Integrated Science
7th Edition
ISBN: 9780077862602
Author: Tillery, Bill W.
Publisher: Mcgraw-hill,
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Chapter 11, Problem 7CQ
To determine
The meaning of background
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Integrated Science
Ch. 11.1 - Prob. 1SCCh. 11.1 - Prob. 2SCCh. 11.1 - Prob. 3SCCh. 11.1 - Prob. 4SCCh. 11.1 - Prob. 5SCCh. 11.1 - Prob. 6SCCh. 11.1 - Prob. 7SCCh. 11.1 - Prob. 8SCCh. 11.1 - Prob. 9SCCh. 11.2 - Prob. 10SC
Ch. 11.2 - Prob. 11SCCh. 11.3 - Prob. 12SCCh. 11 - How is a radioactive material different from a...Ch. 11 - Prob. 2CQCh. 11 - Prob. 3CQCh. 11 - Prob. 4CQCh. 11 - What is half-life? Give an example of the...Ch. 11 - Prob. 6CQCh. 11 - Prob. 7CQCh. 11 - Prob. 8CQCh. 11 - Prob. 9CQCh. 11 - Prob. 10CQCh. 11 - Prob. 11CQCh. 11 - Prob. 12CQCh. 11 - Prob. 13CQCh. 11 - Prob. 14CQCh. 11 - Prob. 15CQCh. 11 - Prob. 16CQCh. 11 - Prob. 17CQCh. 11 - Prob. 1PEACh. 11 - Prob. 2PEACh. 11 - Predict if the nuclei in exercise 1 are...Ch. 11 - Prob. 4PEACh. 11 - Prob. 5PEACh. 11 - Prob. 6PEACh. 11 - Prob. 7PEACh. 11 - Prob. 1PEBCh. 11 - Prob. 2PEBCh. 11 - Prob. 3PEBCh. 11 - Prob. 4PEBCh. 11 - Prob. 5PEBCh. 11 - Prob. 6PEBCh. 11 - Prob. 7PEB
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- Calculate the dose in Sv to the chest at a patient given an xray under the following conditions. The xray beam intensity is 1.50 W/m2, the area of the chest exposed is 0.0750 m2 35.0% of the xrays are absorbed in 20.0 kg of tissue, and the exposure time is 0.250 s.arrow_forwardWhat is the dose in Sv in a cancer treatment that exposes the patient to 200 Gy of rays?arrow_forwardWhat is the dose in Sv in a cancer treatment that exposes the patient to 200 Gy of rays?arrow_forward
- If everyone in Australia received an extra 0.05 mSv per year of radiation, what would be the increase in the number of cancer deaths per year? (Assume that time had elapsed for the effects to become apparent.) Assume that there are 200104 deaths per Sv of radiation per year. What percent at the actual number of cancer deaths recorded is this?arrow_forward(a) A cancer patient is exposed to rays from a 5000Ci 60Co transillumination unit for 32.0 s. The rays are collimated in such a manner that only 1.00% of them strike the patient. Of those, 20.0% are absorbed in a tumor having a mass of 1.50 kg. What is the dose in rem to the tumor, it the average energy per decay is 1.25 MeV? None of the s from the decay reach the patient. (b) Is the dose consistent with stated therapeutic doses?arrow_forwardFind the radiation dose in Gy for: (a) A 10mSv fluoroscopic xray series. (b) 50 mSv of skin exposure by an emitter. (c) 160 mSv of and rays from the 40K in your body.arrow_forward
- A plumber at a nuclear power plant receives a whole - body dose of 30 mSv in 15 minutes while repairing a crucial valve. Find the radiation-induced yearly risk of death from cancer and the chance of genetic defect from this maximum allowable exposure.arrow_forward(a) Calculate the energy released in the neutron- induced fission n+238U96Sr+140Xe+3n , given m(96Sr)=95.921750uand m(140Xe)=139.92164 . This result is about 6 MeV greater than the result for spontaneous fission. Why? Confirm that the total number of nucleons and total charge are conserved in this reaction.arrow_forwardA beam of 168MeV nitrogen nuclei is used for cancer therapy. If this beam is directed onto a 0.200kg tumor and gives it a 2.00Sv dose, how many nitrogen nuclei were stopped? (Use an RBE of 20 for heavy ions.)arrow_forward
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