Concept explainers
A solution containing
Interpretation:
The mass of precipitated barium chromate when barium chloride reacts with sodium chromate is to be calculated. The reactant and its mass which is present in excess in the reaction mixture is to be determined.
Concept introduction:
The limiting reagent of a reaction is that reactant of the reaction that controls the amount of product formed. The limiting agents limit the amount of product and by adding some more amount of the limiting reagent in the reaction mixture, the amount of product can be increased.
Answer to Problem 45E
The mass of precipitated barium chromate when barium chloride reacts with sodium chromate is
Explanation of Solution
The reaction between barium chloride and sodium chromate is shown below.
The mass of
The mass of
The molar mass of
The molar mass of
The molar mass of
The number of moles of a substance is given by the expression shown below.
Where,
•
•
Substitute the mass and molar mass of
Therefore, the number of moles of
Substitute the mass and molar mass of
Therefore, the number of moles of
One mole of
Where,
•
•
Substitute the value of
The required amount of
One mole of
Where,
•
•
Substitute the value of
Rearrange the equation (1) for the value of
Substitute the value of molar mass and the number of moles of
Therefore, the mass of precipitated barium chromate when barium chloride reacts with sodium chromate is
The number of moles of sodium chromate that will react with
Substitute the value of molar mass and the number of moles of sodium chromate in the equation (4).
Therefore, the mass of sodium chromate reacted to produce
The excess mass of sodium chromate is given by the expression as shown below.
Where,
•
•
Substitute the value of
Therefore, the mass of sodium chromate present in excess is
The mass of precipitated barium chromate when barium chloride reacts with sodium chromate is
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Chapter 10 Solutions
Introductory Chemistry: An Active Learning Approach
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