The number of moles of CO 2 in 4.00 L of CO 2 gas should be calculated by using molar volume. Concept Introduction: According to Avogadro’s law , any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature. For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure. Standard Temperature = 0 o C (273 K) Standard Pressure = 1 atm (760 mmHg) At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

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Answer 1

Question

Chapter 11.6, Problem 54PP

(a)

Interpretation Introduction

Interpretation:

The number of moles of CO2 in 4.00 L of CO2 gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(b)

Interpretation Introduction

Interpretation:

The volume in litersoccupied by 0.420 mol of helium gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(c)

Interpretation Introduction

Interpretation:

The volume in liters occupied by 6.40 g of O₂ gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(d)

Interpretation Introduction

Interpretation:

The number of grams of Ne present in 11.2 L Ne gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

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Answer 2

Question

Chapter 11.6, Problem 54PP

(a)

Interpretation Introduction

Interpretation:

The number of moles of CO2 in 4.00 L of CO2 gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(b)

Interpretation Introduction

Interpretation:

The volume in litersoccupied by 0.420 mol of helium gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(c)

Interpretation Introduction

Interpretation:

The volume in liters occupied by 6.40 g of O₂ gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(d)

Interpretation Introduction

Interpretation:

The number of grams of Ne present in 11.2 L Ne gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

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Answer 3

Question

Chapter 11.6, Problem 54PP

(a)

Interpretation Introduction

Interpretation:

The number of moles of CO2 in 4.00 L of CO2 gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(b)

Interpretation Introduction

Interpretation:

The volume in litersoccupied by 0.420 mol of helium gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(c)

Interpretation Introduction

Interpretation:

The volume in liters occupied by 6.40 g of O₂ gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(d)

Interpretation Introduction

Interpretation:

The number of grams of Ne present in 11.2 L Ne gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

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Answer 4

Question

Chapter 11.6, Problem 54PP

(a)

Interpretation Introduction

Interpretation:

The number of moles of CO2 in 4.00 L of CO2 gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(b)

Interpretation Introduction

Interpretation:

The volume in litersoccupied by 0.420 mol of helium gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(c)

Interpretation Introduction

Interpretation:

The volume in liters occupied by 6.40 g of O₂ gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(d)

Interpretation Introduction

Interpretation:

The number of grams of Ne present in 11.2 L Ne gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

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Answer 5

Chapter 11.6, Problem 54PP

(a)

Interpretation Introduction

Interpretation:

The number of moles of CO2 in 4.00 L of CO2 gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(b)

Interpretation Introduction

Interpretation:

The volume in litersoccupied by 0.420 mol of helium gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(c)

Interpretation Introduction

Interpretation:

The volume in liters occupied by 6.40 g of O₂ gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

(d)

Interpretation Introduction

Interpretation:

The number of grams of Ne present in 11.2 L Ne gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

Answer 6

Chapter 11.6, Problem 54PP

(a)

Interpretation Introduction

Interpretation:

The number of moles of CO2 in 4.00 L of CO2 gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

Answer 7

Chapter 11.6, Problem 54PP

(a)

Interpretation Introduction

Interpretation:

The number of moles of CO2 in 4.00 L of CO2 gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

Answer 8

(b)

Interpretation Introduction

Interpretation:

The volume in litersoccupied by 0.420 mol of helium gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

Answer 9

(b)

Interpretation Introduction

Interpretation:

The volume in litersoccupied by 0.420 mol of helium gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

Answer 10

(c)

Interpretation Introduction

Interpretation:

The volume in liters occupied by 6.40 g of O₂ gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

Answer 11

(c)

Interpretation Introduction

Interpretation:

The volume in liters occupied by 6.40 g of O₂ gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

Answer 12

(d)

Interpretation Introduction

Interpretation:

The number of grams of Ne present in 11.2 L Ne gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

Answer 13

(d)

Interpretation Introduction

Interpretation:

The number of grams of Ne present in 11.2 L Ne gas should be calculated by using molar volume.

Concept Introduction:

According to Avogadro’s law, any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

For comparison, STP conditions are taken under consideration that is standard temperature and standard pressure.

Standard Temperature = 0^oC (273 K)

Standard Pressure = 1 atm (760 mmHg)

At STP, one mole of any gas occupies a volume of 22.4 L and this volume of any gas is known as molar volume.

Answer 14

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Answer 15

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Answer 16

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Answer 17

Ch. 11.1 - Prob. 1PP Ch. 11.1 - Prob. 2PP Ch. 11.1 - Prob. 3PP Ch. 11.1 - Prob. 4PP Ch. 11.1 - Prob. 5PP Ch. 11.1 - Prob. 6PP Ch. 11.1 - Prob. 7PP Ch. 11.1 - Prob. 8PP Ch. 11.2 - Prob. 9PP Ch. 11.2 - Prob. 10PP

Solution Summary: The author explains Avogadro's law that any two gases have equal volumes if gases consist of same number of moles of gas at same pressure and temperature.

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