Applied Physics (11th Edition)
11th Edition
ISBN: 9780134159386
Author: Dale Ewen, Neill Schurter, Erik Gundersen
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 11, Problem 3AC
(a)
To determine
Find the communication satellite’s orbiting altitude from the center of the earth and from the surface of the earth.
(b)
To determine
Find the linear speed.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
(a) What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 182 km?
m/s
(b) What is the period of revolution?
min
(a) What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 160 km above Earth's surface?
(b) What is the period of revolution? Take the mass of earth as 5.98×1024 kg and the radius as 6.37×106 m
An earth satellite in a circular orbit 300 mi above the surface of the earth makes a complete revolution in
96 min. Assuming the earth to be a sphere of radius 4000 mi, calculate the angular and linear speed of the satellite.
Chapter 11 Solutions
Applied Physics (11th Edition)
Ch. 11.1 - Compare the gravitational force that (a) the earth...Ch. 11.1 - Find the gravitational force between the sun and...Ch. 11.1 - Find the gravitational force between the sun and...Ch. 11.1 - Find the gravitational force between the sun and...Ch. 11.1 - Find the gravitational force between the sun and...Ch. 11.1 - Explain why the gravitational force between the...Ch. 11.1 - A satellite is orbiting 3.22 105 m above the...Ch. 11.1 - If the satellite in Problem 7 is orbiting at twice...Ch. 11.1 - What is the gravitational force exerted between an...Ch. 11.1 - The Apollo 16 lunar module had a mass of 4240 kg....
Ch. 11.3 - The moon orbits 3.84 108 m from the earth. How...Ch. 11.3 - The moon orbits 3.84 108 m from the earth. How...Ch. 11.3 - Find the orbital velocity for Mercury as it orbits...Ch. 11.3 - Prob. 4PCh. 11.3 - Find the orbital velocity for Saturn as it orbits...Ch. 11.3 - Find the orbital velocity for Uranus as it orbits...Ch. 11.3 - Find the time Mercury takes to orbit the sun.Ch. 11.3 - Find the time the earth takes to orbit the sun.Ch. 11.3 - Find the time Saturn takes to orbit the sun.Ch. 11.3 - Find the time Uranus takes to orbit the sun.Ch. 11 - What type of force is related to the mass of...Ch. 11 - As the distance increases between two objects, the...Ch. 11 - As the mass of two objects increases, the...Ch. 11 - The mass of a satellite is increased. In order to...Ch. 11 - As the distance increases between a satellite and...Ch. 11 - Explain why the gravitational force that exists...Ch. 11 - What would happen to your weight on earth if the...Ch. 11 - What would happen to your weight on earth if the...Ch. 11 - Explain how a satellite in orbit is in a constant...Ch. 11 - According to Isaac Newton, how is the motion of a...Ch. 11 - Most planets actually have slightly elliptical...Ch. 11 - Does the mass of a satellite influence the time it...Ch. 11 - Two 0.300-kg apples are 25.0 cm apart from one...Ch. 11 - Two 65.0-kg people are standing 1.00 m apart. What...Ch. 11 - Find the weight of a 65.0-kg person on the earth...Ch. 11 - Find the weight of a 65.0-kg person on Jupiter (in...Ch. 11 - Find the weight of a 65.0-kg person on Pluto (in...Ch. 11 - If the moon orbited at one half the present...Ch. 11 - If the moon orbited at twice the present distance...Ch. 11 - If the moon orbited at four times the present...Ch. 11 - Using Newtons law of universal gravitation, find...Ch. 11 - If an 85.0-kg astronaut in a space shuttle orbits...Ch. 11 - The gravitational differences between the earth...Ch. 11 - (a) How far from the center of the earth must a...Ch. 11 - Prob. 3ACCh. 11 - Flight engineers for the Apollo Lunar Orbiter...Ch. 11 - (a) What is the gravitational force on a 65.7-kg...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Model the Moons orbit around the Earth as an ellipse with the Earth at one focus. The Moons farthest distance (apogee) from the center of the Earth is rA = 4.05 108 m, and its closest distance (perigee) is rP = 3.63 108 m. a. Calculate the semimajor axis of the Moons orbit. b. How far is the Earth from the center of the Moons elliptical orbit? c. Use a scale such as 1 cm 108 m to sketch the EarthMoon system at apogee and at perigee and the Moons orbit. (The semiminor axis of the Moons orbit is roughly b = 3.84 108 m.)arrow_forwardQuestion 6. A satellite orbits the Earth with a speed of 5.00 km/s. Calculate the orbital period of the satellite.arrow_forwardGiven the mass of the Earth is 5.98 ×1024 kg and a satellite orbits the Earth once every 8 hours. (a) Find the angular speed of the satellite.(b) Find the radius of the orbit of the satellite.arrow_forward
- (a) What linear speed must an Earth satellite have to be in a circular orbit at an altitude of 144 km above Earth's surface? (b) What is the period of revolution? (a) Number Units (b) Number Unitsarrow_forwardThe maximum distance of the earth from the sun is 9.3 x 107 miles. The minimum distance is 9.1 x 107. The sun is at one focus of the elliptical orbit. Find the distance from the sun to the other foci of the ellipse.arrow_forwardThe International Space Station has a mass of 4.19 x 105 kg and orbits at a radius of 6.79 x 10° m from the center of Earth. Find the gravitational force exerted by Earth on be the space station, the space station's gravitational potential energy, and the weight of a 71.7 kg astronaut living inside the station. HINT (a) the gravitational force (in N) exerted by Earth on the space station (Enter the magnitude.) 3.637e7 X N (b) the space station's gravitational potential energy (in J) -2.4696e13 (c) the weight (in N) of an 71.7 kg astronaut living inside the station X N Need Help? Read It Watch Itarrow_forward
- A 639-kg satellite is in a circular orbit about Earth at a height ℎ=1.09e7h=1.09e7 m above the Earth's surface. Find (a) the gravitational force acting on the satellite, (b) the satellite's speed (magnitude of its velocity, notnot its angular velocity), and (c) the period of its revolution. Caution: The radius of the satellite's orbit is not just its height above the Earth's surface. It also includes the radius of the Earth. The mass of the Earth is 5.98×10245.98×1024 kg, and the radius of the Earth is 6.38×1066.38×106 m.arrow_forwardA satellite is in a circular orbit around the Earth at an altitude of 3.80 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 106 m, and the mass of the Earth is 5.98 1024 kg.) ?h(b) Find the speed of the satellite.? km/s(c) Find the acceleration of the satellite.? m/s2 toward the center of the eartharrow_forwardA satellite is in a circular orbit around the Earth at an altitude of 3.82 x 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 x 106 m, and the mass of the Earth is 5.98 x 1024 kg.) h (b) Find the speed of the satellite. km/s (c) Find the acceleration of the satellite. m/s2 toward the center of the eartharrow_forward
- A satellite is in a circular orbit around the Earth at an altitude of 2.06 x 106 m. (a) Find the period of the orbit. (Hint: Modify Kepler's third law so it is suitable for objects orbiting the Earth rather than the Sun. The radius of the Earth is 6.38 x 106 m, and the mass of the Earth is 5.98 x 1024 kg.) h (b) Find the speed of the satellite. km/s (c) Find the acceleration of the satellite. m/s? toward the center of the eartharrow_forwardWhat is the speed of satellite in a circular orbit just above the surface of the earth, if the radius of the earth is 6.4*10^6m ang g=9.8m/s^2arrow_forwardCalculate at what speed the earth would have to rotate in order that objects at the equator would have no weight. Assume the radius of the earth to be 6400 kilometers. What would be the linear speed of a point on the equator? [Hint: When this happens, the object’s weight equals the centripetal force: mg=mv2/r].arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice UniversityClassical Dynamics of Particles and SystemsPhysicsISBN:9780534408961Author:Stephen T. Thornton, Jerry B. MarionPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Classical Dynamics of Particles and Systems
Physics
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning