. 23ACh. 12 - Prob. 24ACh. 12 - Prob. 25ACh. 12 - Prob. 26ACh. 12 - Prob. 27ACh. 12 - Prob. 28ACh. 12 - Prob. 29ACh. 12 - Prob. 30ACh. 12 - Prob. 31ACh. 12 - Prob. 32ACh. 12 - Prob. 33ACh. 12 - Prob. 34ACh. 12 - Prob. 35ACh. 12 - Prob. 36ACh. 12 - Prob. 37ACh. 12 - Prob. 38ACh. 12 - Prob. 39ACh. 12 - Prob. 40ACh. 12 - Prob. 41ACh. 12 - Prob. 42ACh. 12 - Prob. 43ACh. 12 - Prob. 44ACh. 12 - Prob. 45ACh. 12 - Prob. 46ACh. 12 - Prob. 47ACh. 12 - Prob. 48ACh. 12 - Prob. 49ACh. 12 - Prob. 50ACh. 12 - Prob. 51ACh. 12 - Prob. 52ACh. 12 - Prob. 53ACh. 12 - Prob. 54ACh. 12 - Prob. 55ACh. 12 - Prob. 56ACh. 12 - Prob. 57ACh. 12 - Prob. 58ACh. 12 - Prob. 59ACh. 12 - Prob. 60ACh. 12 - Prob. 61ACh. 12 - Prob. 62ACh. 12 - Prob. 63ACh. 12 - Prob. 64ACh. 12 - Prob. 1STPCh. 12 - Prob. 2STPCh. 12 - Prob. 3STPCh. 12 - Prob. 4STPCh. 12 - Prob. 5STPCh. 12 - Prob. 6STPCh. 12 - Prob. 7STPCh. 12 - Prob. 8STPCh. 12 - Prob. 9STP
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