Interpretation:
Vapor phase composition present above liquid is to be calculated. Also, vapor phase composition present above second liquid is to be calculated.
Concept introduction:
Distillation is a liquid-gas separation technique for two or more liquids on the basis of their difference in boiling point or vapor pressure.
Vapor pressure is pressure exerted by vapor phase of liquid produced due to an increase in the molecular kinetic energy of the liquid phase or due to the increase in temperature.
The temperature at which atmospheric pressure exerted on liquid equals to its vapor pressure is known to be its boiling point. Vapor pressure of the component decide boiling point of any mixture. Impurities in the mixture might result in an increase or decrease of observed boiling point.
Want to see the full answer?
Check out a sample textbook solutionChapter 12 Solutions
Laboratory Techniques in Organic Chemistry
- Sketch graphs of total vapor pressure versus the mole fraction of two volatile substances that show (a) positive deviation from Raoults law. (b) negative deviation from Raoults law. (c) a maximum boiling azeotrope. (d) a minimum boiling azeotrope.arrow_forwardDefine the normal boiling point of water. Why does a sample of boiling water remain at the same temperature until all the water has been boiled? Define the normal freezing point of water. Sketch a representation of a heating/cooling curve for water, marking clearly the normal freezing and boiling points.arrow_forwardExamine the nanoscale diagrams and the phase diagram for Question 112. Match each particulate diagram (1 through 7) to its corresponding point (A through H) on the phase diagram.arrow_forward
- In the distillation of a pure substance (e.g., water), why does all of the water not vaporize at once when the boiling point is reached?arrow_forwardThe molecular mass of butanol, C4H9OH, is 74.14; that of ethylene glycol, CH2(OH)CH2OH, is 62.08, yet their boiling points are 117.2 C and 174 C, respectively. Explain the reason for the difference.arrow_forwardConsider two hypothetical pure substances, AB(s) and XY(s). When equal molar amounts of these substances are placed in separate 500-mL samples of water, they undergo the following reactions: AB(s)A+(aq)+B(aq)XY(s)XY(aq) a Which solution would you expect to have the lower boiling point? Why? b Would you expect the vapor pressures of the two solutions to be equal? If not, which one would you expect to have the higher vapor pressure? c Describe a procedure that would make the two solutions have the same boiling point. d If you took 250 mL of the AB(aq) solution prepared above, would it have the same boiling point as the original solution? Be sure to explain your answer. e The container of XY(aq) is left out on the bench top for several days, which allows some of the water to evaporate from the solution. How would the melting point of this solution compare to the melting point of the original solution?arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
- Introductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning