Integrated Science
7th Edition
ISBN: 9780077862602
Author: Tillery, Bill W.
Publisher: Mcgraw-hill,
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Chapter 11.2, Problem 11SC
To determine
The correct option for the measure of the
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Chapter 11 Solutions
Integrated Science
Ch. 11.1 - Prob. 1SCCh. 11.1 - Prob. 2SCCh. 11.1 - Prob. 3SCCh. 11.1 - Prob. 4SCCh. 11.1 - Prob. 5SCCh. 11.1 - Prob. 6SCCh. 11.1 - Prob. 7SCCh. 11.1 - Prob. 8SCCh. 11.1 - Prob. 9SCCh. 11.2 - Prob. 10SC
Ch. 11.2 - Prob. 11SCCh. 11.3 - Prob. 12SCCh. 11 - How is a radioactive material different from a...Ch. 11 - Prob. 2CQCh. 11 - Prob. 3CQCh. 11 - Prob. 4CQCh. 11 - What is half-life? Give an example of the...Ch. 11 - Prob. 6CQCh. 11 - Prob. 7CQCh. 11 - Prob. 8CQCh. 11 - Prob. 9CQCh. 11 - Prob. 10CQCh. 11 - Prob. 11CQCh. 11 - Prob. 12CQCh. 11 - Prob. 13CQCh. 11 - Prob. 14CQCh. 11 - Prob. 15CQCh. 11 - Prob. 16CQCh. 11 - Prob. 17CQCh. 11 - Prob. 1PEACh. 11 - Prob. 2PEACh. 11 - Predict if the nuclei in exercise 1 are...Ch. 11 - Prob. 4PEACh. 11 - Prob. 5PEACh. 11 - Prob. 6PEACh. 11 - Prob. 7PEACh. 11 - Prob. 1PEBCh. 11 - Prob. 2PEBCh. 11 - Prob. 3PEBCh. 11 - Prob. 4PEBCh. 11 - Prob. 5PEBCh. 11 - Prob. 6PEBCh. 11 - Prob. 7PEB
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- Data from the appendices and the periodic table may be needed for these problems. (a) Natural potassium contains 40K, which has a halflife of 1.277109y. What mass of 40K in a person would have a decay rate of 4140 Bq? (b) What is the fraction of 40K in natural potassium, given that the person has 140 g in his body? (These numbers are typical for a 70kg adult.)arrow_forwardOften, when people have to work around radioactive materials spills, we see them wearing white coveralls (usually a plastic material). What types of radiation (it any) do you think these suits protect the worker from, and how?arrow_forwardIt is estimated that the total explosive yield of all the nuclear bombs in existence currently is about 4.000 MT. (a) Convert this amount of energy to kilowatthours, noting that 1kWh=3.60106J. (b) What would the monetary value of this energy be if it could be converted to electricity costing 10 cents per kW.h?arrow_forward
- (a) Calculate the number of grams of deuterium in an 80.000L swimming pool, given deuterium is 0.0150% of natural hydrogen. (b) Find the energy released in joules if this deuterium is fused via the reaction 2H+2H3He+n. (c) Could the neutrons be used to create more energy? (d) Discuss the amount of this type of energy in a swimming pool as compared to that in, say, a gallon of gasoline, also taking into consideration that water is far more abundant.arrow_forward(a) Calculate the energy released by the fusion of a 1.00-kg mixture of deuterium and tritium, which produces helium. Tire re are equal numbers of deuterium and tritium nuclei in the mixture. (b) If this process takes place continuously over a period of a year, what is the average power output?arrow_forwardConstruct Your Own Problem Consider the decay of radioactive substances in the Earth's interior. The energy emitted is converted to thermal energy that reaches the earth's surface and is radiated away into cold dark space. Construct a problem in which you estimate the activity in a cubic meter of earth rock? And then calculate the power generated. Calculate how much power must cross each square meter of the Earth’s surface if the power is dissipated at the same rate as it is generated. Among the things to consider are the activity per cubic meter, the energy per decay, and the size of the Earth.arrow_forward
- Data from the appendices and the periodic table may be needed for these problems. There is more than one isotope of natural uranium. If a researcher isolates 1.00 mg of the relatively scarce 235U and finds this mass to have an activity of 80.0 Bq, what is its halflife in years?arrow_forward(a) Calculate BEN for 235U, the rarer of the two most common uranium isotopes; (b) Calculate BEN for 238U(Most of uranium is 238U .)arrow_forwardHow many kilograms of water are needed to obtain the 198.8 mol of deuterium, assuming that deuterium is 0.01500% (by number) of natural hydrogen?arrow_forward
- One half the rays from 99mTc are absorbed by a 0.170mmthick lead shielding. Half of the rays that pass through the first layer of lead are absorbed in a second layer of equal thickness. What thickness of lead will absorb all but one in 1000 of these rays?arrow_forwardData from the appendices and the periodic table may be needed for these problems. Natural uranium is 0.7200% 235U and 99.27% 238U. What were the percentages of 235U and 238U in natural uranium when Earth formed 4.5109 years age?arrow_forwardOne half the rays from 99mTcare absorbed by a 0.170-mm-thicklead shielding. Half of the y rays that pass through the first layer of lead are absorbed in a second layer of equal thickness. What thickness of lead will absorb all but one in 1000 of these rays?arrow_forward
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