Principles of Geotechnical Engineering (MindTap Course List)
9th Edition
ISBN: 9781305970939
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Chapter 12, Problem 12.24P
(a)
To determine
Find the undrained shear strength of remolded clay using the relationships Leroueil et al.
(b)
To determine
Find the undrained shear strength of remolded clay using the relationships Terzaghi et al.(1996).
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Students have asked these similar questions
A given saturated clay is known to have effective
strength parameters of c' = 10 kPa and = 28°.
A sample of this clay was brought to failure quickly
so that no dissipation of the pore water pressures
%3D
could occur. At failure it was known that o
KPa, o = 10 KPa and
= 20 kPa.
%3D
(a) Estimate the values of o, and oz at failure
(b) Use the Mohr circle to illustrate the effective
stress and total failure stress.
The following results were obtained from an oedometer test on a specimen of saturated clay:
54
107
214
429
214
107
54
27
Pressure (kPa):
1.024
1.012
1.001
0.994
1.068
1.144
1.217
1.243
Void ratio:
A layer of this clay 8 m thick lies below a 4 m depth of sand, the water table being at the surface. The saturated unit weight for both soils =19 kN/m3=19 kN/m3. A 4 m depth of fill, unit weight =21 kN/m3=21 kN/m3, is placed on the sand over an extensive area. Determine the final settlement due to consolidation of the clay. If the fill were to be removed some time after the completion of consolidation, what heave would eventually take place due to swelling of the clay?
A series of previous tests has established that the ultimate effective friction angle
of a NC clayey soil is 19.2°.
If a CD test is now performed on this soil with a cell pressure of 105 kPa, what
would be deviator stress at failure?
Given: o3 = Kao, where Ka
1-sin o'
1+sin o'
Chapter 12 Solutions
Principles of Geotechnical Engineering (MindTap Course List)
Ch. 12 - Prob. 12.1PCh. 12 - Prob. 12.2PCh. 12 - Prob. 12.3PCh. 12 - Prob. 12.4PCh. 12 - Prob. 12.5PCh. 12 - Prob. 12.6PCh. 12 - Prob. 12.7PCh. 12 - Prob. 12.8PCh. 12 - Prob. 12.9PCh. 12 - Prob. 12.10P
Ch. 12 - Prob. 12.11PCh. 12 - Prob. 12.12PCh. 12 - Prob. 12.13PCh. 12 - Following are the results of...Ch. 12 - Prob. 12.15PCh. 12 - Prob. 12.16PCh. 12 - Prob. 12.17PCh. 12 - Prob. 12.18PCh. 12 - Prob. 12.19PCh. 12 - Prob. 12.20PCh. 12 - Prob. 12.21PCh. 12 - Prob. 12.22PCh. 12 - Prob. 12.23PCh. 12 - Prob. 12.24PCh. 12 - Prob. 12.1CTP
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- A consolidated-undrained triaxial compression test was performed on a normalconsolidated clay sample. During the experiment, the confining pressure was 140 kPa, thedeviator stress was 125 kPa, and the pore water pressure was 75 kPa at the time of failure.According to the information given:i- Find the consolidated-undrained internal friction angle of the clay. ii- Find the drained friction angle of the clayarrow_forwardThe following results were obtained at failure in a series of drained triaxial tests on fully saturated clay specimens originally 38 mm diameter by 76 mm long. All-round pressure (kN/m2) Axial compression (mm) Axial load (N) Pore-water pressure (kN/m2) 200 400 600 7.22 8.36 9.41 480 895 1300 25 75 100 (a) Determine the values of the shear strength parameters c and . (b) Determine the values of the shear strength parameters c and . (c) A different specimen of the same soil is tested in undrained triaxial compression at a cell pressure of 240 kN/m2 and fails when the deviator stress is 160 kN/m2. Calculate the pore water pressure in the specimen at failure.arrow_forwardQuestion 3 The results of two consolidated-drained test triaxial tests on a clay are given below: Specimen No. Chamber Pressure Deviator Stress 220 400 105 II 210 1. Determine the angle of internal friction. 2. Determine the cohesion of the clay. 3. Determine the normal stress on the point on the failure plane of the 2"d specimen. O Question 1: A. 26.744 O Question 1: B. 26.042 O Question 1: C. 27.871 O Question 1: D. 27.486 O Question 2: A. 10.737 O Question 2: B. 12.141 O Question 2: C. 17.372 O Question 2: D. 14.836 O Question 3: A. 317.694 O Question 3: B. 232.575 O Question 3: C. 230.306 O Question 3: D. 322.194 O O O O O O O COarrow_forward
- The following results were obtained from a direct shear test on a dry uncemented carbonate sand: normal stress = 96.6 kPa, shear stress at failure = 67.7 kPa. By means of a Mohr's circle of stresses, find the magnitude and directions of the principal stresses acting on a soil element within the zone of failure. Assume uniformity of the sample. Show step-by-step your answer with the formulated equations and final results.arrow_forwardZAIN IQ I. Homework 4... During an oedometer test on a specimen of saturated clay, the thickness of the specimen decreased from 19.931 mm to 19.720 mm under an increment of stress from 200 to 400 kPa which was maintained for 24 hours. The stress was then removed from the specimen, its thickness was measured water content determined as 26.8%. 19.842 mm, and its Taking Gs of the particles to be 2.70, calculate the void ratio before and after the application of the stress increment, and the coefficient of volume decrease (m,) for this stress range. (Ans: e,= 0.731, e2= 0.713, m, = 0.052 m/MN)arrow_forwardA consolidated-drained triaxial test was conducted on an overconsolidated clay sample. The sample failed in test 1 at 01=200 kPa and 03=130 kPa, and in test 2 at o1=400 kPa and 03=290 kPa. Determine the undrained and drained friction angles and cohesion for the assumption that the Skempton's pore water pressure parameter A=0.45. Also, for a CU test on the same soil, determine o1, 1', 03', and excess pore water pressure u for 03=340 kPa.arrow_forward
- a sample of moist sand was subjected to a series of triaxial tests. the soil fails under the following stresses: sample 1: Cell pressure = 14 kPa Plunger stress = 34 kPa Sample 2: Cell pressure = 25 kPa Plunger stress = 56 kPa what is the cohesion angle of internal friction of the soil in degrees?arrow_forwardA consolidated undrained tri-axial test was conducted on a normally consolidated clay sample and the results are as follows: chamber confining pressure = 110kpa deviator stress at failure = 96kpa pore water pressure = 66kpa these test results were used to determine the drained friction angle of the soil. compute the deviator stress in (kpa) at failure when the drained test was conducted with the chamber confining pressure changed to 163kpa.arrow_forwardA sample of dry sand is subjected to a triaxial test . The angle of internal friction is 36° . If the cell pressure is 180 kN/m^2 , at what value of deviator stress will the soil fail ?arrow_forward
- A consolidated-undrained tri-axial test was conducted on a normally conslidated clay sample and the results are follows: Chamber confining pressure= 119kpa Deviator Stress at failure=90 kpa Pore water pressure= 58kpa These results were used to determine the drained friction angle of the soil. Compute the deviator stress (kpa) at failure when the drained test was conducted with the chamber confining pressure changed to 156 kpa. Use stored value. Answer to 5 decimal places.arrow_forwardQuestion 42 The results of two consolidated-drained test triaxial tests on a clay are given below: Specimen No. Chamber Pressure Deviator Stress 105 220 210 400 1. Determine the angle of internal friction. 2. Determine the cohesion of the clay. 3. Determine the normal stress on the point on the failure plane of the 2nd specimen. Question 1: A. 26.744 O Question 1: B. 26.042 Question 1: C. 27.871 O Question 1: D. 27.486 Question 2: A. 10.737 O Question 2: B. 12.141 Question 2: C. 17.372 Question 2: D. 14.836 Question 3: A. 317.694 O Question 3: B. 232.575 Question 3: C. 230.306 O Question 3: D. 322.194arrow_forwardA stratified soil sample has the following profile characteristics: LAYER 1: The upper later is a 4-m thick sand layer with void ration = 0.61 and specific gravity of solids = 2.65. LAYER 2: The lower layer is a 5-m thick clay layer with void ration = 0.48 and specific gravity of solids = 2.67. If the ground water table is situated at the interface between the sand and clay layers, evaluate the effective stress (in kPa) at the bottom of the sand layer, and the effective stress at the bottom of the clay layer.arrow_forward
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