The heats of vaporization of liquid Chlorine, liquid Hydrogen and liquid Nitrogen are given. These values are expected values has to be explained. Concept introduction: Larger size molecules have lesser interaction between nuclei and electrons. Thus the electrons are free from nuclear force of attraction and easily form dipoles. Thus, larger the size of the molecules, higher is the strength of London dispersion force. London dispersion forces < Dipole-dipole forces < Hydrogen bonding Both London dispersion forces and dipole-dipole forces do not exist permanently. London dispersion force is due to temporary dipole whereas dipole-dipole force is due to temporary dipole and remains longer time than the former one. But hydrogen bonding exists permanently and thus it is the strongest among the intermolecular forces.
The heats of vaporization of liquid Chlorine, liquid Hydrogen and liquid Nitrogen are given. These values are expected values has to be explained. Concept introduction: Larger size molecules have lesser interaction between nuclei and electrons. Thus the electrons are free from nuclear force of attraction and easily form dipoles. Thus, larger the size of the molecules, higher is the strength of London dispersion force. London dispersion forces < Dipole-dipole forces < Hydrogen bonding Both London dispersion forces and dipole-dipole forces do not exist permanently. London dispersion force is due to temporary dipole whereas dipole-dipole force is due to temporary dipole and remains longer time than the former one. But hydrogen bonding exists permanently and thus it is the strongest among the intermolecular forces.
Solution Summary: The author explains that the heats of vaporization of liquid Chlorine, liquid Hydrogen and liquid Nitrogen are expected values.
Author: Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
The heats of vaporization of liquid Chlorine, liquid Hydrogen and liquid Nitrogen are given. These values are expected values has to be explained.
Concept introduction:
Larger size molecules have lesser interaction between nuclei and electrons. Thus the electrons are free from nuclear force of attraction and easily form dipoles. Thus, larger the size of the molecules, higher is the strength of London dispersion force.
Both London dispersion forces and dipole-dipole forces do not exist permanently. London dispersion force is due to temporary dipole whereas dipole-dipole force is due to temporary dipole and remains longer time than the former one. But hydrogen bonding exists permanently and thus it is the strongest among the intermolecular forces.
JON
Determine the bund energy for
UCI (in kJ/mol Hcl) using me
balanced chemical equation and
bund energies listed?
का
(My (9) +36/2(g)-(((3(g) + 3(g)
A Hryn = -330. KJ
bond energy
и-н 432
bond
bond
C-1413
C=C 839 N-H
391
C=O 1010
S-H 363
б-н 467
02 498
N-N
160
N=N
243
418
C-C 341
C-0 358
C=C
C-C 339 N-Br
243
Br-Br
C-Br 274
193
614
(-1 214||(=olin (02) 799
C=N
615
AAL
Determine the bond energy for HCI (
in kJ/mol HCI) using he balanced
cremiculequecticnand bund energles
listed? also c double bond to N is
615, read numbets carefully please!!!!
Determine the bund energy for
UCI (in kJ/mol cl) using me
balanced chemical equation and
bund energies listed?
51
(My (9) +312(g)-73(g) + 3(g)
=-330. KJ
спод
bond energy
Hryn
H-H
bond
band
432
C-1 413
C=C 839 NH
391
C=O 1010
S-1 343
6-H
02 498
N-N
160
467
N=N
C-C
341
CL-
243
418
339 N-Br
243
C-O
358
Br-Br
C=C
C-Br 274
193
614
(-1 216 (=olin (02) 799
C=N
618
Chapter 11 Solutions
General Chemistry - Standalone book (MindTap Course List)
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell